Botany 2023 Paper II 50 marks Explain

Paper II — Q7

(a) How can the reaction equilibria and reaction rates be explained by using free energy diagram in a simple enzymatic reaction ?…

(a)

How can the reaction equilibria and reaction rates be explained by using free energy diagram in a simple enzymatic reaction ? 20 marks

(b)

Explain the following : 5+5=10

(i)

Nitrate and nitrite reduction in the leaves of higher plants. 5 marks

(ii)

Protection of enzyme nitrogenase against oxygen and hydrogen damage. 5 marks

(c)

Comment on the following : 10+10=20

(i)

Biosphere reserves 10

(ii)

Red Data Book 10

हिंदी में प्रश्न पढ़ें
(a)

एक साधारण एन्जाइमी अभिक्रिया में मुक्त ऊर्जा आरेख का उपयोग करके अभिक्रिया संतुलन और अभिक्रिया दरों को कैसे समझाया जा सकता है ? 20 अंक

(b)

निम्नलिखित को समझाइए : 5+5=10

(i)

उच्च पादपों की पत्तियों में नाइट्रेट और नाइट्राइट का अपचयन । 5

(ii)

ऑक्सीजन और हाइड्रोजन क्षति के विरुद्ध एन्जाइम नाइट्रोजिनेज का संरक्षण । 5

(c)

निम्नलिखित पर टिप्पणी कीजिए : 10+10=20

(i)

जीवमंडल निचय 10

(ii)

संकटग्रस्त जीव पुस्तिका 10

Q7 of the 2023 UPSC Mains Botany Paper II, as printed
The question as printed in the 2023 Botany paper

Model answer

Drafted with AI by UPSC Answer Check against this question's marking rubric, to the expected length. UPSC does not publish answers for Mains — this is one way to score well, not an official key. How we build rubrics and answers.

(a) Reaction equilibrium and rate from a free-energy diagram

A free-energy diagram plots free energy (G) against the reaction coordinate from substrate (S) to product (P).

Equilibrium: The difference in free energy between S and P, ΔG°′, fixes the equilibrium constant: ΔG°′ = −RT ln K_eq. An enzyme does not change the free energy of S or P, so ΔG°′ and K_eq are the same with or without enzyme. A reaction with negative ΔG°′ is favoured in the forward direction, and the enzyme only helps equilibrium to be reached faster.

Rate: The rate depends on the activation free energy ΔG‡, the height of the barrier between the substrate and the transition state (S‡). The rate constant is k = (k_BT/h)e^(−ΔG‡/RT), so even a small fall in ΔG‡ raises the rate greatly (about 5.7 kJ/mol gives a tenfold rise at 25 °C).

Enzyme pathway: The enzyme binds the substrate to form the enzyme–substrate complex (ES), passes through the enzyme-bound transition state (ES‡) and gives the enzyme–product complex (EP) and then P. Binding the transition state more tightly than the substrate lowers ΔG‡ by means of proximity and orientation, strain, acid–base and covalent catalysis, and the environment of the active site. The diagram shows a lower peak with several smaller barriers and dips for ES and EP. The rate-limiting step is the highest barrier.

The same lowering applies to the reverse reaction, so the forward and reverse rates rise by equal factors and equilibrium is unchanged.

Diagram: Free-energy diagram of an uncatalysed and an enzyme-catalysed reaction

(b)(i) Nitrate and nitrite reduction in leaves

Nitrate is reduced in two steps.

  1. Nitrate reductase (cytosol): NO₃⁻ + NADH + H⁺ → NO₂⁻ + NAD⁺ + H₂O. It is a molybdenum-containing flavoprotein (with FAD and heme).
  2. Nitrite reductase (chloroplast): NO₂⁻ + 6 reduced ferredoxin + 8 H⁺ → NH₄⁺ + 6 oxidised ferredoxin + 2 H₂O. It contains siroheme and an Fe–S cluster; in roots the reductant comes from NADPH.

Nitrite is toxic, so it is quickly moved to the chloroplast; the ammonium is then incorporated into amino acids by glutamine synthetase and GOGAT.

(b)(ii) Protection of nitrogenase from oxygen and hydrogen

Nitrogenase (Fe protein and MoFe protein) is irreversibly inactivated by O₂ and inhibited by its by-product H₂.

Against oxygen:

  • Leghemoglobin in legume nodules binds O₂ with high affinity, keeping free O₂ low but supplying bacteroids for respiration.
  • Respiratory protection: Azotobacter has very high respiration, which consumes the oxygen.
  • Conformational protection: in Azotobacter, the Shethna (FeSII) protein reversibly binds nitrogenase.
  • Heterocysts in cyanobacteria have thick walls and lack PS II, so they do not produce O₂.
  • Nodule cortex acts as a diffusion barrier to O₂.

Against hydrogen: an uptake hydrogenase oxidises H₂ back to protons and electrons, which also gives back energy and consumes oxygen, protecting the enzyme.

(c)(i) Biosphere reserves

Biosphere reserves are areas of terrestrial and coastal ecosystems recognised under UNESCO's Man and the Biosphere (MAB) programme, designated by the government and then nominated internationally. They conserve biodiversity and genetic resources, promote sustainable development and support research, monitoring and education.

Zonation: a core zone, strictly protected; a buffer zone around it, where research, education and compatible uses are allowed; and an outer transition zone, with human settlements and sustainable agriculture and resource use. Nilgiri (1986) was the first in India, followed by Nanda Devi, Sundarbans, Gulf of Mannar and others; India has 18 designated biosphere reserves, many in UNESCO's world network. Unlike national parks, they include people, but they depend on community participation and effective zone management.

(c)(ii) Red Data Book

The Red Data Book is a record of threatened species, started by the IUCN (1966). It is based on the IUCN Red List categories: Extinct, Extinct in the Wild, Critically Endangered, Endangered, Vulnerable, Near Threatened, Least Concern, Data Deficient and Not Evaluated. They are assigned using criteria of population size, rate of decline, range and extinction probability.

It identifies conservation priorities, guides action plans, law and funding, and is updated regularly. In India, the Botanical Survey of India and the Zoological Survey of India compile Red Data Books of threatened plants and animals. Examples: Nepenthes khasiana, Endangered; Santalum album, Vulnerable. The limitation is that it is a list and not a legal instrument; protection needs law, such as the Wildlife (Protection) Act, 1972 and the Biological Diversity Act, 2002.

How this answer will be evaluated

Framework: Botany Paper 2: Define > Structure/Process > Labelled Diagram > Significance

What earns full marks: All parts fully addressed with labelled diagrams, exact terminology, and specific examples; no factual errors.

Evaluation rubric

Each sub-part is marked on its own, against the marks and word limit printed on the paper.

  1. (a) (a) How can reaction equilibria and rates be explained using a free-energy diagram in a simple enzymatic reaction? (20 marks) 20 marks

    explain— definition/context → points in order → small example → short close

    Must cover

    • Free energy vs reaction coordinate: S, transition state, P
    • Equilibrium fixed by delta G0' and K_eq; enzyme does not alter it
    • Rate fixed by activation energy; enzyme lowers it
    • ES, ES-double-dagger, EP intermediates and forward/reverse equal effect

    Loses marks

    • Saying enzyme shifts equilibrium.
    • Saying enzyme changes delta G.

    Earns more

    • Rate constant relationship.
    • Catalytic mechanisms.

    Extra mark

    • Rate-limiting step
    • Transition-state binding
  2. (b)(i) (b)(i) Explain nitrate and nitrite reduction in the leaves of higher plants (5 marks). 5 marks

    explain— definition/context → points in order → small example → short close

    Must cover

    • Nitrate reductase: cytosol, NADH, Mo flavoprotein
    • Nitrite reductase: chloroplast, ferredoxin, siroheme
    • Equations for both steps
    • Ammonium assimilation by GS-GOGAT

    Loses marks

    • Swapping enzyme locations.
    • No equations.

    Earns more

    • Toxicity of nitrite.

    Extra mark

    • Root NADPH variant
  3. (b)(ii) (b)(ii) Explain the protection of nitrogenase from oxygen and hydrogen damage (5 marks). 5 marks

    explain— definition/context → points in order → small example → short close

    Must cover

    • Leghemoglobin
    • Respiratory and conformational (Shethna) protection
    • Heterocysts lacking PSII
    • Uptake hydrogenase for H2

    Loses marks

    • Saying heterocysts perform oxygenic photosynthesis.
    • H2 protection omitted.

    Earns more

    • Nodule diffusion barrier.

    Extra mark

    • Energy recovery by hydrogenase
  4. (c)(i) (c)(i) Comment on biosphere reserves (10 marks). 10 marks

    comment— context → arguments both sides → judgment → close

    Must cover

    • UNESCO MAB basis
    • Core, buffer, transition zones
    • Indian examples: Nilgiri, Nanda Devi, Sundarbans
    • Difference from national parks; role of people

    Loses marks

    • Stating wrong zone uses.
    • No Indian example.

    Earns more

    • Number of Indian reserves.
    • Research role.

    Extra mark

    • Management challenges
  5. (c)(ii) (c)(ii) Comment on the Red Data Book (10 marks). 10 marks

    comment— context → arguments both sides → judgment → close

    Must cover

    • IUCN origin and purpose
    • Categories: EX, EW, CR, EN, VU and others
    • Criteria for assignment
    • Indian examples and limitations as a non-legal list

    Loses marks

    • Treating it as legal protection.
    • Wrong categories.

    Earns more

    • BSI and ZSI Red Data Books.
    • Link to laws.

    Extra mark

    • Nepenthes khasiana
    • Santalum album
What "Explain" is asking you to do

Make the working of something clear — what sets it off, what follows from what, and what it produces. Explain is the Commission's mechanism word: it dominates the technical papers and the “explain why” stems, where the marks sit in the causal chain and not in the label.

Structure that answers it

State what it is → the initiating condition → the chain of cause, step by step → an instance where it plays out → what the chain produces

Where marks are lost

Describing what something looks like instead of why it works that way. Naming the stages without linking them reads as description too.

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