UPSC Prelims 2019 CSAT Paper II · Q71 / 79 Logical Reasoning medium

A joint family consists of seven members A, B, C, D, E, F and G with three females. G is a widow and sister-in-law of D's father F. B and D are siblings and A is daughter of B. C is cousin of B. Who is E ? 1. Wife of F 2. Grandmother of A 3. Aunt of C Select the correct answer using the code given below :

  1. (a) 1 and 2 only
  2. (b) 2 and 3 only
  3. (c) 1 and 3 only
  4. (d) 1, 2 and 3 ✓ UPSC's answer

Why the answer is (d)

• B and D are siblings, so both are children of F; A is B's daughter.

• G is a widow and F's sister-in-law: she is the wife of F's late brother, and C, the cousin of B, is her child.

• The three females are A, G and one more; the mother of B and D must be that third female, and the only member left is E. So E is F's wife.

• As F's wife, E is the grandmother of A (B's daughter) and the aunt of C (the child of F's brother).

• All three descriptions fit E, option (d).

Why the other options are wrong

(a) 1 and 2 only
E is also the aunt of C, the child of F's brother.
(b) 2 and 3 only
E is also F's wife, being the mother of B and D.
(c) 1 and 3 only
E is also the grandmother of A, the daughter of E's child B.

Asked in the CSAT Paper II of the UPSC Civil Services Preliminary Examination 2019, held on 2 June 2019. Question and answer key: Union Public Service Commission. Explanation: UPSC Answer Check.

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