Question : If x and y are integers, then is x even? Statement I : x²y² is even. Statement II : 1 + x² + y² is odd.
- (a) Select this option if the question can be answered using one of these statements alone, but cannot be answered using other statement
- (b) Select this option if the question can be answered using either statement alone
- (c) Select this option if the question can be answered using both the statements together, but cannot be answered using either statement alone ✓ UPSC's answer
- (d) Select this option if the question cannot be answered even using any of the statements
Why the answer is (c)
• Statement I: x²y² even means xy is even, so at least one of x, y is even. x could be odd (x = 1, y = 2) or even. Not sufficient.
• Statement II: 1 + x² + y² odd means x² + y² is even, so x and y have the same parity (both odd or both even). Not sufficient.
• Together: same parity, and they cannot both be odd because then xy would be odd. So both are even, and x is even.
• Both statements are needed together: (c).
Why the other options are wrong
- (a) Select this option if the question can be answered using one of these statements alone…
- Neither statement alone decides the parity of x.
- (b) Select this option if the question can be answered using either statement alone
- Neither statement alone is sufficient.
- (d) Select this option if the question cannot be answered even using any of the statements
- Together the statements do force x to be even.
Asked in the CSAT Paper II of the UPSC Civil Services Preliminary Examination 2026, held on 24 May 2026. Question and answer key: Union Public Service Commission. Explanation: UPSC Answer Check.