UPSC Prelims 2022 CSAT Paper II · Q9 of 78 Basic Numeracy medium

Which number amongst 2⁴⁰, 3²¹, 4¹⁸ and 8¹² is the smallest?

  1. (a) 2⁴⁰
  2. (b) 3²¹ ✓ UPSC's answer
  3. (c) 4¹⁸
  4. (d) 8¹²

Why the answer is (b)

• Convert all numbers to the same base, which is 2, to facilitate comparison.

• 2⁴⁰ remains 2⁴⁰.

• 3²¹ cannot be converted to base 2 directly, so compare it with the others by estimating or converting others to base 3 or using logarithms; however, a simpler method is to convert the base-2 numbers to a common exponent or compare magnitudes.

• Let's convert 4¹⁸ and 8¹² to base 2: 4¹⁸ = (2²)¹⁸ = 2³⁶ and 8¹² = (2³)¹² = 2³⁶.

• So, 4¹⁸ and 8¹² are equal to 2³⁶.

• Now compare 2⁴⁰ and 2³⁶. Since 40 > 36, 2⁴⁰ > 2³⁶.

• Now compare 3²¹ with 2³⁶. Note that 3²¹ = (3³)⁷ = 27⁷ and 2³⁶ = (2⁶)⁶ = 64⁶. This is not direct. Let's use logarithms or simple bounds. 3²¹ ≈ 1.04 × 10¹⁰. 2³⁶ ≈ 6.87 × 10¹⁰. 2⁴⁰ ≈ 1.09 × 10¹².

• Therefore, 3²¹ (approx 10¹⁰) is smaller than 2³⁶ (approx 10¹⁰ but larger coefficient) and 2⁴⁰ (approx 10¹²). Specifically, 3²¹ < 2³⁶ < 2⁴⁰.

• Thus, 3²¹ is the smallest number.

Why the other options are wrong

(a) 2⁴⁰
2⁴⁰ is the largest number among the options as its exponent is significantly higher when converted to a common base.
(c) 4¹⁸
4¹⁸ equals 2³⁶, which is larger than 3²¹.
(d) 8¹²
8¹² equals 2³⁶, which is larger than 3²¹.

Asked in the CSAT Paper II of the UPSC Civil Services Preliminary Examination 2022, held on 5 June 2022. Question and answer key: Union Public Service Commission. Explanation: UPSC Answer Check.

Reading the answer is not the same as getting it right under a clock. Practise this question with UPSC's negative marking, and anything you miss goes into an error notebook until you get it right twice.

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