UPSC Prelims 2021 CSAT Paper II · Q5 of 79 Basic Numeracy easy

If 3^2019 is divided by 10, then what is the remainder ?

  1. (a) 1
  2. (b) 3
  3. (c) 7 ✓ UPSC's answer
  4. (d) 9

Why the answer is (c)

• To find the remainder when $3^{2019}$ is divided by 10, we examine the pattern of the last digit of powers of 3.

• The last digits of $3^n$ for $n=1, 2, 3, 4, \dots$ are 3, 9, 7, 1, repeating in a cycle of 4.

• We divide the exponent 2019 by the cycle length 4: $2019 \div 4 = 504$ with a remainder of 3.

• A remainder of 3 indicates the last digit corresponds to the 3rd term in the cycle, which is 7.

• Therefore, the remainder when $3^{2019}$ is divided by 10 is 7, matching option (c).

Why the other options are wrong

(a) 1
Option (a) is incorrect because the last digit of $3^{2019}$ is 7, not 1.
(b) 3
Option (b) is incorrect because the last digit of $3^{2019}$ is 7, not 3.
(d) 9
Option (d) is incorrect because the last digit of $3^{2019}$ is 7, not 9.

Asked in the CSAT Paper II of the UPSC Civil Services Preliminary Examination 2021, held on 10 October 2021. Question and answer key: Union Public Service Commission. Explanation: UPSC Answer Check.

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