UPSC Prelims 2026 CSAT Paper II · Q38 / 72 Basic Numeracy medium

In an objective type question paper, 5 marks are awarded for a correct answer and 2 marks are deducted for a wrong answer. A student attempted all the questions and got a score of 69. Had he been awarded 4 marks for a correct answer and 1 mark deducted for a wrong answer, he would have scored 84. How many questions were there in the question paper?

  1. (a) 99
  2. (b) 81 ✓ UPSC's answer
  3. (c) 84
  4. (d) 79

Why the answer is (b)

• Let c be correct and w wrong answers (all questions attempted).

• 5c − 2w = 69 and 4c − w = 84, so w = 4c − 84.

• Substituting: 5c − 8c + 168 = 69, so 3c = 99, c = 33 and w = 48.

• Total questions = 33 + 48 = 81: (b).

Why the other options are wrong

(a) 99
99 does not satisfy both scoring equations.
(c) 84
84 is the second score, not the number of questions.
(d) 79
79 does not satisfy both scoring equations.

Asked in the CSAT Paper II of the UPSC Civil Services Preliminary Examination 2026, held on 24 May 2026. Question and answer key: Union Public Service Commission. Explanation: UPSC Answer Check.

Reading the answer is not the same as getting it right under a clock. Practise this question with UPSC's negative marking, and anything you miss goes into an error notebook until you get it right twice.

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