Mathematics 2024 Paper II 50 marks Solve

Paper II — Q3

(a) Locate the poles and their order for the function f(z) = 1/[z(sin πz)(z + 1/2)]. Also, find the residue of f(z) at these…

(a)

Locate the poles and their order for the function f(z) = 1/[z(sin πz)(z + 1/2)]. Also, find the residue of f(z) at these poles. 15 marks

(b)

Consider the series Σ(n=1 to ∞) U_n(x), 0 ≤ x ≤ 1, the sum of whose first n terms is given by S_n(x) = (1/2n²)log(1 + n⁴x²), x ∈ [0,1]. Show that the given series can be differentiated term-by-term, though Σ(n=1 to ∞) U'_n(x), does not converge uniformly on [0,1]. 20 marks

(c)

Using duality principle, solve the following linear programming problem: Minimize z = 4x₁ + 3x₂ + x₃ subject to x₁ + 2x₂ + 4x₃ ≥ 12, 3x₁ + 2x₂ + x₃ ≥ 8, x₁, x₂, x₃ ≥ 0. 15 marks

हिंदी में प्रश्न पढ़ें
(a)

फलन f(z) = 1/[z(sin πz)(z + 1/2)] के अनंतक तथा उनकी घात (ऑर्डर) का पता लगाइए। इन अनंतकों पर f(z) के अवशेष भी ज्ञात कीजिए। (15 अंक)

(b)

श्रेणी Σ(n=1 to ∞) U_n(x), 0 ≤ x ≤ 1 का विचार कीजिए, जिसके पहले n पदों का योगफल S_n(x) = (1/2n²)log(1 + n⁴x²), x ∈ [0,1] के द्वारा दिया गया है। दर्शाइए कि दी गई श्रेणी को पद-दर-पद अवकलित किया जा सकता है, यद्यपि Σ(n=1 to ∞) U'_n(x), [0,1] पर एकसमान अभिसरित नहीं होती है। (20 अंक)

(c)

द्वैत सिद्धांत का उपयोग करते हुए, निम्नलिखित रैखिक प्रोग्रामन समस्या को हल कीजिए: न्यूनतमीकरण कीजिए z = 4x₁ + 3x₂ + x₃ बशर्ते कि x₁ + 2x₂ + 4x₃ ≥ 12, 3x₁ + 2x₂ + x₃ ≥ 8, x₁, x₂, x₃ ≥ 0। (15 अंक)

Q3 of the 2024 UPSC Mains Mathematics Paper II, as printed
The question as printed in the 2024 Mathematics paper

Model answer

Written by UPSC Answer Check against this question's marking rubric, to the expected length. UPSC does not publish answers for Mains — this is one way to score well, not an official key.

(a) The poles are zeros of the denominator z(sin πz)(z + 1/2).

  • At z = 0: z has a simple zero and sin πz has a simple zero, while z + 1/2 ≠ 0. Hence the denominator has a zero of order 2, so f has a pole of order 2 at z = 0.
  • At z = n, where n is an integer and n ≠ 0: sin πz has a simple zero, while n ≠ 0 and n + 1/2 ≠ 0. Hence f has a simple pole at each z = n, n ∈ ℤ, n ≠ 0.
  • At z = −1/2: z + 1/2 has a simple zero, while z = −1/2 ≠ 0 and sin(−π/2) = −1 ≠ 0. Hence f has a simple pole at z = −1/2.

Residues:

For a simple pole at z = n, n ∈ ℤ, n ≠ 0, Res(f, n) = lim(z→n) (z − n) f(z) = 1/[n(n + 1/2)] · lim(z→n) (z − n)/sin πz. Since sin πz ≈ (−1)ⁿ π(z − n) near z = n, lim(z→n) (z − n)/sin πz = (−1)ⁿ/π. Thus Res(f, n) = (−1)ⁿ/[π n(n + 1/2)] = 2(−1)ⁿ/[π n(2n + 1)], n ∈ ℤ, n ≠ 0.

At z = −1/2, Res(f, −1/2) = lim(z→−1/2) (z + 1/2) f(z) = 1/[z sin πz] at z = −1/2 = 1/[(-1/2)(−1)] = 2.

At z = 0, let h(z) = (z + 1/2) sin πz. Near z = 0, sin πz = πz − π³z³/6 + …, so h(z) = (z + 1/2)(πz − π³z³/6 + …) = (π/2)z + πz² + … . Therefore 1/h(z) = 2/(πz) − 4/π + …, and f(z) = 1/[z h(z)] = 2/(π z²) − 4/(π z) + … . Hence Res(f, 0) = −4/π.

(b) Let Sₙ(x) = 1/(2n²) log(1 + n⁴x²), x ∈ [0, 1]. Then U₁ = S₁ and for n ≥ 2, Uₙ = Sₙ − Sₙ₋₁, with S₀ = 0.

First find the sum of the given series. For fixed x, if x = 0, Sₙ(x) = 0. If x > 0, Sₙ(x) = 1/(2n²) log(1 + n⁴x²) = 1/(2n²)[4 log n + 2 log x + o(1)] → 0. Also for 0 ≤ x ≤ 1, 0 ≤ Sₙ(x) ≤ log(1 + n⁴)/(2n²) → 0. Thus the series converges uniformly to f(x) = 0 on [0, 1].

Now differentiate Sₙ: Sₙ′(x) = 1/(2n²) · (2n⁴x)/(1 + n⁴x²) = n²x/(1 + n⁴x²).

Therefore U₁′(x) = S₁′(x) = x/(1 + x²), and for n ≥ 2, Uₙ′(x) = Sₙ′(x) − Sₙ₋₁′(x).

The partial sum of the derivative series is Σ(k=1 to N) Uₖ′(x) = S_N′(x) = N²x/(1 + N⁴x²).

For fixed x ≥ 0, if x = 0, S_N′(0) = 0; if x > 0, S_N′(x) ∼ 1/(N²x) → 0. Hence Σ(n=1 to ∞) Uₙ′(x) = 0 = f′(x). So the given series can be differentiated term-by-term on [0, 1].

However, the convergence of Σ Uₙ′(x) is not uniform. Its N-th remainder is 0 − S_N′(x) = − N²x/(1 + N⁴x²). The maximum of N²x/(1 + N⁴x²) on [0, 1] occurs at x = 1/N², and equals (N² · 1/N²)/(1 + 1) = 1/2. Thus sup(0 ≤ x ≤ 1) |remainder| = 1/2, which does not tend to 0 as N → ∞. Therefore Σ Uₙ′(x) does not converge uniformly on [0, 1], although term-by-term differentiation still holds here.

(c) Primal problem: Minimize z = 4x₁ + 3x₂ + x₃ subject to x₁ + 2x₂ + 4x₃ ≥ 12, 3x₁ + 2x₂ + x₃ ≥ 8, x₁, x₂, x₃ ≥ 0.

Using duality, the dual is: Maximize w = 12y₁ + 8y₂ subject to y₁ + 3y₂ ≤ 4, 2y₁ + 2y₂ ≤ 3, 4y₁ + y₂ ≤ 1, y₁, y₂ ≥ 0.

From 4y₁ + y₂ ≤ 1 and y₁ ≥ 0, w = 12y₁ + 8y₂ = 8(4y₁ + y₂) − 20y₁ ≤ 8 · 1 − 0 = 8. Equality holds when y₁ = 0 and 4y₁ + y₂ = 1, so y₂ = 1. This point satisfies all dual constraints. Hence the dual optimum is **w* = 8 at (y₁, y₂) = (0, 1)**.

By the duality principle, the primal optimum is also **z* = 8**.

Use complementary slackness. Since y₂ = 1 > 0, the second primal constraint is tight: 3x₁ + 2x₂ + x₃ = 8. At (y₁, y₂) = (0, 1), the dual constraints for x₁ and x₂ are y₁ + 3y₂ = 3 < 4, 2y₁ + 2y₂ = 2 < 3. Hence x₁ = 0 and x₂ = 0. Then from the tight second constraint, x₃ = 8. The first primal constraint gives 4x₃ = 32 ≥ 12, so it is satisfied.

Therefore the optimal primal solution is (x₁, x₂, x₃) = (0, 0, 8), and the minimum value is z_min = 8.

What "Solve" is asking you to do

Choose the method, then carry it through to a final answer. Identifying what kind of problem this is and why that method applies is the first thing marked; a correct figure arrived at invisibly earns almost nothing.

Structure that answers it

Given data and what is required → method chosen, with the reason it applies → set-up (equation, circuit, free body, trial balance) → working, step by step → answer with units and any condition of validity

Where marks are lost

Doing the middle steps mentally and writing only the result. In mathematics papers, a further loss comes from giving a decimal where the exact value in surds or fractions was wanted, or from skipping the justification a part explicitly asks for.

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How this answer will be evaluated

Approach

(a) calculate: given > formula > substitution > result with units > interpretation | (b) justify: claim > 3-4 reasons > evidence > conclusion | (c) calculate: given > formula > substitution > result with units > interpretation Full marks: Complete derivations, correct theorems cited, all parts solved with verification.

Key points expected

  • Identify poles at z=0, z=n (integers), z=-1/2
  • Determine order of each pole (simple)
  • Calculate residue at z=0
  • Calculate residue at z=-1/2
  • Derive U_n(x) from S_n(x) - S_{n-1}(x)
  • Show S_n(x) converges uniformly on [0,1]
  • Show U_n'(x) converges pointwise
  • Prove sum of U_n'(x) is not uniformly convergent

Evaluation rubric

Each sub-part is marked on its own, against the marks and word limit printed on the paper.

  1. (a) Identify poles, their orders, and calculate residues for f(z). 15 marks

    calculate— given → formula → substitution → result with units → interpretation

    Must cover

    • Identify poles at z=0, z=n (integers), z=-1/2
    • Determine order of each pole (simple)
    • Calculate residue at z=0
    • Calculate residue at z=-1/2

    Loses marks

    • Missing any pole location
    • Incorrect order of poles
    • Calculation error in residue formula

    Earns more

    • Calculate residue at general integer pole z=n
    • Use limit definition for residues
    • Verify residue sum is zero (if applicable)

    Extra mark

    • Mention Riemann sphere pole at infinity
  2. (b) Prove term-by-term differentiability and non-uniform convergence of derivative series. 20 marks

    justify— claim → 3-4 reasons → evidence → conclusion

    Must cover

    • Derive U_n(x) from S_n(x) - S_{n-1}(x)
    • Show S_n(x) converges uniformly on [0,1]
    • Show U_n'(x) converges pointwise
    • Prove sum of U_n'(x) is not uniformly convergent

    Loses marks

    • Failing to derive U_n(x) explicitly
    • Assuming uniform convergence without proof
    • Incorrect differentiation of log term

    Earns more

    • State Weierstrass M-test or relevant theorem
    • Explicitly calculate limit of U_n'(x)
    • Show sup norm of remainder does not vanish

    Extra mark

    • Provide a specific counter-example for non-uniformity
  3. (c) Solve the minimization LPP using the duality principle. 15 marks

    calculate— given → formula → substitution → result with units → interpretation

    Must cover

    • Formulate the dual maximization problem
    • Solve the dual problem (e.g., via simplex)
    • Identify optimal values of dual variables
    • State the minimum value of z

    Loses marks

    • Incorrect formulation of the dual
    • Solving the primal directly instead of dual
    • Arithmetic errors in simplex iterations

    Earns more

    • Show the simplex table for the dual
    • Verify complementary slackness conditions
    • State the optimal values of x1, x2, x3

    Extra mark

    • Graphical verification of the solution

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