UPSC Prelims 2017 CSAT Paper II · Q58 of 79 Mental Ability easy

The outer surface of a 4 cm × 4 cm × 4 cm cube is painted completely in red. It is sliced parallel to the faces to yield sixty four 1 cm × 1 cm × 1 cm small cubes. How many small cubes do not have painted faces?

  1. (a) 8 ✓ UPSC's answer
  2. (b) 16
  3. (c) 24
  4. (d) 36

Why the answer is (a)

• The original cube has dimensions 4 cm × 4 cm × 4 cm, which is divided into 1 cm × 1 cm × 1 cm cubes, resulting in a 4 × 4 × 4 grid of 64 small cubes.

• Small cubes with no painted faces are located strictly in the interior of the large cube, meaning they are not on any of the six outer surfaces.

• To find the number of interior cubes, subtract 2 from each dimension of the large cube to remove the outer layer of cubes on both sides: (4 - 2) × (4 - 2) × (4 - 2).

• This calculation yields 2 × 2 × 2 = 8 small cubes.

• Therefore, exactly 8 small cubes have no painted faces, which corresponds to option (a).

Why the other options are wrong

(b) 16
Option (b) is incorrect because 16 is the total number of cubes in a single 4x4 face layer, not the count of interior cubes.
(c) 24
Option (c) is incorrect because 24 represents the number of edge cubes (excluding corners) in a 4x4x4 cube, which have two painted faces.
(d) 36
Option (d) is incorrect because 36 is the number of face-center cubes (excluding edges and corners) in a 4x4x4 cube, which have one painted face.

Asked in the CSAT Paper II of the UPSC Civil Services Preliminary Examination 2017, held on 18 June 2017. Question and answer key: Union Public Service Commission. Explanation: UPSC Answer Check.

Reading the answer is not the same as getting it right under a clock. Practise this question with UPSC's negative marking, and anything you miss goes into an error notebook until you get it right twice.

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