UPSC Prelims 2024 CSAT Paper II · Q6 of 79 Basic Numeracy medium

In the expression 5 * 4 * 3 * 2 * 1, * is chosen from +, -, × each at most two times. What is the smallest non-negative value of the expression?

  1. (a) 3
  2. (b) 2
  3. (c) 1
  4. (d) 0 ✓ UPSC's answer

Why the answer is (d)

• The expression is 5 * 4 * 3 * 2 * 1, where the four operators are chosen from {+, -, ×}, with each operator used at most two times.

• To find the smallest non-negative value, we aim for 0, which requires the expression to be a difference of two equal terms or a product involving zero (impossible here as all numbers are non-zero).

• Consider the combination: 5 - 4 - 3 + 2 + 1. Here, '-' is used twice, '+' is used twice, and '×' is used zero times. This satisfies the constraint that each operator is used at most two times.

• Calculating this expression: 5 - 4 = 1; 1 - 3 = -2; -2 + 2 = 0; 0 + 1 = 1. This yields 1, not 0.

• Consider another combination: 5 - 4 - 3 + 2 × 1. Here, '-' is used twice, '+' is used once, '×' is used once. This satisfies the constraints.

• Calculating this expression: 5 - 4 = 1; 1 - 3 = -2; 2 × 1 = 2; -2 + 2 = 0. This yields 0, which is the smallest non-negative value.

Why the other options are wrong

(a) 3
The value 3 is not the smallest possible non-negative value since 0 is achievable.
(b) 2
The value 2 is not the smallest possible non-negative value since 0 is achievable.
(c) 1
The value 1 is not the smallest possible non-negative value since 0 is achievable.

Asked in the CSAT Paper II of the UPSC Civil Services Preliminary Examination 2024, held on 16 June 2024. Question and answer key: Union Public Service Commission. Explanation: UPSC Answer Check.

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