Civil Engineering 2023 Paper I 50 marks Solve

Q4

(a) Determine the horizontal component of deflection of joint D of the truss loaded as shown in the figure. The cross-sectional area of each member is tabulated below. Take E = 200 kN/mm². Length of the members are indicated in the figure. Use Castigliano's theorems. (15 marks) Table : Area of cross-section | S.No | Member | Area of cross-section | |------|--------|----------------------| | 1. | AB | 765 mm² | | 2. | AD | 390 mm² | | 3. | DB | 575 mm² | | 4. | BC | 765 mm² | | 5. | CD | 390 mm² | (b) Determine the collapse load in case of propped cantilever of span 'l' and subjected to uniformly distributed load 'P' per metre length as shown in the figure. Take the plastic moment capacity of beam as M_P. (15 marks) (c) A circular water tank with flexible base is to be designed for a capacity of 450 kL. The depth of water is to be 4 m including a free board of 250 mm. Find the dimensions of the tank and design and detail the wall of the tank. Use M 20 concrete and Fe 250 steel. (20 marks) Given : Tensile stress in steel under direct tension for plain mild steel bars, σ_s = 115 MPa Permissible direct tensile stress in concrete (M 20), σ_ct = 1·2 MPa Unit weight of water, γ = 9800 N/m³

हिंदी में प्रश्न पढ़ें

(a) चित्र में दर्शाए अनुसार भारित कैंची के जोड़ D के विषम के क्षैतिज घटक को निर्धारित कीजिए। प्रत्येक अवयव का अनुप्रस्थ-परिच्छेद क्षेत्रफल नीचे सारणीकृत किया गया है। E = 200 kN/mm² लीजिए। अवयवों की लंबाई चित्र में दर्शित है। कास्टिग्लियानो के प्रमेयों का उपयोग कीजिए। (15 अंक) सारणी : अनुप्रस्थ-परिच्छेद का क्षेत्रफल | क्रमांक | अवयव | अनुप्रस्थ-परिच्छेद का क्षेत्रफल | | 1. | AB | 765 mm² | | 2. | AD | 390 mm² | | 3. | DB | 575 mm² | | 4. | BC | 765 mm² | | 5. | CD | 390 mm² | (b) चित्र में दर्शाए अनुसार, 'P' प्रति मीटर लंबाई के एकसमान वितरित भार से भारित 'l' विस्तृति के टेकदार प्रास के लिए निपात भार निर्धारित कीजिए । धरन की सुखदाय आरूण क्षमता को M_P लीजिए । (15 अंक) (c) 450 kL क्षमता के लिए नम्य आधार वाली एक वृत्ताकार पानी की टंकी की अभिकल्पना की जानी है । 250 mm के मुक्तांतर सहित जल की गहराई 4 m होनी है । टंकी की विमाओं को ज्ञात कीजिए और टंकी की दीवार का अभिकल्पन एवं विस्तरण कीजिए । M 20 कंक्रीट और Fe 250 इस्पात का उपयोग कीजिए । (20 अंक) प्रदत : सादा मृदु इस्पात छड़ों के लिए प्रत्यक्ष तनन में इस्पात में तनन प्रतिबल, σ_s = 115 MPa कंक्रीट (M 20) में अनुज्ञेय प्रत्यक्ष तनन प्रतिबल, σ_ct = 1·2 MPa जल का एकक भार, γ = 9800 N/m³

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How this answer will be evaluated

Approach

Solve all three sub-parts systematically, allocating time proportional to marks: approximately 35% for part (a) truss deflection using Castigliano's theorem, 30% for part (b) plastic collapse analysis of propped cantilever, and 35% for part (c) complete water tank design including dimensioning, wall thickness calculation, and reinforcement detailing. Begin each part with clear identification of given data, show complete derivations with formulae, and conclude with boxed final answers. For part (c), present design calculations followed by a neat sketch showing reinforcement arrangement.

Key points expected

  • Part (a): Correct application of Castigliano's first theorem by placing unit horizontal load at D, calculation of member forces P due to actual loading and ∂P/∂Q due to dummy load, summation of (P·L/AE)·(∂P/∂Q) for all members
  • Part (b): Identification of correct collapse mechanism for propped cantilever with UDL—formation of plastic hinge at fixed end and within span, use of virtual work or equilibrium method to relate external work to internal energy dissipation
  • Part (c): Calculation of tank diameter from capacity (450 kL) and effective depth (3.75 m), determination of hoop tension and bending moment coefficients from IS 3370 tables for H²/Dt ratio, design of vertical and horizontal reinforcement
  • Part (c): Check for tensile stress in concrete against permissible σ_ct = 1.2 MPa, calculation of steel area using σ_s = 115 MPa, provision of minimum reinforcement as per IS 3370
  • Part (c): Detailing showing distribution steel, vertical steel on both faces, development lengths, and proper lap splices for circular tank wall

Evaluation rubric

DimensionWeightMax marksExcellentAveragePoor
Concept correctness20%10Correctly identifies Castigliano's theorem application for (a), recognizes the two-hinge collapse mechanism for propped cantilever in (b), and applies IS 3370 provisions for circular tank with flexible base in (c); no conceptual errors in any sub-partMinor errors in theorem application or collapse mechanism identification; tank design follows correct approach but with some incorrect coefficient selection or misapplication of H²/Dt ratioFundamental misunderstanding of Castigliano's method, wrong collapse mechanism assumed, or treats tank as fixed base instead of flexible base; major conceptual gaps
Numerical accuracy20%10All calculations precise with correct unit conversions (mm to m, kN to N where needed); final deflection in mm, collapse load P in terms of Mp/l², and tank dimensions/reinforcement quantities accurately computedMinor arithmetic errors or unit conversion mistakes in one sub-part; final answers slightly off but method sound; significant figures handled reasonablyMultiple calculation errors, incorrect unit handling (e.g., mixing mm and m), or order-of-magnitude mistakes; final answers unreliable or missing
Diagram quality20%10Clear truss diagram with member lengths and load positions for (a); collapse mechanism diagram with hinge locations and rotation angles for (b); neat cross-section of tank wall showing reinforcement layout, cover, and dimensions for (c)Diagrams present but lacking clarity or missing some labels; truss geometry or collapse mechanism sketch incomplete; tank section shows reinforcement but without proper dimensioningMissing diagrams or poorly drawn sketches that hinder understanding; no attempt to illustrate collapse mechanism or reinforcement detailing
Step-by-step derivation20%10Systematic presentation: for (a) table of member forces with P, ∂P/∂Q, L, A values; for (b) clear virtual work equation with external work and internal dissipation; for (c) complete design steps from capacity to final reinforcement with all IS code referencesDerivations present but with skipped steps or missing intermediate calculations; some logical jumps that require examiner inference; tabular format for truss but incompleteDisorganized working with no clear flow; missing essential steps; no tables or systematic presentation; appears as random calculations without derivation structure
Practical interpretation20%10For (a), comments on significance of deflection magnitude for serviceability; for (b), discusses ductility requirement and practical moment redistribution; for (c), justifies bar diameter and spacing choices, mentions crack control and water-tightness provisions per IS 3370Brief mention of practical relevance in one or two sub-parts; some code references but limited insight into why specific choices were made; standard concluding remarksPurely mathematical treatment with no engineering judgment; no code references, no discussion of serviceability, durability, or constructability; answer ends with numbers only

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