Mechanical Engineering 2023 Paper I 50 marks Calculate

Paper I — Q7

(a) (i) A tube is to be drawn as per the dimensions given in the following Figure 7(a)(i) showing die, plug and tube. Assuming…

(a)
(i)

A tube is to be drawn as per the dimensions given in the following Figure 7(a)(i) showing die, plug and tube. Assuming the metal in work hardened condition with yield stress 1·40 kN/mm², coefficient of friction for die as well as for plug is 0·15, calculate the drawing load and power of the motor required for drawing the tube with the speed of drawing 0·50 m/s. (All dimensions are in 'mm') Figure 7(a)(i) 10 marks

(ii)

Draw and label the surface roughness symbol, if the method of machining was milling, sample length 3·0 mm, direction of lay is perpendicular to the surface, machining allowance is 2 mm with roughness Rₐ as 6·3 μm. Also, calculate the centre line average and root mean square values of surface roughness for the following measurements {figure 7(a)(ii)} taken over a sample length of 20 mm. 10 marks

(b)

The following information is given for the items procured and sold by a shopkeeper : Annual Demand : 8000 units; Ordering Cost : ₹ 180/order; Holding Cost : 10% of the item cost. Following offers are given to the shopkeeper for different lot sizes : Lot Size 1 – 999: Unit Price ₹ 22.00; Lot Size 1000 – 1499: Unit Price ₹ 20.00; Lot Size 1500 – 1999: Unit Price ₹ 19.00; Lot Size 2000 and above: Unit Price ₹ 18.50. Check the feasibility of different offers using Economic Order Quantity and compare the total annual costs of the feasible offers. 20 marks

(c)

What are the key features of Total Quality Management to improve customer satisfaction through design, manufacture and delivery of quality products ? 10 marks

हिंदी में प्रश्न पढ़ें
(a)
(i)

चित्र 7(a)(i) में डाई, प्लग और ट्यूब दिखाया गया है जिसमें से ट्यूब का कर्षण करना है । धातु को कार्य कठोरन अवस्था में, प्रारंभ प्रतिबल 1·40 kN/mm², डाई तथा प्लग का घर्षण गुणांक 0·15 मानते हुए, आवश्यक कर्षण लोड (बल) तथा मोटर की शक्ति ज्ञात कीजिए जबकि ट्यूब का 0·50 m/s की गति से कर्षण किया जा रहा है । (सभी विमाएँ 'मिमी' में हैं) चित्र 7(a)(i) (10 अंक)

(ii)

सतह खुरदरापन प्रतीक को चित्रित एवं नामांकित कीजिए यदि मशीन का तरीका मिलिंग था, नमूने की लंबाई 3·0 mm, बिछने (ले) की दिशा तल के लंबवत्, मशीनिंग छूट 2 mm, खुरदरापन Rₐ = 6·3 μm है। निम्नांकित 20 mm लंबाई के नमूने {चित्र 7(a)(ii)} के सतही खुरदरापन के केंद्रीय रेखा औसत तथा वर्ग माध्य मूल मानों की भी गणना कीजिए । (10 अंक)

(b)

एक दुकानदार द्वारा सामानों की खरीद और बिक्री की निम्नलिखित जानकारी दी गई है : वार्षिक मांग : 8000 इकाई; आदेश लागत : ₹ 180/आदेश; धारण लागत : सामग्री की लागत का 10%। दुकानदार को अलग-अलग लॉट साइज के लिए निम्नलिखित प्रस्ताव दिए गए हैं : लॉट साइज 1 – 999: इकाई लागत ₹ 22.00; लॉट साइज 1000 – 1499: इकाई लागत ₹ 20.00; लॉट साइज 1500 – 1999: इकाई लागत ₹ 19.00; लॉट साइज 2000 और उससे अधिक: इकाई लागत ₹ 18.50। मितव्ययी आदेश मात्रा का उपयोग करते हुए अलग-अलग प्रस्तावों की व्यवहार्यता की जांच कीजिए तथा व्यवहार्य प्रस्तावों की कुल वार्षिक लागतों की तुलना कीजिए । (20 अंक)

(c)

गुणवत्ता वाले उत्पादों के अभिकल्पन, निर्माण और वितरण के माध्यम से ग्राहकों की संतुष्टि में सुधार के लिए कुल गुणवत्ता प्रबंधन की प्रमुख विशेषताएं क्या हैं ? (10 अंक)

Q7 of the 2023 UPSC Mains Mechanical Engineering Paper I, as printed
The question as printed in the 2023 Mechanical Engineering paper

The figure this question refers to, in words

The question paper is a scan and the diagram did not survive as text. This is the figure as read from the original page — every component, value and label — so the question can be worked from the text below.

(a(i)) A cross-sectional diagram labeled 'Figure 7(a)(i)' showing a tube drawing process through a conical die with an internal plug, moving from right to left as indicated by an arrow on the drawn tube. Key dimensions and parameters shown are: initial outer diameter of the tube = phi 20 mm; initial tube wall thickness = 2.0 mm; final outer diameter of the tube = phi 18 mm; final tube wall thickness = 1.5 mm; die semi-cone angle = 15 degrees with respect to the horizontal axis; plug semi-cone angle = 10 degrees with respect to the horizontal axis. A note states '(All dimensions are in 'mm')'.

(a(ii)) A surface roughness profile graph titled 'Figure 7(a)(ii)'. The vertical axis is labeled in 'um' with an upward arrow, representing ordinate heights from a horizontal baseline. The horizontal axis represents distance over a sample length of 20 mm, divided into 8 equally spaced measurement locations labeled 1 through 8. A continuous wavy profile has the following measured ordinates at each position:

  • Position 1 (crest/peak): 70 um
  • Position 2 (trough/valley): 35 um
  • Position 3 (crest/peak): 75 um
  • Position 4 (trough/valley): 20 um
  • Position 5 (crest/peak): 65 um
  • Position 6 (trough/valley): 40 um
  • Position 7 (crest/peak): 80 um
  • Position 8 (trough/valley): 50 um

Model answer

Drafted with AI by UPSC Answer Check against this question's marking rubric, to the expected length. UPSC does not publish answers for Mains — this is one way to score well, not an official key. How we build rubrics and answers.

(a)(i) Drawing load and motor power for tube drawing over a plug

Use the slab-method result for tube drawing with a fixed plug. For die semi-angle α, plug semi-angle β and friction coefficients μ_d and μ_p: σ_d = Y[(1 + B)/B][1 − (A_f/A₀)^B], where B = (μ_d + μ_p)/(tanα − tanβ).

From the figure the initial tube is 20 mm outside diameter with 2.0 mm wall, and the drawn tube is 18 mm outside diameter with 1.5 mm wall (15 mm inside diameter). A₀ = (π/4)(20² − 16²) = 36π mm². A_f = (π/4)(18² − 15²) = 24.75π mm² = 77.75 mm². A_f/A₀ = 11/16 = 0.6875.

With Y = 1.40 kN/mm², μ_d = μ_p = 0.15, α = 15°, β = 10°: B = 0.30/(tan15° − tan10°) = 0.30/(0.2679 − 0.1763) = 3.274. (A_f/A₀)^B = 0.6875^3.274 = 0.2932. σ_d = 1.40 × (4.274/3.274) × (1 − 0.2932) = 1.292 kN/mm².

Drawing load F = σ_d A_f = 1.292 × 77.75 = 100.4 kN. Power = F × v = 100.4 × 0.50 = 50.2 kW.

This is for steady drawing with Coulomb friction, negligible redundant work and no back tension.

(a)(ii) Surface roughness symbol, centre line average and RMS value

Symbol: the basic roughness mark (a check-shaped tick on the surface line) carries the following entries. Ra 6.3 μm is placed above the tick, the production method "milling" beside it, the sampling length 3.0 mm below the horizontal bar, the lay symbol ⊥ (lay perpendicular to the surface) at the right end, and the machining allowance 2 mm at the left.

Profile ordinates at the eight stations: 70, 35, 75, 20, 65, 40, 80, 50 μm. Mean level: h̄ = 435/8 = 54.375 μm.

Deviations from the mean: 15.625, −19.375, 20.625, −34.375, 10.625, −14.375, 25.625, −4.375. Centre line average: CLA = Σ|h − h̄|/n = 145/8 = 18.13 μm. Root mean square: RMS = √[Σ(h − h̄)²/n] = √(3221.9/8) = √402.7 = 20.07 μm.

The RMS value is slightly larger than CLA, as it always is for a non-uniform profile.

Diagram: Surface texture symbol

(b) Economic order quantity with quantity-discount offers

D = 8000 units/year, C_o = ₹180/order, holding cost C_h = 10% of unit price. Q* = √(2DC_o/C_h), and an offer is feasible only if Q* lies inside its lot range; otherwise cost is evaluated at the nearest allowed lot size.

Price ₹22.00 (1–999): C_h = 2.20, Q* = 1144 lies outside the range. At Q = 999, TC = 176 000 + 1 441 + 1 099 = ₹1,78,540. Price ₹20.00 (1000–1499): C_h = 2.00, Q* = 1200 is feasible. TC = 160 000 + 1 200 + 1 200 = ₹1,62,400. Price ₹19.00 (1500–1999): C_h = 1.90, Q* = 1231 is below the range. At Q = 1500, TC = 152 000 + 960 + 1 425 = ₹1,54,385. Price ₹18.50 (2000 and above): C_h = 1.85, Q* = 1248 is below the range. At Q = 2000, TC = 148 000 + 720 + 1 850 = ₹1,50,570.

The total annual cost falls as the lot size rises, so the cheapest offer is the last one. Order 2000 units at ₹18.50, with a total annual cost of ₹1,50,570.

(c) Key features of Total Quality Management

TQM is an organisation-wide approach in which quality is built into design, manufacture and delivery to raise customer satisfaction. Its key features are:

  1. Customer focus, treating internal customers (the next process) as well as external ones.
  2. Leadership and commitment of top management, expressed through a quality policy.
  3. Quality by design: design reviews, FMEA, robust design and reliability engineering.
  4. Quality in manufacture: statistical process control, poka-yoke and a zero-defect aim, with prevention preferred to inspection.
  5. Employee involvement: training, teamwork and empowerment.
  6. Continuous improvement through Kaizen, Six Sigma and benchmarking.
  7. Supplier partnership and fact-based decisions using quality data and cost of quality.
  8. Delivery and service: on-time delivery, packaging, after-sales service and feedback, closing the loop to design.

Together these make customer satisfaction the outcome of a managed system rather than of final inspection.

How this answer will be evaluated

What earns full marks: All parts show complete working with correct formulas, units, and clear interpretation.

Evaluation rubric

Each sub-part is marked on its own, against the marks and word limit printed on the paper.

  1. (a)(i) Calculate the drawing load and motor power for the tube drawn over a plug. 10 marks

    calculate— given → formula → substitution → result with units → interpretation

    Must cover

    • A0 = 36 pi and Af = 24.75 pi mm2
    • B = (mu_d+mu_p)/(tan alpha - tan beta) = 3.274
    • sigma_d = 1.292 kN/mm2
    • F = 100.4 kN and power 50.2 kW

    Loses marks

    • Using the wrong wall thickness from the figure.

    Earns more

    • Marks for areas, B, drawing stress, load and power.

    Extra mark

    • Stating assumptions of the slab method.
  2. (a)(ii) Draw the roughness symbol and compute CLA and RMS values of the profile. 10 marks

    calculate— given → formula → substitution → result with units → interpretation

    Must cover

    • Ra 6.3, milling, 3.0 mm, perpendicular lay, 2 mm allowance
    • Mean 54.375 um
    • CLA 18.13 um
    • RMS 20.07 um

    Loses marks

    • Placing all entries without positions.

    Earns more

    • Marks for symbol entries, mean level, CLA and RMS.

    Extra mark

    • Remark that RMS exceeds CLA.
  3. (b) Check offer feasibility by EOQ and compare total annual costs. 20 marks

    calculate— given → formula → substitution → result with units → interpretation

    Must cover

    • EOQ formula with holding cost 10 percent of price
    • Feasibility of each lot range
    • Total costs 178540, 162400, 154385, 150570
    • Order 2000 at Rs 18.50

    Loses marks

    • Using EOQ outside its price range.

    Earns more

    • Marks for EOQ, feasibility, costs and the choice.

    Extra mark

    • Table-like comparison and reasoning for the trend.
  4. (c) Discuss key features of Total Quality Management for customer satisfaction. 10 marks

    explain— definition/context → points in order → small example → short close

    Must cover

    • Customer focus and leadership
    • Quality by design and in manufacture
    • Employee involvement and continuous improvement
    • Supplier partnership and delivery/service

    Loses marks

    • Plain list without link to customer satisfaction.

    Earns more

    • Marks for features linked to design, manufacture and delivery.

    Extra mark

    • Tools such as FMEA, SPC, Six Sigma named.
What "Calculate" is asking you to do

Apply the standard formula or schedule to data the question has already supplied — a table of readings, cost records, a balance sheet — and produce the number. The method is rarely in doubt; the marks sit in the named intermediate quantities, each of which has to appear as a labelled line.

Structure that answers it

Data as given → formula or standard treatment, named → substitution → each intermediate, labelled → result with units

Where marks are lost

Omitting an intermediate the marking scheme pays for separately, or rounding at an intermediate line so the final figure drifts. In commerce and accountancy, any figure in a statement that no numbered working note supports is treated as unearned.

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