UPSC Prelims 2015 CSAT Paper II · Q57 / 74 Mental Ability medium

If ABC × DEED = ABCABC; where A, B, C, D and E are different digits, what are the values of D and E ?

  1. (a) D = 2, E = 0
  2. (b) D = 0, E = 1
  3. (c) D = 1, E = 0 ✓ UPSC's answer
  4. (d) D = 1, E = 2

Why the answer is (c)

• ABCABC is the three-digit number ABC written twice, which equals ABC × 1001 (for example, 123123 = 123 × 1001).

• So ABC × DEED = ABC × 1001, and DEED = 1001.

• Reading the digits, D = 1 and E = 0 — option (c).

• Hence option (c).

Why the other options are wrong

(a) D = 2, E = 0
D = 2, E = 0 gives DEED = 2002, which would double the number, not repeat it.
(b) D = 0, E = 1
D = 0, E = 1 gives 0110, not a four-digit number equal to 1001.
(d) D = 1, E = 2
D = 1, E = 2 gives 1221, not 1001.

Asked in the CSAT Paper II of the UPSC Civil Services Preliminary Examination 2015, held on 23 August 2015. Question and answer key: Union Public Service Commission. Explanation: UPSC Answer Check.

Reading the answer is not the same as getting it right under a clock. Practise this question with UPSC's negative marking, and anything you miss goes into an error notebook until you get it right twice.

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