Mathematics 2024 Paper I 50 marks Solve

Q8

(a) Using Laplace transform, solve the initial value problem y'' + 2y' + 5y = δ(t-2), y(0) = 0, y'(0) = 0 where δ(t-2) denotes the Dirac delta function. (15 marks) (b) Using Gauss divergence theorem, evaluate the integral ∬_S (y²î + xz³ĵ + (z-1)²k̂) · n̂ dS over the region bounded by the cylinder x² + y² = 16 and the planes z = 1 and z = 5. (15 marks) (c) A particle moves with a central acceleration μ(3/r³ + d²/r⁵) being projected from a distance d at an angle 45° with a velocity equal to that in a circle at the same distance. Prove that the time it takes to reach the centre of force is d²/√(2μ) (2 - π/2). (20 marks)

हिंदी में प्रश्न पढ़ें

(a) लाप्लास रूपांतर का उपयोग करके प्रारंभिक मान समस्या y'' + 2y' + 5y = δ(t-2), y(0) = 0, y'(0) = 0 को हल कीजिए, जहाँ δ(t-2) डिरैक डेल्टा फलन को दर्शाता है। (15 अंक) (b) गॉस के अपसरण प्रमेय का उपयोग करते हुए बेलन x² + y² = 16 तथा समतलों z = 1 और z = 5 द्वारा परिबद्ध क्षेत्र पर समाकल ∬_S (y²î + xz³ĵ + (z-1)²k̂) · n̂ dS का मान निकालिए। (15 अंक) (c) d दूरी से एक कण को समान दूरी पर स्थित एक वृत्त में उसके वेग के बराबर वेग से 45° के कोण पर प्रक्षेपित करने पर वह केंद्रीय त्वरण μ(3/r³ + d²/r⁵) के साथ गति करता है। सिद्ध कीजिए कि बल के केंद्र तक इसके पहुँचने का समय d²/√(2μ) (2 - π/2) है। (20 अंक)

Directive word: Solve

This question asks you to solve. The directive word signals the depth of analysis expected, the structure of your answer, and the weight of evidence you must bring.

See our UPSC directive words guide for a full breakdown of how to respond to each command word.

How this answer will be evaluated

Approach

Solve all three sub-parts systematically, allocating time proportionally to marks: spend ~30% on part (a) Laplace transform problem, ~30% on part (b) Gauss divergence theorem application, and ~40% on part (c) central force motion proof. Begin each part with clear statement of given data, show complete working with proper mathematical notation, and conclude with boxed final answers. For part (c), explicitly state all mechanical assumptions and reference central force theorems used.

Key points expected

  • Part (a): Apply Laplace transform to both sides, use L{δ(t-2)} = e^(-2s), solve for Y(s) = e^(-2s)/(s²+2s+5), complete the square to get e^(-2s)/[(s+1)²+4], then apply inverse transform with shift theorem to obtain y(t) = (1/2)e^(-(t-2))sin[2(t-2)]·H(t-2)
  • Part (b): Identify divergence of F = ∂(y²)/∂x + ∂(xz³)/∂y + ∂(z-1)²/∂z = 0 + 0 + 2(z-1) = 2(z-1), set up cylindrical coordinates with r: 0-4, θ: 0-2π, z: 1-5, evaluate ∫∫∫ 2(z-1) r dr dθ dz = 2 × 2π × 8 × 8 = 256π
  • Part (c): Verify initial conditions satisfy circular orbit velocity v² = μ(3/d² + 1/d²) = 4μ/d², use energy equation and angular momentum conservation, substitute u = 1/r to get differential equation, integrate with proper limits from r=d to r=0, show time integral yields d²/√(2μ) [arccos(0) - arccos(1/√2)] = d²/√(2μ)(2 - π/2)
  • Correct handling of Dirac delta function properties and Heaviside step function in part (a)
  • Proper application of divergence theorem with closed surface orientation and volume element in cylindrical coordinates for part (b)
  • Clear derivation of orbital equation and time integral transformation using substitution u = 1/r for part (c)

Evaluation rubric

DimensionWeightMax marksExcellentAveragePoor
Setup correctness20%10Correctly writes initial conditions for (a), identifies cylinder radius 4 and z-limits for (b), and establishes central force parameters with proper velocity condition for circular orbit in (c); all coordinate systems and variable substitutions are explicitly definedMost setups are correct but may miss one initial condition in (a), confuse cylinder dimensions in (b), or state velocity condition without derivation in (c)Major errors in problem setup such as wrong Laplace transform of delta function, incorrect divergence calculation, or fundamental misunderstanding of central force motion setup
Method choice20%10Selects standard Laplace transform method with shift theorem for (a), applies Gauss divergence theorem correctly converting surface to volume integral for (b), and uses Binet's equation or equivalent energy-angular momentum approach with u=1/r substitution for (c)Correct general methods but may use less efficient approaches or miss optimal substitutions, such as direct integration without shift theorem or Cartesian instead of cylindrical coordinatesWrong method selection such as undetermined coefficients for (a), direct surface integration ignoring divergence theorem for (b), or attempting Cartesian coordinates for central force in (c)
Computation accuracy20%10Flawless algebraic manipulation including completing the square (s+1)²+4, accurate triple integration yielding 256π, and correct evaluation of inverse trigonometric integrals with precise limits; all arithmetic steps shownMinor computational errors such as sign errors in completing the square, arithmetic mistakes in integration bounds, or coefficient errors in final time expression that don't affect method validitySerious computational errors including wrong partial fraction decomposition, incorrect volume element (missing r in cylindrical), or fundamental errors in evaluating the time integral leading to wrong functional form
Step justification20%10Explicitly justifies each key step: shift theorem application with delay justification, divergence calculation showing zero partials, cylindrical coordinate transformation with Jacobian; for (c) proves velocity equals circular orbit speed and justifies the u-substitution with differential relationshipShows most steps but may omit justification for standard results like L{δ(t-a)} or assume divergence theorem applicability without verifying closed surface; logical flow present but gaps existMissing critical justifications such as no mention of Heaviside function emergence, unexplained coordinate changes, or assertion of results without derivation; logical gaps between steps
Final answer & units20%10Presents all three final answers in clean boxed form: y(t) = (1/2)e^(2-t)sin[2(t-2)]H(t-2) or equivalent, 256π for (b), and exactly d²/√(2μ)(2-π/2) for (c); dimensions verified consistent (time, pure number, time respectively)Correct functional forms but with minor errors in coefficients, or correct numerical answers without proper presentation; units implied but not explicitly checkedWrong final answers, missing components like Heaviside function, incorrect numerical values, or answers without any dimensional verification; incomplete or illegible final results

Practice this exact question

Write your answer, then get a detailed evaluation from our AI trained on UPSC's answer-writing standards. Free first evaluation — no signup needed to start.

Evaluate my answer →

More from Mathematics 2024 Paper I