UPSC Prelims 2021 CSAT Paper II · Q30 / 79 Basic Numeracy medium

A student appeared in 6 papers. The maximum marks are the same for each paper. His marks in these papers are in the proportion of 5 : 6 : 7 : 8 : 9 : 10. Overall he scored 60%. In how many number of papers did he score less than 60% of the maximum marks ?

  1. (a) 2
  2. (b) 3 ✓ UPSC's answer
  3. (c) 4
  4. (d) 5

Why the answer is (b)

• Let the marks be 5k, 6k, 7k, 8k, 9k and 10k, a total of 45k, and let the maximum in each paper be M.

• Overall 60% means 45k = 0·6 × 6M = 3·6M, so M = 12·5k and 60% of M = 7·5k.

• Papers with less than 7·5k: 5k, 6k and 7k — three papers.

• Hence option (b).

Why the other options are wrong

(a) 2
Three papers (5k, 6k, 7k) are below 7·5k, not two.
(c) 4
Only three papers are below 7·5k; 8k is above 60% of the maximum.
(d) 5
Only three papers are below 7·5k; 8k and 9k are above 60% of the maximum.

Asked in the CSAT Paper II of the UPSC Civil Services Preliminary Examination 2021, held on 10 October 2021. Question and answer key: Union Public Service Commission. Explanation: UPSC Answer Check.

Reading the answer is not the same as getting it right under a clock. Practise this question with UPSC's negative marking, and anything you miss goes into an error notebook until you get it right twice.

Practise this paper free

Practise Prelims PYQs and the daily 21 free

Score the daily set, see your rank, and let Guru explain what you missed.

Start free

Already have an account? Log in