Consider the following : A, B, C, D, E, F, G and H are standing in a row facing North. B is not neighbour of G. F is to the immediate right of G and neighbour of E. G is not at the extreme end. A is sixth to the left of E. H is sixth to the right of C. Which one of the following is correct in respect of the above?

• 'A is sixth to the left of E' implies A is at position 1 and E is at position 7 (since 1+6=7).

• 'H is sixth to the right of C' implies C is at position 1 and H is at position 7 (since 1+6=7).

• Combining these, Position 1 must be both A and C, which is impossible. Re-evaluating: 'Sixth to the left' means if E is at pos $x$, A is at $x-6$. If A is at 1, E is at 7. If C is at 1, H is at 7. This creates a conflict unless we interpret the positions differently or check for unique slots. Let's list positions 1-8.

• From 'A is 6th left of E': Possible pairs (A,E) are (1,7) or (2,8). From 'H is 6th right of C': Possible pairs (C,H) are (1,7) or (2,8).

• Case 1: A=1, E=7. Then C and H must be (2,8) or (1,7). If C=1, conflict with A. So C=2, H=8. Positions: 1:A, 2:C, 7:E, 8:H.

• 'F is immediate right of G and neighbour of E'. E is at 7. Neighbours of E are 6 and 8. 8 is H. So F must be at 6. Since F is right of G, G is at 5.

• Current arrangement: 1:A, 2:C, 5:G, 6:F, 7:E, 8:H. Remaining spots: 3, 4. Remaining people: B, D.

• 'B is not neighbour of G'. G is at 5. Neighbours are 4 and 6. 6 is F. So B cannot be at 4. Thus B is at 3, and D is at 4.

• Final Arrangement: 1:A, 2:C, 3:B, 4:D, 5:G, 6:F, 7:E, 8:H.

• Check option (c): G (pos 5) is to the immediate right of D (pos 4). This is correct.