UPSC Prelims 2018 CSAT Paper II · Q60 / 60 Basic Numeracy easy

Twelve equal squares are placed to fit in a rectangle of diagonal 5 cm. There are three rows containing four squares each. No gaps are left between adjacent squares. What is the area of each square?

  1. (a) 5/7 sq cm
  2. (b) 7/5 sq cm
  3. (c) 1 sq cm ✓ UPSC's answer
  4. (d) 25/12 sq cm

Why the answer is (c)

• Let each square have side s cm. Three rows of four squares make a rectangle 4s long and 3s wide.

• Its diagonal is 5 cm, so (4s)² + (3s)² = 5², that is 16s² + 9s² = 25, giving 25s² = 25.

• So s² = 1: each square has an area of 1 sq cm, option (c).

Why the other options are wrong

(a) 5/7 sq cm
5/7 sq cm does not satisfy 25s² = 25.
(b) 7/5 sq cm
7/5 sq cm does not satisfy 25s² = 25.
(d) 25/12 sq cm
25/12 sq cm divides the diagonal squared by 12, but the diagonal squared equals 25s², not 12s².

Asked in the CSAT Paper II of the UPSC Civil Services Preliminary Examination 2018, held on 3 June 2018. Question and answer key: Union Public Service Commission. Explanation: UPSC Answer Check.

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