Paper II — Q2
(a) (i) In the presence of sodium ethoxide, the following transformation occurs. Explain : (ii) Propose a suitable mechanism for…
In the presence of sodium ethoxide, the following transformation occurs. Explain :
Propose a suitable mechanism for the following transformation :
The following reaction does not produce the product shown :
(1) Predict the major product from the conditions shown above, and write a detailed mechanism for its formation.
(2) Write that reaction conditions which would lead to successful synthesis of the product shown above (i.e., 3,3-dimethyl-2-butanol).
Write the structure of the major product(s) formed in the following reaction. Justify your answer :
Write the structure of the major product(s) formed in the following reactions :
(i)
(ii)
(iii)
(iv)
हिंदी में प्रश्न पढ़ें
सोडियम एथॉक्साइड की उपस्थिति में निम्नलिखित रूपांतरण होता है। व्याख्या कीजिए।
निम्नलिखित रूपांतरण के लिए उपयुक्त क्रियाविधि प्रस्तावित कीजिए :
निम्नलिखित अभिक्रिया में दर्शाया हुआ उत्पाद नहीं बनता है :
(1) उपर दर्शाई गई अवस्था में बनने वाले मुख्य उत्पाद का पूर्वानुमान लगाइए व इसके बनने की क्रियाविधि की विस्तृत जानकारी दीजिए।
(2) उस अभिक्रिया अवस्था को लिखिए, जिससे उपयुक्त उत्पाद (अर्थात् 3,3-डाइमेथिल-2-ब्यूटेनॉल) का सफल संश्लेषण किया जा सके।
निम्नलिखित अभिक्रिया में बनने वाले मुख्य उत्पाद/उत्पादों की संरचना लिखिए। अपने उत्तर का औचित्य सिद्ध कीजिए :
निम्नलिखित अभिक्रियाओं में बनने वाले मुख्य उत्पाद/उत्पादों की संरचना लिखिए :
(i)
(ii)
(iii)
(iv)
The figure this question refers to, in words
The question paper is a scan and the diagram did not survive as text. This is the figure as read from the original page — every component, value and label — so the question can be worked from the text below.
(a) Reaction scheme (i): A cyclopentanone ring bearing a methyl group at the alpha-carbon and an -OEt group at the other alpha-carbon (a 2-methyl-2-ethoxycarbonyl cyclopentanone) is treated with 1) NaOEt 2) HCl to give a cyclopentanone ring with a methyl group and an -OEt group rearranged to the adjacent position (ring contraction/expansion product). Reaction scheme (ii): An epoxide of a long-chain alkene (a terminal epoxide on a chain with a methyl branch) is treated with H2SO4 / H2O to give a bicyclic decalin-type diol with two hydroxyl groups and a methyl substituent.
(a(i)) A chemical reaction scheme. The reactant is 2-methyl-2-(ethoxycarbonyl)cyclopentan-1-one, which consists of a five-membered cyclopentane ring with a ketone group (C=O) at position 1 and a quaternary carbon at position 2 bearing a methyl group and an ethoxycarbonyl group (-C(=O)OEt). The reaction conditions are listed as: 1) NaOEt, 2) HCl. The product is 2-methylcyclopentane-1,3-dione with an ethoxycarbonyl group at position 3, specifically ethyl 2-methyl-3-oxocyclopentane-1-carboxylate. The product structure shows a five-membered ring with a ketone at position 1, a methyl group at position 2, and a ketone and an ethoxycarbonyl group (-C(=O)OEt) at position 3.
(a(ii)) A chemical reaction scheme. The reactant is an acyclic molecule containing an epoxide ring at one end and a terminal alkene at the other. The structure is 2,2-dimethyl-7-octen-1-yl epoxide (or 2,2-dimethyl-7-octen-1-ol epoxide). Specifically, it is an epoxide ring where one carbon is bonded to two methyl groups and the other carbon is bonded to a hydrogen and a carbon chain. The chain is -CH2-CH2-CH=CH-CH2-CH3 (a hex-3-enyl group). The reaction conditions are H2SO4 and H2O. The product is a bicyclic diol, specifically a decalin derivative (decahydronaphthalene). The product structure shows a fused six-membered ring system. One ring has a gem-dimethyl group and a hydroxyl group (-OH) on the adjacent carbon. The other ring has a hydroxyl group (-OH) at the position corresponding to the original terminal alkene.
(b(i)) A reaction scheme showing 3,3-dimethyl-1-butene (a terminal alkene with a quaternary carbon adjacent to the double bond) reacting with water (H2O) in the presence of catalytic sulfuric acid (Cat. H2SO4). An arrow points to a product structure, 3,3-dimethyl-2-butanol, which is crossed out with a large 'X' to indicate it is not formed.
(b(ii)) A reaction scheme showing styrene (vinylbenzene) reacting with bromotrichloromethane (BrCCl3) under light (hv). An arrow points to a question mark, indicating the product is to be determined.
(c(i)) A reaction scheme showing 2-(3-oxobutyl)cyclohexanone (a cyclohexanone ring with a ketone side chain at the 2-position) reacting with 1) KOH followed by 2) HA (acid workup). An arrow points to a question mark.
(c(ii)) A reaction scheme showing a bicyclic amine structure (specifically a quinuclidine derivative) with a tertiary alcohol substituent at the bridgehead carbon. The substituent is a carbon atom bonded to the ring, two phenyl groups (Ph), and a hydroxyl group (OH). The reaction conditions are H+ (acid). An arrow points to a question mark.
(c(iii)) A reaction scheme showing 1-tetralone (a bicyclic ketone consisting of a benzene ring fused to a cyclohexanone ring) reacting with 1) hydroxylamine (NH2OH) followed by 2) aluminum oxide (Al2O3). An arrow points to a question mark.
(c(iv)) A reaction scheme showing a complex diester molecule. The structure is a central carbon chain with multiple ester groups (CO2Et). Specifically, it appears to be a substituted malonate derivative with an additional ester group. The reaction condition is ethoxide ion (EtO-). An arrow points to a question mark.
Model answer
Drafted with AI by UPSC Answer Check against this question's marking rubric, to the expected length. UPSC does not publish answers for Mains — this is one way to score well, not an official key. How we build rubrics and answers.
(a)
(i) Transformation of 2-methyl-2-carbethoxycyclopentanone The reaction proceeds via a retro-Dieckmann/Dieckmann sequence rather than a standard Claisen condensation. The starting material possesses a quaternary α-carbon bearing the ester group, which lacks an acidic proton. Consequently, the base (NaOEt) cannot form an enolate at this position. Instead, the ethoxide ion attacks the ketone carbonyl, forming a tetrahedral intermediate. This intermediate undergoes a retro-Dieckmann ring-opening, cleaving the C–C bond to yield an open-chain diethyl 2-methylhexanedioate. The newly revealed methylene group (CH₂) adjacent to the ester is acidic; deprotonation by ethoxide generates an enolate. This enolate then undergoes an intramolecular Dieckmann cyclization by attacking the other ester carbonyl. The resulting β-keto ester product possesses an acidic α-hydrogen. The formation of the stabilized enolate of this product drives the equilibrium toward the cyclized form. Finally, the addition of HCl reprotonates the enolate to yield the neutral 2-methyl-5-carbethoxycyclopentanone (ethyl 3-methyl-2-oxocyclopentanecarboxylate).
(ii) Mechanism for the cyclisation of the epoxy-diene The transformation is a cationic cyclization initiated by acid. The epoxide oxygen is protonated by H₂SO₄, increasing the electrophilicity of the ring. The epoxide ring opens at the more substituted carbon to generate a stable tertiary carbocation. The pendant alkene then attacks this cation intramolecularly in a Markovnikov fashion, forming the first six-membered ring and a new secondary carbocation. A second intramolecular cyclization occurs as the remaining alkene attacks this new cation, closing the second ring to form a bicyclic cation. Water acts as a nucleophile to trap the final carbocation, yielding the alcohol. The reaction proceeds through chair-like transition states, which favor the formation of a trans-fused decalin system due to steric minimization.
(b)
(i) Hydration of 3,3-dimethyl-1-butene (1) The reaction does not yield the product shown because the initially formed carbocation is unstable. Protonation of the alkene at C1 generates a secondary carbocation at C2. This cation is adjacent to a quaternary carbon (C3). A 1,2-methyl shift (Wagner–Meerwein rearrangement) occurs, moving a methyl group from C3 to C2. This rearrangement converts the secondary cation into a more stable tertiary cation at C3. Water then attacks this tertiary cation, and subsequent deprotonation yields 2,3-dimethylbutan-2-ol as the major product. (2) To synthesize 3,3-dimethyl-2-butanol (the unrearranged product), one must use oxymercuration–demercuration. The reagents are 1) Hg(OAc)₂, H₂O and 2) NaBH₄. In this mechanism, the alkene reacts with the mercuric ion to form a bridged mercurinium ion. Water attacks the more substituted carbon of the bridge. Because the intermediate is a bridged ion rather than a free carbocation, 1,2-shifts (rearrangements) cannot occur. The final reduction with NaBH₄ replaces the mercury group with hydrogen, yielding the unrearranged alcohol.
(ii) Styrene + BrCCl₃, hν The reaction is a radical chain addition known as the Kharasch reaction.
- Initiation: Light (hν) causes homolysis of BrCCl₃ to form ·CCl₃ and Br· radicals.
- Propagation: The ·CCl₃ radical adds to the terminal CH₂ of the styrene. This regioselectivity is driven by the formation of a benzylic radical intermediate, which is stabilized by resonance with the aromatic ring.
- Propagation (second step): The benzylic radical abstracts a bromine atom from another molecule of BrCCl₃ to form the product and regenerate the ·CCl₃ radical.
The major product is PhCH(Br)CH₂CCl₃.
(c)
(i) 2-(3-oxopentyl)cyclohexanone + KOH, then HA This is an intramolecular aldol condensation. The base (KOH) deprotonates the α-carbon of the ethyl ketone side chain. The resulting enolate attacks the ketone carbonyl of the cyclohexanone ring. This forms a six-membered ring (the new ring) fused to the original ring. The initial aldol product (a β-hydroxy ketone) undergoes dehydration under the reaction conditions (or upon heating with acid) to form the conjugated enone. Product: 1-methyl-4,4a,5,6,7,8-hexahydronaphthalen-2(3H)-one.
(ii) Quinuclidine derivative + H⁺ This is a pinacol (or semipinacol) rearrangement. Protonation of the hydroxyl group on the diphenyl-substituted carbon leads to the loss of water, generating a carbocation at that position. This cation is highly stabilized by the two phenyl rings. To relieve steric strain and form a stable carbonyl, a C–C bond of the bicyclic amine framework migrates to the cationic center. This migration expands the ring size and converts the adjacent hydroxyl group into a ketone. Product: A ring-expanded bicyclic ketone: the C–C bond of the bicyclic amine framework migrates to the diphenylcarbinyl cation, one ring grows by one carbon atom and the carbinol-bearing ring carbon becomes a ketone; the two phenyl groups remain attached at the migration terminus.
(iii) Benzosuberone + NH₂OH, then Al₂O₃ This is a Beckmann rearrangement. First, the ketone reacts with hydroxylamine (NH₂OH) to form an oxime. The oxime is then heated over alumina (Al₂O₃). The group anti to the oxime hydroxyl group migrates to the nitrogen atom, accompanied by the loss of water. In this cyclic ketone, the migration of the ring carbon expands the seven-membered ring to an eight-membered ring. Product: 3,4,5,6-tetrahydro-1-benzazocin-2(1H)-one (a benzo-fused eight-membered lactam formed by aryl migration).
(iv) Tetraester + EtO⁻ This is a Dieckmann condensation. The substrate contains multiple ester groups. The central carbon is fully substituted (quaternary) and has no acidic protons. However, the terminal methylene group (CH₂) adjacent to an ester is acidic. Ethoxide deprotonates this CH₂ to form an enolate. This enolate attacks the ester carbonyl on the other end of the chain. The resulting intermediate expels an ethoxide ion to form a cyclic β-keto ester. Product: A cyclopentanone ring bearing a β-keto triester functionality.
How this answer will be evaluated
What earns full marks: Every product right with arrow-pushing; each rearrangement and its driving force stated.
Evaluation rubric
Each sub-part is marked on its own, against the marks and word limit printed on the paper.
- (a) (i) Why NaOEt then HCl moves the methyl of the 2-methyl-2-carbethoxycyclopentanone to the other α-carbon; (ii) a mechanism for the H2SO4/H2O cyclisation of the epoxy-diene to the decalindiol. 15 marks
explain— definition/context → points in order → small example → short close
Must cover
- (i) Quaternary α-carbon: no acidic H, so ethoxide attacks the ketone
- (i) Retro-Dieckmann ring-opening to diethyl 2-methylhexanedioate, then Dieckmann re-closure at the new CH₂
- (i) Product 2-methyl-5-carbethoxycyclopentanone (= ethyl 3-methyl-2-oxocyclopentanecarboxylate); its acidic α-H enolate drives the equilibrium; HCl reprotonates
- (ii) Protonated epoxide opens at the more substituted carbon to the tertiary cation; the two alkenes cyclise sequentially (chair-like TS, trans-decalin); water traps the final cation — bicyclic diol
Loses marks
- Calls (i) a simple Claisen condensation
- Product drawn without a mechanism
- (ii) Epoxide opened at the less substituted carbon
Earns more
- (i) Open-chain diethyl 2-methylhexanedioate intermediate drawn
- (ii) Chair-like transition states give the trans-fused decalin
- (ii) Markovnikov cation at each ring closure
- Curved arrows for every step
Extra mark
- (ii) Names the epoxide-initiated polyene cyclisation
- (i) Explains why re-closure at the methyl-bearing carbon reverses
- (b)(i) Major product of acid-catalysed hydration of 3,3-dimethyl-1-butene with its mechanism, and conditions that give 3,3-dimethyl-2-butanol instead. 10 marks
explain— definition/context → points in order → small example → short close
Must cover
- Markovnikov protonation at C1 gives the secondary cation at C2, adjacent to the quaternary C3
- 1,2-methyl shift (Wagner–Meerwein) converts it into the tertiary cation; water then adds
- Major product 2,3-dimethyl-2-butanol (structure drawn in the added figure), not the alcohol shown
- Oxymercuration–demercuration (Hg(OAc)₂/H₂O then NaBH₄) gives 3,3-dimethyl-2-butanol — the bridged mercurinium ion prevents rearrangement
Loses marks
- Proposes hydroboration–oxidation for 3,3-dimethyl-2-butanol
- Product without the rearrangement step
- Writes 3,3-dimethyl-2-butanol as the major hydration product
Earns more
- Names the Wagner–Meerwein rearrangement
- States that no free carbocation forms in oxymercuration
- Tertiary cation more stable than secondary: the driving force
- Mercurinium ion opened by water at the more substituted carbon
Extra mark
- Notes hydroboration–oxidation would give the primary alcohol instead
- Draws the three-centre transition state of the methyl shift
- (b)(ii) Structure of the product of BrCCl3 addition to styrene under light, with reasons. 5 marks
justify— claim → 3-4 reasons → evidence → conclusion
Must cover
- Radical chain (Kharasch): light homolyses BrCCl₃ into ·CCl₃ and Br·
- ·CCl₃ adds to the terminal CH₂ giving the resonance-stabilised benzylic radical
- The benzylic radical abstracts Br from BrCCl₃ → PhCH(Br)CH₂CCl₃ (structure drawn in the added figure)
Loses marks
- Br placed on the terminal carbon
- Ionic mechanism written under light
Earns more
- Benzylic radical stabilised by resonance with the ring
- Propagation: the radical abstracts Br from BrCCl3
- Names the Kharasch addition
Extra mark
- Contrasts with the ionic addition regiochemistry
- (c) Major products of four reactions: (i) KOH then acid on 2-(3-oxopentyl)cyclohexanone; (ii) acid on the quinuclidine 1,2-diol bearing C(OH)Ph2; (iii) NH2OH then Al2O3 on benzosuberone; (iv) ethoxide on the tetraester. 20 marks
describe— define → structure or process in order → labelled diagram → significance
Must cover
- (i) Intramolecular aldol (enolate of the ethyl-ketone side chain) then dehydration: 1-methyl-4,4a,5,6,7,8-hexahydronaphthalen-2(3H)-one (drawn)
- (ii) Pinacol/semipinacol rearrangement via the diphenyl-stabilised cation; one ring expands by one carbon and a ketone is formed (structure described in text)
- (iii) Oxime, then Beckmann rearrangement over alumina: aryl migration gives the ring-expanded benzo-fused 8-membered lactam 3,4,5,6-tetrahydro-1-benzazocin-2(1H)-one (drawn)
- (iv) Dieckmann condensation at the terminal CH₂ next to the ester: cyclopentanone β-keto triester (drawn)
Loses marks
- (iii) Stops at the oxime
- (i) Aldol product left undehydrated
- Structures without arrows where a mechanism decides the product
Earns more
- (i) Enolate of the ethyl ketone attacks the ring carbonyl
- (ii) Cation at the diphenyl carbon, not the ring carbon
- (iii) The group anti to the oxime OH migrates to nitrogen
- (iv) Malonate carbon has no H; only the terminal CH2 enolises
Extra mark
- (i) Recognises the Robinson annulation end-game
- (iv) Explains why closure at the methyl-bearing carbon reverses
What "Explain" is asking you to do
Make the working of something clear — what sets it off, what follows from what, and what it produces. Explain is the Commission's mechanism word: it dominates the technical papers and the “explain why” stems, where the marks sit in the causal chain and not in the label.
Structure that answers it
State what it is → the initiating condition → the chain of cause, step by step → an instance where it plays out → what the chain produces
Where marks are lost
Describing what something looks like instead of why it works that way. Naming the stages without linking them reads as description too.
Practice this exact question
Write your answer and it is marked point by point against the model answer above — what you covered, what you missed, what you got wrong.
Evaluate my answer →More from Chemistry 2025 Paper II
- Q1 (a) (i) Tropolone is aromatic, but fulvene is non-aromatic. Why? (ii) Explain with exampl…
- Q2 (a) (i) In the presence of sodium ethoxide, the following transformation occurs. Explain…
- Q3 (a) (i) Write the structure of the product formed in the following reactions: (1) (2) (10…
- Q4 (a) (i) After polymerization of p-hydroxybenzoic acid, IR analysis shows 0·2% unreacted —…
- Q5 (a) Write the structure of the product(s) and the intermediate formed in the following re…