Mathematics 2023 Paper II 50 marks Compulsory Solve

Q5

(a) By eliminating the arbitrary functions f and g from z = f(x² - y) + g(x² + y), form partial differential equation. (10 marks) (b) Given dy/dx = (y² - x)/(y² + x) with initial condition y = 1 at x = 0. Find the value of y for x = 0.4 by Euler's method, correct to 4 decimal places, taking step length h = 0.1. (10 marks) (c) Evaluate, using the binary arithmetic, the following numbers in their given system: (i) (634.235)₈ - (132.223)₈ (ii) (7AB.432)₁₆ - (5CA.D61)₁₆ (10 marks) (d) A planet of mass m is revolving around the sun of mass M. The kinetic energy T and the potential energy V of the planet are given by T = ½m(ṙ² + r²θ̇²) and V = GMm(1/2a - 1/r), where (r, θ) are the polar coordinates of the planet at time t, G is the gravitational constant and 2a is the major axis of the ellipse (the path of the planet). Find the Hamiltonian and the Hamilton equations of the planet's motion. (10 marks) (e) In a fluid motion, there is a source of strength 2m placed at z = 2 and two sinks of strength m are placed at z = 2 + i and z = 2 - i. Find the streamlines. (10 marks)

हिंदी में प्रश्न पढ़ें

(a) z = f(x² - y) + g(x² + y) से स्वेच्छिक फलनों f तथा g का विलोपन कर अंशिक अवकल समीकरण बनाइए। (10 अंक) (b) दिया है dy/dx = (y² - x)/(y² + x) तथा प्रारंभिक प्रतिबंध x = 0 पर y = 1 है। ऑयलर की विधि से पद लंबाई (स्टेप लैंथ) h = 0.1 लेते हुए x = 0.4 के लिए y का मान, दशमलव के 4 स्थानों तक सही, ज्ञात कीजिए। (10 अंक) (c) द्वि-आधारी अंकगणित का उपयोग कर निम्नलिखित संख्याओं का मूल्यांकन उनकी दी गई पद्धति में कीजिए: (i) (634.235)₈ - (132.223)₈ (ii) (7AB.432)₁₆ - (5CA.D61)₁₆ (10 अंक) (d) m द्रव्यमान का एक ग्रह M द्रव्यमान के सूर्य की परिक्रमा कर रहा है। ग्रह की गतिज ऊर्जा T तथा स्थितिज ऊर्जा V, T = ½m(ṙ² + r²θ̇²) तथा V = GMm(1/2a - 1/r) द्वारा दी गई हैं, जहाँ t समय पर ग्रह के ध्रुवीय निर्देशांक (r, θ) हैं, गुरुत्वीय स्थिरांक G है तथा दीर्घवृत्त (ग्रह का पथ) का दीर्घ अक्ष 2a है। ग्रह की गति के लिए हैमिल्टोनी तथा हैमिल्टन समीकरणों को ज्ञात कीजिए। (10 अंक) (e) एक तरल प्रवाह में, 2m सामर्थ्य का एक स्रोत z = 2 पर स्थित है तथा m सामर्थ्य के दो अभिगम (सिंक) z = 2 + i और z = 2 - i पर स्थित हैं। प्रवाह-रेखाएँ ज्ञात कीजिए। (10 अंक)

Directive word: Solve

This question asks you to solve. The directive word signals the depth of analysis expected, the structure of your answer, and the weight of evidence you must bring.

See our UPSC directive words guide for a full breakdown of how to respond to each command word.

How this answer will be evaluated

Approach

Solve each sub-part systematically with clear working: for (a) apply partial differentiation to eliminate arbitrary functions; for (b) execute Euler's method with 4 iterations; for (c)(i)-(ii) perform octal and hexadecimal subtraction with borrowing; for (d) construct Hamiltonian from T-V and derive canonical equations; for (e) use complex potential for source-sink superposition. Allocate approximately 15% time to (a), 20% to (b), 20% to (c), 25% to (d), and 20% to (e), ensuring all numerical answers are boxed with correct precision.

Key points expected

  • For (a): Correctly identify arguments u = x² - y and v = x² + y, compute partial derivatives p = ∂z/∂x and q = ∂z/∂y, then eliminate f' and g' to obtain PDE: x(∂z/∂x) = 2(∂z/∂y) or equivalent second-order form
  • For (b): Apply Euler's formula y_{n+1} = y_n + hf(x_n, y_n) for 4 steps (x=0 to 0.4), showing each iteration with h=0.1, final answer y(0.4) ≈ 1.4615 (to 4 decimal places)
  • For (c)(i): Perform octal subtraction (634.235)₈ - (132.223)₈ = (502.012)₈ with proper borrowing across radix point
  • For (c)(ii): Perform hexadecimal subtraction (7AB.432)₁₆ - (5CA.D61)₁₆ = (1E0.871)₁₆ handling borrow from 16's complement
  • For (d): Form Hamiltonian H = T + V = ½m(p_r²/m² + p_θ²/(m²r²)) + GMm(1/2a - 1/r), derive ṙ = ∂H/∂p_r, θ̇ = ∂H/∂p_θ, ṗ_r = -∂H/∂r, ṗ_θ = -∂H/∂θ = 0
  • For (e): Construct complex potential W = 2m ln(z-2) - m ln(z-2-i) - m ln(z-2+i), extract stream function ψ = Im(W), obtain streamline equation or implicit form

Evaluation rubric

DimensionWeightMax marksExcellentAveragePoor
Setup correctness20%10Correctly identifies all initial conditions, variable substitutions, and problem structures: proper arguments u,v for (a), Euler setup with h=0.1 for (b), radix alignment for (c), canonical momenta for (d), and source-sink locations in complex plane for (e)Most setups correct but minor errors in one sub-part: wrong step size, misaligned radix points, or incorrect canonical momentum definitionsFundamental setup errors in multiple parts: incorrect elimination approach, wrong Euler formula, confused number bases, or invalid Hamiltonian construction
Method choice20%10Selects optimal methods: Charpit's approach for PDE elimination, forward Euler for ODE, 8's/16's complement or direct borrowing for arithmetic, Legendre transform for Hamiltonian, and complex potential superposition for fluid flowMethods mostly appropriate but suboptimal: missing efficiency in arithmetic or slightly roundabout PDE eliminationInappropriate methods chosen: using Runge-Kutta instead of Euler, decimal instead of binary arithmetic, or Lagrangian instead of Hamiltonian formalism
Computation accuracy20%10All calculations precise: correct second-order PDE obtained, Euler iterations accurate to 4 decimal places (y₁=1.1000, y₂=1.1918, y₃=1.2780, y₄≈1.4615), exact octal/hexadecimal results, correct Hamilton equations, proper streamline derivationMinor computational slips: rounding errors in Euler beyond 4th decimal, single borrowing error in arithmetic, or sign error in one Hamilton equationSignificant computational errors: wrong PDE order, completely wrong Euler trajectory, multiple base conversion errors, or incorrect Hamiltonian sign
Step justification20%10Every non-trivial step explicitly justified: shows cross-multiplication for PDE elimination, displays all 4 Euler iterations with f(x,y) evaluations, writes borrow chains for subtraction, derives p_r = mṙ and p_θ = mr²θ̇, explains stream function from complex potentialMost steps shown but some gaps: missing one Euler iteration, skipping borrow details, or assuming canonical momenta without derivationMajor logical gaps: jumps from z=f+g to final PDE without working, presents only final Euler answer, or states Hamiltonian without derivation
Final answer & units20%10All answers boxed with correct precision: PDE in standard form, y(0.4)=1.4615, (502.012)₈ and (1E0.871)₁₆, four Hamilton equations clearly stated, streamline equation ψ = constant or explicit y(x) formAnswers present but format issues: missing subscripts for bases, insufficient decimal places, or implicit rather than explicit streamline formMissing or wrong final answers: no PDE stated, only intermediate Euler values, arithmetic without final result, incomplete Hamilton equations, or no streamline equation

Practice this exact question

Write your answer, then get a detailed evaluation from our AI trained on UPSC's answer-writing standards. Free first evaluation — no signup needed to start.

Evaluate my answer →

More from Mathematics 2023 Paper II