UPSC Prelims 2022 CSAT Paper II · Q9 / 78 Basic Numeracy medium

Which number amongst 2⁴⁰, 3²¹, 4¹⁸ and 8¹² is the smallest?

  1. (a) 2⁴⁰
  2. (b) 3²¹ ✓ UPSC's answer
  3. (c) 4¹⁸
  4. (d) 8¹²

Why the answer is (b)

• Write 4¹⁸ and 8¹² as powers of 2: 4¹⁸ = (2²)¹⁸ = 2³⁶ and 8¹² = (2³)¹² = 2³⁶, so both equal 2³⁶.

• 2⁴⁰ is larger than 2³⁶, so it cannot be the smallest.

• Compare 3²¹ with 2³⁶ by taking a common exponent of 3: 3²¹ = (3⁷)³ = 2187³ and 2³⁶ = (2¹²)³ = 4096³.

• Since 2187 < 4096, 3²¹ < 2³⁶ < 2⁴⁰.

• So 3²¹ is the smallest, option (b).

Why the other options are wrong

(a) 2⁴⁰
2⁴⁰ is the largest of the four numbers, since 4¹⁸ and 8¹² both equal 2³⁶ and 3²¹ is smaller still.
(c) 4¹⁸
4¹⁸ = 2³⁶ = 4096³, which is larger than 3²¹ = 2187³.
(d) 8¹²
8¹² = 2³⁶ = 4096³, which is larger than 3²¹ = 2187³.

Asked in the CSAT Paper II of the UPSC Civil Services Preliminary Examination 2022, held on 5 June 2022. Question and answer key: Union Public Service Commission. Explanation: UPSC Answer Check.

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