UPSC Prelims 2019 CSAT Paper II · Q53 of 79 Mental Ability medium

A printer numbers the pages of a book starting with 1 and uses 3089 digits in all. How many pages does the book have ?

  1. (a) 1040
  2. (b) 1048
  3. (c) 1049 ✓ UPSC's answer
  4. (d) 1050

Why the answer is (c)

• Pages 1 to 9 are single-digit numbers, using 9 pages × 1 digit = 9 digits.",

"- Pages 10 to 99 are two-digit numbers, using 90 pages × 2 digits = 180 digits.",

"- Pages 100 to 999 are three-digit numbers, using 900 pages × 3 digits = 2700 digits.",

"- Total digits used up to page 999 is 9 + 180 + 2700 = 2889 digits.",

"- Remaining digits needed are 3089 - 2889 = 200 digits.",

"- Since pages from 1000 onwards are four-digit numbers, the number of additional pages is 200 / 4 = 50 pages.",

"- Total pages = 999 + 50 = 1049, which matches option (c).

Why the other options are wrong

(a) 1040
Option (a) 1040 implies only 41 four-digit pages (164 digits), resulting in a total of 3053 digits, not 3089.
(b) 1048
Option (b) 1048 implies 49 four-digit pages (196 digits), resulting in a total of 3085 digits, not 3089.
(d) 1050
Option (d) 1050 implies 51 four-digit pages (204 digits), resulting in a total of 3093 digits, not 3089.

Asked in the CSAT Paper II of the UPSC Civil Services Preliminary Examination 2019, held on 2 June 2019. Question and answer key: Union Public Service Commission. Explanation: UPSC Answer Check.

Reading the answer is not the same as getting it right under a clock. Practise this question with UPSC's negative marking, and anything you miss goes into an error notebook until you get it right twice.

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