UPSC Prelims 2018 CSAT Paper II · Q57 of 58 Basic Numeracy easy

A shopkeeper sells an article at ₹ 40 and gets X% profit. However, when he sells it at ₹ 20, he faces same percentage of loss. What is the original cost of the article?

  1. (a) ₹ 10
  2. (b) ₹ 20
  3. (c) ₹ 30 ✓ UPSC's answer
  4. (d) ₹ 40

Why the answer is (c)

• Let the cost price (CP) be C and the profit/loss percentage be X%.

• Selling at ₹40 gives a profit of X%, so 40 = C(1 + X/100).

• Selling at ₹20 gives a loss of X%, so 20 = C(1 - X/100).

• Adding the two equations: 40 + 20 = C(1 + X/100) + C(1 - X/100).

• This simplifies to 60 = 2C, which means C = 30.

• Therefore, the original cost of the article is ₹30.

Why the other options are wrong

(a) ₹ 10
If the cost were ₹10, selling at ₹40 would yield a 300% profit, while selling at ₹20 would yield a 100% profit, not a loss.
(b) ₹ 20
If the cost were ₹20, selling at ₹20 would result in neither profit nor loss (0%), contradicting the condition of a loss.
(d) ₹ 40
If the cost were ₹40, selling at ₹40 would result in neither profit nor loss (0%), contradicting the condition of a profit.

Asked in the CSAT Paper II of the UPSC Civil Services Preliminary Examination 2018, held on 3 June 2018. Question and answer key: Union Public Service Commission. Explanation: UPSC Answer Check.

Reading the answer is not the same as getting it right under a clock. Practise this question with UPSC's negative marking, and anything you miss goes into an error notebook until you get it right twice.

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