UPSC Prelims 2026 CSAT Paper II · Q29 / 72 Basic Numeracy easy

Three variables x, y and z take values 2, 3, 4 or 5 such that their values are always distinct. If M and N denote the largest possible value and the smallest possible value, respectively, for the expression {(x × y) + z}; then M - N is

  1. (a) 11
  2. (b) 12
  3. (c) 13 ✓ UPSC's answer
  4. (d) 14

Why the answer is (c)

• x, y, z are three different values from 2, 3, 4, 5.

• Largest (x × y) + z: multiply the two biggest and add the next: 5 × 4 + 3 = 23 = M.

• Smallest: multiply the two smallest and add the next: 2 × 3 + 4 = 10 = N (the alternatives 2 × 4 + 3 = 11 and 3 × 4 + 2 = 14 are larger).

• M − N = 23 − 10 = 13: (c).

Why the other options are wrong

(a) 11
11 uses a wrong minimum or maximum; M = 23 and N = 10.
(b) 12
12 would need N = 11, but 2 × 3 + 4 = 10 is smaller.
(d) 14
14 would need M = 24, which is not possible with distinct values.

Asked in the CSAT Paper II of the UPSC Civil Services Preliminary Examination 2026, held on 24 May 2026. Question and answer key: Union Public Service Commission. Explanation: UPSC Answer Check.

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