Civil Engineering 2023 Paper I 50 marks Solve

Q2

(a) Draw the shearing force and bending moment diagrams for the beam loaded as shown in the figure below. (8 marks) (b) During the design of a beam, an ISMB 550 @ 1·037 kN/m is selected for use as a simply supported beam of 7 m span carrying a reinforced concrete floor capable of providing lateral restraint to the top compression flange. The total uniformly distributed load is made up of 100 kN dead load and 150 kN imposed load. In addition to this load, the beam also carries a point load at its midspan which is made up of 50 kN dead load and 50 kN imposed load. Check the adequacy of the section for the following : (i) Shear strength (ii) Bending strength (iii) Deflection (iv) Web buckling at support Assume the section is plastic. Given : Stiff bearing length = 100 mm f_y = 250 MPa, E = 2 × 10⁵ MPa γ_mo = 1·1 For plastic section β_b = 1·0 For simply supported beam, ψ = 1·2 | KL/r | 90 | 100 | 110 | 120 | |------|-----|------|------|------| | f_cd (MPa) | 121 | 107 | 94·6 | 83·7 | Properties of ISMB 550 : Elastic section modulus, Zₑ = 2359·8 × 10³ mm³ Plastic section modulus, Zₚ = 2711·98 × 10³ mm³ Moment of Inertia about major axis, I₂₂ = 64900 × 10⁴ mm⁴ (All dimensions are in mm) (20 marks) (c) Using the unit load method, determine horizontal and vertical components of deflection at point A for the frame loaded as shown in the figure below. Support C is fixed and B is a rigid joint. Take E as constant and same for both the members. (15 marks)

हिंदी में प्रश्न पढ़ें

(a) नीचे चित्र में दर्शाए अनुसार भारित धरन के लिए अपरूपण बल और बंकन आघूर्ण आरेख बनाइए । (8 अंक) (b) धरन की अभिकल्पना के दौरान, एक ISMB 550 @ 1·037 kN/m को एक 7 m विस्तृति की शुद्धलंबित धरन की तरह उपयोग के लिए चुना गया जो शीर्ष संपीडन फ्लैंज को पार्श्वतः बाधित करने में सक्षम एक प्रबलित कंक्रीट फर्श को वहन करती है। सकल एकसमान वितरित भार 100 kN अचल भार और 150 kN अध्यारोपित भार से बना है। इस भार के अतिरिक्त, धरन अपनी विस्तृति के मध्य में एक बिंदु भार भी वहन करती है जो 50 kN के अचल भार और 50 kN के अध्यारोपित भार से बना है। निम्नलिखित के लिए परिछेद की पर्याप्तता की जांच कीजिए : (i) अपरूपण सामर्थ्य (ii) बंकन सामर्थ्य (iii) विस्थाप (iv) आलंब पर वेब व्याकुंचन परिछेद को सुखदाय मान लीजिए । प्रदत्त : दृढ़ धारण लंबाई = 100 mm f_y = 250 MPa, E = 2 × 10^5 MPa γ_mo = 1·1 सुखदाय परिछेद के लिए, β_b = 1·0 शुद्धलंबित धरन के लिए, ψ = 1·2 | KL/r | 90 | 100 | 110 | 120 | |------|-----|------|------|------| | f_cd (MPa) | 121 | 107 | 94·6 | 83·7 | ISMB 550 के गुण : प्रत्यास्थ परिच्छेद मापाक, Zₑ = 2359·8 × 10³ mm³ सुचद्रय परिच्छेद मापाक, Zₚ = 2711·98 × 10³ mm³ मुख्य अक्ष के परितः जड़त्व आघूर्ण, I₂₂ = 64900 × 10⁴ mm⁴ (सभी विमाएँ mm में हैं) (20 अंक) (c) एकांक भार विधि का उपयोग करके, नीचे चित्र में दर्शाए अनुसार भारित फ्रेम के लिए बिंदु A पर विसर्प के क्षैतिज और उद्वर्धर घटकों को निर्धारित कीजिए । आलम्ब C आबद्ध है और B दृढ़ जोड़ है । E को नियत और दोनों अवयवों के लिए समान लीजिए । (15 अंक)

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How this answer will be evaluated

Approach

Solve this multi-part structural analysis problem by allocating approximately 20% time to part (a) for SFD/BMD construction, 45% to part (b) for comprehensive steel beam design checks (shear, bending, deflection, web buckling), and 35% to part (c) for unit load method application. Begin with clear free-body diagrams, proceed through systematic calculations with IS 800:2007 provisions, and conclude with adequacy statements for each check.

Key points expected

  • Part (a): Correct determination of support reactions and construction of SFD and BMD with proper sign conventions and peak values marked
  • Part (b)(i): Shear strength check using V_d = V_n/γ_mo where V_n = 0.577f_yA_v with A_v = h×t_w for ISMB 550
  • Part (b)(ii): Bending strength calculation using M_d = β_bZ_pf_y/γ_mo with lateral restraint condition (ψ = 1.2) and comparison with factored moment
  • Part (b)(iii): Deflection check under service loads comparing calculated δ = 5WL³/384EI + PL³/48EI against span/360 or span/240 limits
  • Part (b)(iv): Web buckling check at support using F_w = (b_1+n_1)t_wf_cd with n_1 = 2.5d and interpolation from given KL/r vs f_cd table
  • Part (c): Application of unit load method with proper virtual work integration, calculation of horizontal and vertical deflection components at A using M and m diagrams
  • Correct use of partial safety factors: 1.5 for dead load, 1.5 for imposed load, and load combinations per IS 800:2007

Evaluation rubric

DimensionWeightMax marksExcellentAveragePoor
Concept correctness20%9Correctly identifies plastic section behavior, applies IS 800:2007 clauses for all four design checks, recognizes lateral restraint enables full plastic moment, and properly sets up virtual work equations for unit load method with correct sign conventionsApplies basic formulas with minor errors in code interpretation (e.g., confuses elastic and plastic modulus or misses lateral restraint benefit), some conceptual gaps in virtual work setupFundamental misconceptions such as using working stress method, ignoring partial safety factors, or incorrect virtual work principle application
Numerical accuracy20%9All calculations precise to 3 significant figures, correct interpolation for f_cd at KL/r ≈ 98-102, accurate factored load combinations (1.5DL + 1.5IL), and correct deflection superposition for combined loadingMinor arithmetic errors in intermediate steps or slight inaccuracies in interpolation, but final conclusions remain valid; occasional unit conversion errors (mm to m)Major calculation errors leading to wrong adequacy conclusions, incorrect load factors, or order-of-magnitude mistakes in section properties
Diagram quality20%9Neat, scaled SFD/BMD with all critical values labeled, clear free-body diagrams for frame in part (c), proper M and m diagrams for unit load method with dimensions and sign conventions indicated, and well-organized tabular presentation for design checksDiagrams present but lacking scale, missing some critical values, or poor labeling; adequate but not exemplary presentationMissing diagrams, unrecognizable sketches, or diagrams contradicting calculations; no free-body diagrams for frame analysis
Step-by-step derivation20%8Systematic presentation: reactions → internal forces → design checks with explicit formula statements, clear substitution of values, and logical flow from given data to final adequacy statement for each sub-part; proper virtual work integration steps shownSome steps skipped or combined without clarity, adequate but not fully transparent derivation; missing intermediate checksDisorganized calculations, unexplained jumps between steps, or missing essential derivations (e.g., direct final answers without showing work)
Practical interpretation20%8Explicit adequacy statements for all four checks in (b) with percentage utilization, practical significance of web buckling check at supports noted, and real-world implications of deflection limits on floor serviceability; mentions if section is over-designed or requires revisionBasic adequacy statements present but lacking quantitative utilization ratios or practical context; generic conclusionsNo conclusions on adequacy, missing interpretation of results, or incorrect practical implications (e.g., declaring unsafe section as safe)

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