Paper II — Q3
(a) (i) Predict the reaction mechanism and the major product formed when methyl cyanide is heated with dilute hydrochloric acid…
Predict the reaction mechanism and the major product formed when methyl cyanide is heated with dilute hydrochloric acid. 10 marks
Addition of bromine to cis-2-butene gives racemic-2,3-dibromobutane while trans-2-butene yields meso-2,3-dibromobutane. Justify. 5 marks
Explain the formation of enone in the following reaction : methyl (E)-3-[2-(1-methoxyethenyl)cyclohex-1-en-1-yl]prop-2-enoate, i.e. CH₂=C(OMe)–C=C(ring)–CH=CH–CO₂Me with the central C=C in a cyclohexene ring →(1) 215 °C; 2) HCl (aq), EtOH) methyl 4-oxo-1,2,3,4,5,6,7,8-octahydronaphthalene-2-carboxylate (bicyclic enone with the ring-fusion C=C conjugated to C=O and CO₂Me on the new ring). 5 marks
Classify the following sigmatropic rearrangement and comment if it is symmetry-allowed or symmetry-forbidden : endo-6-vinylbicyclo[3.1.0]hex-2-ene →(33 °C) bicyclo[3.2.1]octa-2,6-diene. 5 marks
Write the structure of the major product formed in the following reaction : 2-methoxy-5-methyl-1,4-benzoquinone + buta-1,3-diene →(100 °C) ? 5 marks
Consider the following conversion : R–C(=O)–Cl →(1) NaN₃/inert solvent; 2) Heat) R–N=C=O. Show that the above conversion involves the formation of nitrene intermediate. Draw the orbital pictures of singlet and triplet states of nitrene. 10 marks
Account for the following : (1) Indole undergoes electrophilic substitution to give 3-substituted product, but not 2-substituted product. (2) Chlorobenzene does not undergo nucleophilic substitution reaction readily. 10 marks
हिंदी में प्रश्न पढ़ें
(क) (i) मेथिल साइनाइड को तनु हाइड्रोक्लोरिक अम्ल के साथ गर्म करने पर बनने वाले मुख्य उत्पाद तथा क्रियाविधि का अनुमान लगाइए। (10 अंक)
ब्रोमीन, सिस-2-ब्यूटीन के साथ योगज करके रेसिमिक-2,3-डाइब्रोमोब्यूटेन देता है, जबकि ट्रांस-2-ब्यूटीन के साथ मीसो-2,3-डाइब्रोमोब्यूटेन देता है। औचित्य सिद्ध कीजिए। (5 अंक)
(ख) (i) निम्नलिखित अभिक्रिया में ईनोन के बनने की व्याख्या कीजिए : मेथिल (E)-3-[2-(1-मेथॉक्सीएथेनिल)साइक्लोहेक्स-1-ईन-1-इल]प्रोप-2-ईनोएट, अर्थात CH₂=C(OMe)–C=C(वलय)–CH=CH–CO₂Me जिसमें मध्य C=C साइक्लोहेक्सीन वलय में है →(1) 215 °C; 2) HCl (aq), EtOH) मेथिल 4-ऑक्सो-1,2,3,4,5,6,7,8-ऑक्टाहाइड्रोनैफ़्थैलीन-2-कार्बोक्सिलेट (द्विचक्रीय ईनोन जिसमें वलय-संधि C=C, C=O से संयुग्मित है तथा नए वलय पर CO₂Me है)। (5 अंक)
निम्नलिखित सिग्मानुवर्ती पुनर्विन्यास को वर्गीकृत कीजिए और यह टिप्पणी कीजिए कि यह सममिति-अनुमत है या सममिति-वर्जित : एंडो-6-वाइनिलबाइसाइक्लो[3.1.0]हेक्स-2-ईन →(33 °C) बाइसाइक्लो[3.2.1]ऑक्टा-2,6-डाईईन। (5 अंक)
निम्नलिखित अभिक्रिया में बनने वाले मुख्य उत्पाद की संरचना लिखिए : 2-मेथॉक्सी-5-मेथिल-1,4-बेन्ज़ोक्विनोन + ब्यूटा-1,3-डाईईन →(100 °C) ? (5 अंक)
(ग) (i) निम्नलिखित रूपांतरण पर विचार कीजिए : R–C(=O)–Cl →(1) NaN₃/निष्क्रिय विलायक; 2) ताप) R–N=C=O। दिखाइए कि उपर्युक्त रूपांतरण में मध्यवर्ती नाइट्रीन बनता है। नाइट्रीन की एकक व त्रिक अवस्थाओं के कक्षीय चित्र दर्शाइए। (10 अंक)
निम्नलिखित के कारण दीजिए : (1) इंडोल, इलेक्ट्रॉनरागी प्रतिस्थापन द्वारा 3-प्रतिस्थापित उत्पाद देता है, लेकिन 2-प्रतिस्थापित उत्पाद नहीं। (2) क्लोरोबेंज़ीन की नाभिकरागी प्रतिस्थापन अभिक्रिया आसानी से नहीं होती है। (10 अंक)
The figure this question refers to, in words
The question paper is a scan and the diagram did not survive as text. This is the figure as read from the original page — every component, value and label — so the question can be worked from the text below.
(b) Reaction scheme: A six-membered ring containing two ketone groups (a quinone) with a methyl group (Me) at the top-left position and a methoxy group (OMe) at the bottom-right position reacts with ethene (shown as a double bond) in the presence of heat (100 °C) to form a product.
(b(i)) A chemical reaction scheme. The reactant is a bicyclic alkene, specifically a decalin derivative with a double bond in the right-hand ring. This double bond is substituted with a methoxy group (OMe) at the top position and a methyl ester group (CO2Me) at the bottom position. The reaction arrow points to the right, with conditions listed above and below it: '1) 215 °C' and '2) HCl (aq), EtOH'. The product is a bicyclic enone, specifically a decalin derivative with a ketone group (C=O) at the top position of the right-hand ring and a double bond between the top and bottom carbons of the same ring. The methyl ester group (CO2Me) remains attached to the bottom carbon of the double bond.
(b(ii)) A chemical reaction scheme showing a sigmatropic rearrangement. The reactant is a bicyclic alkene, specifically a norbornene derivative with an exocyclic double bond on the five-membered ring portion. The reaction arrow points to the right with the condition '33 °C' written above it. The product is a bicyclic alkene, specifically a norbornene derivative where the double bond has migrated to an endocyclic position within the five-membered ring.
(c) Reaction scheme: An acyl chloride (R-C(=O)-Cl) reacts with sodium azide (NaN3) in an inert solvent, followed by heat, to form an isocyanate (R-N=C=O).
Model answer
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3. (a) (i) Methyl cyanide + dilute HCl, heat
- Major product: acetic acid (ethanoic acid), with ammonium chloride. CH₃CN + 2 H₂O + HCl → CH₃COOH + NH₄Cl. The reaction goes through acetamide.
Mechanism, stage 1 (nitrile → amide):
- H⁺ protonates the nitrile nitrogen (CH₃–C≡N⁺–H). This makes the sp carbon strongly electrophilic.
- Water, a weak nucleophile, adds to that carbon. Loss of H⁺ gives the imidic acid CH₃–C(OH)=NH.
- The imidic acid tautomerises to the more stable amide, CH₃CONH₂ (acetamide).
Mechanism, stage 2 (amide → acid):
- The carbonyl oxygen of the amide is protonated.
- Water adds, giving the tetrahedral intermediate CH₃C(OH)₂NH₃⁺.
- NH₃ is expelled and is immediately captured as NH₄⁺. This makes the step irreversible and drives the reaction to completion.
- Mild conditions: with short times or controlled acid, the reaction can be stopped at acetamide. Prolonged heating gives the acid.
(a) (ii) Br₂ + 2-butenes: stereospecific anti addition
- Step 1: the π bond polarises Br₂ and a cyclic bromonium ion forms. The alkene geometry is frozen in this three-membered ring: there is no open carbocation and no C–C rotation.
- Step 2: Br⁻ opens the ring by backside (SN2-like) attack from the face opposite the bridging Br. The two Br atoms therefore end up anti.
- cis-2-Butene: the bromonium ion has a mirror plane. Br⁻ attacks C-2 or C-3 with equal probability, giving (2R,3R)- and (2S,3S)-2,3-dibromobutane in a 1 : 1 ratio. This is an optically inactive racemic mixture.
- trans-2-Butene: anti attack at either carbon, on either face, gives the same (2R,3S) isomer. It has an internal mirror plane (Br on the same side in the Fischer projection), so it is meso.
- Why this proves anti addition: syn addition, or a free carbocation, would give the opposite outcome or a mixture. The clean stereospecificity is therefore evidence for the bridged bromonium ion.
(b) (i) Enone formation: 6π electrocyclisation, then hydrolysis
- The substrate is a conjugated hexatriene: CH₂=C(OMe)–C=C–CH=CH–CO₂Me. The central C=C is the cyclohexene ring bond, which holds the triene in the required cis (s-cis, s-cis) arrangement.
- At 215 °C, thermal 6π electrocyclic ring closure forms a new σ bond between the triene termini (the CH₂ and the CH bearing CO₂Me). The product is a cyclohexadiene fused to the cyclohexane ring, and the OMe group is now on an enol-ether C=C.
Why it is disrotatory (Woodward–Hoffmann rules):
- The system has 6 π electrons, which is 4n+2.
- The thermal HOMO of a hexatriene is ψ₃, whose terminal lobes have the same sign on the same face.
- Bonding overlap therefore requires the termini to rotate in opposite senses (disrotatory), which is symmetry-allowed.
- Here one terminus is CH₂, so the only new stereocentre is the CH–CO₂Me carbon, and the product is racemic.
Step 2, HCl(aq)/EtOH:
- The methyl enol ether is protonated at carbon and hydrolysed to a ketone, with loss of MeOH. This first gives a β,γ-unsaturated ketone.
- Acid-catalysed enolisation moves the C=C into conjugation with C=O at the ring fusion. The product is the thermodynamically preferred α,β-unsaturated ketone (octalone), methyl 4-oxo-1,2,3,4,5,6,7,8-octahydronaphthalene-2-carboxylate.
- Overall sequence: electrocyclisation → enol-ether hydrolysis → conjugation. It is not a Claisen rearrangement, because there is no allyl vinyl ether.
(b) (ii) Classification of the rearrangement at 33 °C
Class: [3,3]-sigmatropic shift (a Cope rearrangement of the divinylcyclopropane type).
- The reacting 1,5-diene is CH₂=CH–C6–C1–C2=C3.
- The σ bond that migrates is the strained cyclopropane bond C1–C6, which sits in position 1,1′ of the two allyl fragments.
- A new σ bond forms between atoms 3 and 3′ (vinyl CH₂ and ring C3), converting endo-6-vinylbicyclo[3.1.0]hex-2-ene into bicyclo[3.2.1]octa-2,6-diene.
Symmetry: allowed.
- Six electrons (two π bonds and one σ bond) reorganise in a cyclic array: 4n+2.
- With both allyl components suprafacial ([π2s + σ2s + π2s]), the transition state is aromatic (Hückel), so the reaction is thermally allowed.
Why it is so fast:
- The rigid bicycle holds the endo vinyl group over the ring, so it must react through a boat-like transition state.
- Breaking a cyclopropane bond releases about 115 kJ mol⁻¹ of ring strain, so the reaction proceeds even at 33 °C.
(b) (iii) Diels–Alder: 2-methoxy-5-methyl-1,4-benzoquinone + butadiene (100 °C)
- Roles: butadiene is the diene. The quinone is the dienophile, because each of its C=C bonds is activated by two C=O groups.
- Site selectivity: the OMe-substituted C=C is a vinylogous ester. Oxygen lone-pair donation makes it electron-rich and a poor dienophile. The methyl-substituted C=C is only weakly deactivated, so butadiene adds there.
Product: cis-2-methoxy-4a-methyl-4a,5,8,8a-tetrahydronaphthalene-1,4-dione (racemic).
- The new cyclohexene ring carries an angular methyl group at the ring fusion.
- The enone C=C bearing OMe survives, between the two C=O groups.
- Stereochemistry: the addition is suprafacial on the dienophile, so the angular CH₃ and the ring-fusion H end up cis (cis ring fusion). The endo/exo question does not arise, because butadiene is unsubstituted.
- Context: this is the first step of Woodward's total synthesis of steroids (cholesterol and cortisone, 1951–52). There, base later epimerised the cis adduct to the trans-fused isomer.
(c) (i) RCOCl → RN=C=O via a nitrene (Curtius rearrangement)
- Step 1: azide ion substitutes chloride at the acyl carbon (addition–elimination) in an inert solvent, giving the acyl azide R–C(=O)–N=N⁺=N⁻.
- Step 2: on heating, N₂ (an excellent, entropically favoured leaving group) is lost. This leaves the acyl nitrene R–C(=O)–N̈:, a neutral, monovalent nitrogen with only six valence electrons, which is electron-deficient like a carbene.
- Step 3: the electron-deficient N accepts R, which migrates from carbon to nitrogen with its bonding pair (a 1,2-shift). This gives the isocyanate R–N=C=O. In water the isocyanate would go on to the amine plus CO₂, and in alcohol to a carbamate.
Evidence for the nitrene / intramolecular pathway:
- A chiral R group migrates with complete retention of configuration.
- Crossover experiments give no mixed products, so the migration is intramolecular.
- Photolysis of acyl azides gives products of nitrene trapping (C–H insertion into the solvent, aziridines with alkenes).
- The nitrene route is the classical textbook description. Kinetic and computational studies suggest the thermal reaction is largely concerted, with loss of N₂ and migration occurring together, so a free nitrene is established mainly under photolysis.
Orbital pictures of the nitrene:
- N makes one σ bond to R and holds a lone pair in an sp-type orbital pointing away from R. It has two non-bonding p orbitals (pₓ and p_y), perpendicular to the R–N axis, which share the remaining 2 electrons.
- Triplet: one electron in each p orbital, with parallel spins. By Hund's rule this is the ground state of NH and most alkyl and aryl nitrenes. It behaves as a diradical: it abstracts H atoms and adds to alkenes non-stereospecifically.
- Singlet: both electrons paired in one p orbital, with the other p orbital empty. It is electrophilic and carbene-like, adds to alkenes stereospecifically and inserts into C–H bonds. Acyl nitrenes gain extra singlet stabilisation from the neighbouring C=O.
(c) (ii) Account for the following
(1) Indole substitutes at C-3.
- Attack of E⁺ at C-3 gives a σ-complex whose positive charge sits on C-2, directly next to N. The N lone pair therefore stabilises it as an iminium ion (every atom has an octet), and the benzene ring stays fully aromatic.
- Attack at C-2 puts the charge on C-3. That cation is stabilised only as a benzylic cation; N can share the charge only through a quinoid form that destroys the benzene sextet.
- The C-3 intermediate, and so the transition state leading to it, is much lower in energy. Indole therefore behaves like an enamine at C-3: bromination, Vilsmeier formylation and the Mannich reaction (giving gramine) all occur at C-3.
(2) Chlorobenzene resists nucleophilic substitution.
- Resonance: the Cl lone pair conjugates with the ring, giving the C–Cl bond partial double-bond character. The bond is shorter (about 170 pm, against 178 pm in CH₃Cl) and stronger.
- sp² carbon: the sp²-hybridised carbon (more s character) holds the bonding electrons more tightly, making Cl⁻ harder to expel.
- No SN2: backside attack is impossible because the ring blocks the σ* orbital, and inversion at a ring carbon is geometrically forbidden.
- No SN1: the phenyl cation would be very unstable, with its empty sp² orbital not conjugated with the π system.
- Repulsion: the electron-rich π cloud repels incoming nucleophiles.
- When substitution does occur: only under forcing conditions (Dow process: NaOH, about 623 K, high pressure), through benzyne (NaNH₂), or by SNAr when –NO₂ groups sit ortho/para to Cl. For example, 2,4-dinitrochlorobenzene reacts readily through a Meisenheimer complex.
How this answer will be evaluated
What earns full marks: Complete mechanisms with correct stereochemistry, orbital diagrams, and electronic reasoning throughout.
Evaluation rubric
Each sub-part is marked on its own, against the marks and word limit printed on the paper.
- (a)(i) Mechanism and major product of methyl cyanide hydrolysis with dilute HCl. 10 marks
explain— definition/context → points in order → small example → short close
Must cover
- Protonation of nitrile nitrogen
- Nucleophilic attack by water
- Tautomerization to amide intermediate
- Final product: acetic acid and ammonium chloride
Loses marks
- Product without mechanism
- Missing amide intermediate
Earns more
- Arrow-pushing mechanism shown
- Intermediate structures drawn
Extra mark
- Note that NH₃ is trapped as NH₄⁺ (drives the reaction) and that controlled conditions can stop at acetamide
- (a)(ii) Stereochemical outcome of bromine addition to cis- and trans-2-butene. 5 marks
justify— claim → 3-4 reasons → evidence → conclusion
Must cover
- Anti-addition mechanism via bromonium ion
- Cis-2-butene yields racemic mixture
- Trans-2-butene yields meso compound
- Stereochemical reasoning for each
Loses marks
- Syn-addition mechanism
- Confusing racemic and meso products
Earns more
- Bromonium ion intermediate drawn
- Backside attack shown
Extra mark
- Fischer projections of products
- (b)(i) Mechanism of enone formation in the given thermal reaction. 5 marks
explain— definition/context → points in order → small example → short close
Must cover
- Thermal 6π electrocyclic ring closure of the hexatriene
- Disrotatory motion (4n+2 electrons, thermal)
- Cyclohexadiene methyl enol ether intermediate
- Acid hydrolysis of the enol ether and C=C migration into conjugation give the enone
Loses marks
- Conrotatory motion, or calling it a ring opening / Claisen rearrangement
- Missing enol-ether hydrolysis or double-bond isomerisation
Earns more
- Arrow-pushing mechanism
- Intermediate structures
Extra mark
- Woodward–Hoffmann analysis using the HOMO (ψ₃) terminal-lobe symmetry
- (b)(ii) Classification and symmetry analysis of the sigmatropic rearrangement. 5 marks
comment— context → arguments both sides → judgment → close
Must cover
- Identify as a [3,3]-sigmatropic (Cope, divinylcyclopropane-type) rearrangement
- Identify the cyclopropane σ bond that breaks and the new C–C bond formed
- Suprafacial-suprafacial pathway
- Symmetry-allowed classification
Loses marks
- Wrong sigmatropic classification
- Symmetry-forbidden conclusion
Earns more
- Orbital symmetry: 6 electrons, 4n+2, aromatic (Hückel) TS
- Boat-like TS enforced by the endo vinyl group; strain release explains reaction at 33 °C
Extra mark
- Name the product bicyclo[3.2.1]octa-2,6-diene
- (b)(iii) Structure of major product from Diels-Alder reaction. 5 marks
describe— define → structure or process in order → labelled diagram → significance
Must cover
- Butadiene is the diene and the quinone the dienophile
- Cyclohexene ring formation
- Addition at the methyl-bearing C=C (OMe-bearing C=C is deactivated)
- cis ring fusion: 2-methoxy-4a-methyl-4a,5,8,8a-tetrahydronaphthalene-1,4-dione
Loses marks
- Adding to the OMe-bearing C=C, or treating the quinone as the diene
- Missing cyclohexene ring
Earns more
- Arrow-pushing mechanism
- Transition state drawing
Extra mark
- Note Woodward's steroid synthesis (angular methyl) or later epimerisation to trans
- (c)(i) Nitrene intermediate formation and orbital diagrams of singlet/triplet states. 10 marks
explain— definition/context → points in order → small example → short close
Must cover
- Acyl azide formation from acid chloride
- Loss of N₂ gives the acyl nitrene (N with 6 valence electrons)
- Singlet nitrene orbital diagram
- Triplet nitrene orbital diagram
Loses marks
- Missing nitrene intermediate
- Incorrect orbital diagrams
Earns more
- 1,2-shift of R from C to N gives R–N=C=O with retention of configuration
- Orbital energy levels shown
Extra mark
- Evidence: retention, no crossover, photolytic nitrene trapping; note thermal Curtius may be concerted
- (c)(ii) Reasons for indole 3-substitution and chlorobenzene nucleophilic resistance. 10 marks
account for— state the phenomenon → the causes in order of weight → conclusion
Must cover
- Indole: 3-position carbocation stability
- Indole: aromaticity preservation
- Chlorobenzene: resonance gives partial C=Cl double bond (shorter, stronger bond)
- Chlorobenzene: SN2 backside attack blocked and phenyl cation too unstable for SN1
Loses marks
- 2-substitution justification
- Missing resonance structures
Earns more
- Resonance structures drawn
- Carbocation intermediates shown
Extra mark
- Mention of SNAr mechanism
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