UPSC Prelims 2019 CSAT Paper II · Q18 of 79 Basic Numeracy medium

In 2002, Meenu's age was one-third of the age of Meera, whereas in 2010, Meenu's age was half the age of Meera. What is Meenu's year of birth ?

  1. (a) 1992
  2. (b) 1994 ✓ UPSC's answer
  3. (c) 1996
  4. (d) 1998

Why the answer is (b)

• Let Meenu's age in 2002 be $x$ and Meera's age be $y$.

• The first condition gives the equation $x = \frac{1}{3}y$, or $y = 3x$.

• In 2010 (8 years later), Meenu's age is $x + 8$ and Meera's age is $y + 8$.

• The second condition gives the equation $x + 8 = \frac{1}{2}(y + 8)$.

• Substituting $y = 3x$ into the second equation: $x + 8 = \frac{1}{2}(3x + 8)$.

• Solving yields $2x + 16 = 3x + 8$, so $x = 8$.

• Meenu was 8 years old in 2002, so her birth year is $2002 - 8 = 1994$.

Why the other options are wrong

(a) 1992
This option corresponds to a birth year of 1992, implying Meenu was 10 in 2002, which does not satisfy the ratio conditions.
(c) 1996
This option corresponds to a birth year of 1996, implying Meenu was 6 in 2002, which does not satisfy the ratio conditions.
(d) 1998
This option corresponds to a birth year of 1998, implying Meenu was 4 in 2002, which does not satisfy the ratio conditions.

Asked in the CSAT Paper II of the UPSC Civil Services Preliminary Examination 2019, held on 2 June 2019. Question and answer key: Union Public Service Commission. Explanation: UPSC Answer Check.

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