UPSC Prelims 2015 CSAT Paper II · Q15 of 74 Basic Numeracy easy

In a test, a candidate attempted only 8 questions and secured 50% marks in each of the questions. If he obtained a total of 40% in the test and all questions in the test carried equal marks, how many questions were there in the test ?

  1. (a) 8
  2. (b) 10 ✓ UPSC's answer
  3. (c) 15
  4. (d) 16

Why the answer is (b)

• Let the total number of questions in the test be $N$.

• Since all questions carry equal marks, let the marks for each question be 1 unit.

• The candidate attempted 8 questions and scored 50% in each, so the total marks obtained = $8 \times 0.5 = 4$ units.

• The candidate obtained a total of 40% in the test, which means the total marks obtained is 40% of the maximum possible marks ($N$).

• Therefore, $4 = 0.40 \times N$.

• Solving for $N$, we get $N = 4 / 0.40 = 10$.

• Thus, there were 10 questions in the test, which corresponds to option (b).

Why the other options are wrong

(a) 8
If there were 8 questions, the candidate would have scored 100% in the test, not 40%.
(c) 15
If there were 15 questions, the candidate's score of 4 units would represent approximately 26.67%, not 40%.
(d) 16
If there were 16 questions, the candidate's score of 4 units would represent 25%, not 40%.

Asked in the CSAT Paper II of the UPSC Civil Services Preliminary Examination 2015, held on 23 August 2015. Question and answer key: Union Public Service Commission. Explanation: UPSC Answer Check.

Reading the answer is not the same as getting it right under a clock. Practise this question with UPSC's negative marking, and anything you miss goes into an error notebook until you get it right twice.

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