Chemistry 2023 Paper II 50 marks Solve

Q6

(a)(i) The frequencies of vibration of the following molecules in their v = 0 states are HCl : 2885 cm⁻¹; D₂ : 2990 cm⁻¹; DCl : 1990 cm⁻¹ and HD : 3627 cm⁻¹. Calculate the energy change of the following reaction : HCl + D₂ → DCl + HD. Determine whether energy is liberated or absorbed. [Given : h = 6·626 × 10⁻³⁴ Js, c = 2·998 × 10⁸ ms⁻¹, Nₐ = 6·022 × 10²³ mol⁻¹] 10 marks (a)(ii) The IR spectra of butyric acid and ethyl butyrate show sharp strong singlet absorption at 1725 cm⁻¹ and 1740 cm⁻¹, respectively. By contrast, the IR spectrum of butyric anhydride shows a broad, sharp doublet at 1750 cm⁻¹ and 1825 cm⁻¹. Why are these so different ? 5 marks (b)(i) Write the structure of product(s) in the above reactions : 10 marks (b)(ii) What is meant by 'Tacticity' of a polymer ? Distinguish among isotactic, syndiotactic and atactic polymers. 5 marks (c)(i) An organic compound having molecular formula C₁₆H₂₅NO gave following IR and ¹H NMR data : IR(cm⁻¹) = 1690; ¹H NMR(CDCl₃, 400 MHz) : δ 1·11(t, J = 7Hz, 6H), 1·29(d, J = 7Hz 6H), 2·40 (q, J = 7Hz, 4H), 2·55(t, J = 7Hz, 2H), 2·65(t, J = 7 Hz, 2H), 3·12(septet, 1H), 7·21(d, J = 8Hz, 2H), 7·81(d, J = 8Hz, 2H). Determine the structure of the compound. 10 marks (c)(ii) Assign and arrange the lettered protons in the increasing order of their chemical shift value in ¹H NMR spectrum. 10 marks

हिंदी में प्रश्न पढ़ें

(a)(i) ब्यूटिरिक एसिड व एथिल ब्यूटिरेट अवरक्त (IR) स्पेक्ट्रम में क्रमशः: 1725 cm⁻¹ व 1740 cm⁻¹ पर एक प्रबल अवशोषण दिखाते हैं। इसके विपरीत, ब्यूटिरिक एनहाइड्राइड अवरक्त (IR) स्पेक्ट्रम में 1750 cm⁻¹ व 1825 cm⁻¹ पर द्विक अवशोषण दिखाता है। ये इतने अलग क्यों हैं ? 5 (b)(i) निम्नलिखित अभिक्रियाओं में उत्पाद(ओं) की संरचना लिखिए : 10 (b)(ii) बहुलक की टैक्टिसिटी (व्यवस्था) से क्या अभिप्राय है ? समव्यवस्थ (आइसोटैक्टिक), एकान्तर व्यवस्थ (सिन्डियोटैक्टिक) तथा अव्यवस्थ (एटैक्टिक) बहुलकों के बीच अंतर बताएं। 5 (c)(i) एक कार्बनिक यौगिक जिसका आण्विक सूत्र C₁₆H₂₅NO है वह निम्नलिखित IR व ¹H NMR आँकड़ा देता है : IR(cm⁻¹) = 1690; ¹H NMR(CDCl₃, 400 MHz) : δ 1·11(t, J = 7Hz, 6H), 1·29(d, J = 7Hz 6H), 2·40 (q, J = 7Hz, 4H), 2·55(t, J = 7Hz, 2H), 2·65(t, J = 7 Hz, 2H), 3·12(septet, 1H), 7·21(d, J = 8Hz, 2H), 7·81(d, J = 8Hz, 2H). यौगिक की संरचना निर्धारित कीजिए। 10 (c)(ii) अक्षरों से चिह्नित प्रोटोनों को उनके ¹H NMR स्पेक्ट्रम में रासायनिक सृति मानों के अनुसार आरोही क्रम में लिखें। 10

Directive word: Solve

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How this answer will be evaluated

Approach

Solve this multi-part spectroscopy and polymer chemistry problem by allocating approximately 35% time to part (a) covering vibrational energy calculations and IR interpretation, 25% to part (b) on reaction products and tacticity definitions, and 40% to part (c) involving complete structure elucidation from spectral data. Begin each sub-part with clear identification of the chemical principle involved, show all calculations with proper units, draw unambiguous structures with stereochemistry where relevant, and conclude with explicit answers to each directive.

Key points expected

  • For (a)(i): Apply zero-point energy formula E = ½hcν̃ for each molecule, calculate ΔE = [E(DCl) + E(HD)] - [E(HCl) + E(D₂)], convert to kJ/mol using Avogadro's number, and correctly identify energy liberation (exothermic)
  • For (a)(ii): Explain Fermi resonance in anhydrides (coupling of C=O stretch with overtone of C-O stretch), symmetric/asymmetric stretching modes, and contrast with isolated C=O in esters/acids
  • For (b)(i): Draw correct product structures for unspecified reactions (typically Grignard, reduction, or substitution sequences common in UPSC papers) with proper stereochemistry
  • For (b)(ii): Define tacticity as stereochemical arrangement of substituents; distinguish isotactic (same side), syndiotactic (alternating), and atactic (random) with 3D representations
  • For (c)(i): Deduce structure as N,N-diisopropyl-4-ethylbutyrylbenzamide or similar amide from IR (1690 cm⁻¹, amide C=O), molecular formula, and complete NMR analysis including coupling patterns and integration
  • For (c)(ii): Assign all lettered protons and arrange in order: methyl/methylene (δ 0.9-2.8) < methine (δ 3.1) < aromatic (δ 7.2-7.8), citing shielding/deshielding effects

Evaluation rubric

DimensionWeightMax marksExcellentAveragePoor
Concept correctness20%10Demonstrates flawless understanding: for (a)(i) recognizes zero-point energy and isotope mass effects on vibrational frequencies; for (a)(ii) correctly identifies Fermi resonance mechanism; for (b)(ii) precisely defines tacticity with correct stereochemical terminology; for (c)(i) unambiguously identifies compound class and substitution pattern from spectral dataShows basic familiarity with concepts but makes minor errors: confuses zero-point energy with thermal energy, vaguely mentions 'resonance' without specifying Fermi, or partially correct tacticity definitions with stereochemical confusionFundamental misconceptions: treats vibrational frequencies as thermal energies, completely misidentifies IR doublet origin, fails to define tacticity, or misinterprets NMR multiplicities leading to wrong functional group identification
Mechanism / equation20%10Presents complete, balanced formalism: writes E₀ = ½hcν̃ explicitly for all four molecules; shows clear ΔE calculation with proper sign convention; for (b)(i) depicts reaction mechanisms with electron-pushing arrows; explains Fermi resonance coupling with energy level diagrams; uses correct (R)/(S) or meso descriptors for tacticityWrites main equations but with omissions: skips intermediate steps in energy calculation, shows products without mechanisms, or describes tacticity without stereochemical drawingsMissing or incorrect equations: no zero-point energy formula, no reaction products drawn, or completely wrong mechanistic rationale for spectral observations
Numerical accuracy20%10Computes with precision: converts all ν̃ to energies using consistent units (J/molecule), applies Avogadro's number correctly for molar energy, obtains ΔE ≈ -2.8 to -3.0 kJ/mol (energy liberated), and reports final answer with appropriate significant figures (3-4 sig figs)Correct method but calculation errors: unit conversion mistakes (e.g., forgets ×10² for cm⁻¹ to m⁻¹), arithmetic errors in final subtraction, or wrong sign for energy changeCritical numerical failures: order-of-magnitude errors, completely wrong final value, or no calculation shown with only guessed answer
Diagram / structure20%10Produces clear, chemically accurate drawings: for (b)(i) shows all product structures with correct connectivity and stereochemistry; for (b)(ii) draws zig-zag polymer chains with wedge/dash bonds illustrating tacticity; for (c)(i) presents complete molecular structure with all substituents correctly placed; for (c)(ii) labels each proton environment on the drawn structureDraws structures with minor flaws: correct connectivity but poor stereochemical representation, or correct tacticity concepts but unclear 3D depictionInadequate or wrong diagrams: missing structures, incorrect connectivity in products, no visualization of tacticity, or structure for (c)(i) inconsistent with spectral data
Application context20%10Synthesizes across sub-parts: connects isotope effects to kinetic isotope applications in mechanistic studies; relates IR carbonyl differences to functional group identification in pharmaceutical analysis (e.g., Indian drug quality control); links tacticity to polymer properties (PP, PVC industrial relevance); applies NMR problem-solving to natural product/pesticide structure determination relevant to Indian agrochemical industryMentions applications superficially: notes 'used in industry' without specifics, or provides generic context without Indian/scientific relevanceNo contextual awareness: treats problem as purely academic exercise with no mention of real-world spectroscopic analysis, polymer engineering, or structure determination applications

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