UPSC Prelims 2026 CSAT Paper II · Q29 of 70 Basic Numeracy easy

Three variables x, y and z take values 2, 3, 4 or 5 such that their values are always distinct. If M and N denote the largest possible value and the smallest possible value, respectively, for the expression {(x × y) + z}; then M - N is

  1. (a) 11
  2. (b) 12
  3. (c) 13 ✓ UPSC's answer
  4. (d) 14

Why the answer is (c)

• The variables x, y, and z must be distinct values chosen from the set {2, 3, 4, 5}.

• To find M (the maximum value of (x × y) + z), we need to maximize the product x × y. The largest distinct pair is 5 and 4, giving a product of 20.

• The remaining value for z is 3 (since 2 is unused and we want to maximize the sum, but z is just added; actually, to maximize the total, we should check if using 5 and 4 for x,y and 3 for z is better than other combos. Let's list max products: 5*4=20 (z=3 or 2), 5*3=15 (z=4 or 2), 4*3=12. Max product is 20. If x=5, y=4, z can be 3 or 2. Max sum is 20+3=23. So M = 23.

• To find N (the minimum value of (x × y) + z), we need to minimize the product x × y. The smallest distinct pair is 2 and 3, giving a product of 6.

• The remaining values for z are 4 and 5. To minimize the sum, we choose the smallest available z, which is 4. So N = 6 + 4 = 10.

• The difference M - N is 23 - 10 = 13.

Why the other options are wrong

(a) 11
Option (a) 11 is incorrect because the calculated difference is 13, not 11.
(b) 12
Option (b) 12 is incorrect because the calculated difference is 13, not 12.
(d) 14
Option (d) 14 is incorrect because the calculated difference is 13, not 14.

Asked in the CSAT Paper II of the UPSC Civil Services Preliminary Examination 2026, held on 24 May 2026. Question and answer key: Union Public Service Commission. Explanation: UPSC Answer Check.

Reading the answer is not the same as getting it right under a clock. Practise this question with UPSC's negative marking, and anything you miss goes into an error notebook until you get it right twice.

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