For any choices of values of X, Y and Z, the 6-digit number of the form XYZXYZ is divisible by :
- (a) 7 and 11 only
- (b) 11 and 13 only
- (c) 7 and 13 only
- (d) 7, 11 and 13 ✓ UPSC's answer
Why the answer is (d)
• A 6-digit number of the form XYZXYZ can be expressed as $1000 \times (100X + 10Y + Z) + (100X + 10Y + Z)$.
• This simplifies to $(100X + 10Y + Z) \times (1000 + 1)$, which equals $(100X + 10Y + Z) \times 1001$.
• The number 1001 can be factorized into prime factors as $7 \times 11 \times 13$.
• Since the number is a multiple of 1001, it is always divisible by 7, 11, and 13 regardless of the values of X, Y, and Z.
• Therefore, the number is divisible by 7, 11, and 13.
Why the other options are wrong
- (a) 7 and 11 only
- Option (a) is incorrect because it omits 13, which is also a factor of 1001.
- (b) 11 and 13 only
- Option (b) is incorrect because it omits 7, which is also a factor of 1001.
- (c) 7 and 13 only
- Option (c) is incorrect because it omits 11, which is also a factor of 1001.
Asked in the CSAT Paper II of the UPSC Civil Services Preliminary Examination 2023, held on 28 May 2023. Question and answer key: Union Public Service Commission. Explanation: UPSC Answer Check.