UPSC Prelims 2018 CSAT Paper II · Q21 of 58 Logical Reasoning easy

If LSJXVC is the code for MUMBAI, the code for DELHI is

  1. (a) CCIDD ✓ UPSC's answer
  2. (b) CDKGH
  3. (c) CCJFG
  4. (d) CCIFE

Why the answer is (a)

• The code LSJXVC corresponds to MUMBAI, indicating a pattern where each letter is shifted by a specific number of positions in the alphabet.

• Comparing M (13) to L (12), U (21) to S (19), M (13) to J (10), B (2) to X (24), A (1) to V (22), and I (9) to C (3), the shifts are -1, -2, -3, -4, -5, and -6 respectively.

• Applying this same sequence of shifts (-1, -2, -3, -4, -5, -6) to the word DELHI (5 letters), we process each letter individually.

• D (4) shifted by -1 becomes C (3).

• E (5) shifted by -2 becomes C (3).

• L (12) shifted by -3 becomes I (9).

• H (8) shifted by -4 becomes D (4).

• I (9) shifted by -5 becomes D (4).

• Combining these results gives the code CCIDD, which matches option (a).

Why the other options are wrong

(b) CDKGH
Option (b) CDKGH does not follow the consistent decreasing shift pattern of -1, -2, -3, -4, -5 applied to DELHI.
(c) CCJFG
Option (c) CCJFG fails to apply the correct shift values, particularly for the third, fourth, and fifth letters of DELHI.
(d) CCIFE
Option (d) CCIFE incorrectly calculates the shifts for the last two letters, resulting in F and E instead of D and D.

Asked in the CSAT Paper II of the UPSC Civil Services Preliminary Examination 2018, held on 3 June 2018. Question and answer key: Union Public Service Commission. Explanation: UPSC Answer Check.

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