Paper II — Q6
(a) (i) How does the mixture combustion in the combustion chamber of a C.I. engine differ from that of an S.I. engine? (ii) What…
How does the mixture combustion in the combustion chamber of a C.I. engine differ from that of an S.I. engine? (ii) What is meant by combustion induced swirl? Show with sketches two important designs of C.I. combustion chamber using this method of swirl. 20 marks
In a single-heater regenerative cycle the steam enters the turbine at 30 bar, 400°C and the exhaust pressure is 0·1 bar. The feed water heater is a direct-contact type which operates at 0·3 MPa. Find the efficiency of the cycle neglecting pump work. (At 30 bar, 400°C: h = 3230·9 kJ/kg and s = 6·9212 kJ/kg K. Also use steam tables given towards the end of booklet for steam/water properties). 20 marks
A moist air sample has dry bulb temperature of 30°C and specific humidity of 11·5 gm of water vapour per kg dry air. If the saturation vapour pressure of water at 30°C is 4·24 kPa and the total pressure is 90 kPa then what is the relative humidity of the air sample? 10 marks
हिंदी में प्रश्न पढ़ें
एक C.I. इंजन के दहन-कक्ष में मिश्रण दहन, S.I. इंजन से किस प्रकार भिन्न होता है? (ii) दहन प्रेरित भंवर से क्या तात्पर्य है? रेखाचित्रों के साथ C.I. दहन कक्ष के दो महत्वपूर्ण अभिकल्पों को दिखाइए जिसमें भंवर की इस पद्धति का उपयोग होता है। (20 अंक)
एक एकल तापक पुनर्जीवी चक्र में भाप 30 bar, 400°C पर टरबाइन में प्रवेश करती है और रेचक दबाव 0·1 bar है। प्रभरण जल तापक एक प्रत्यक्ष संपर्क प्रकार का है जो 0·3 MPa पर संचालित होता है। पंप कार्य की उपेक्षा करते हुए चक्र की दक्षता ज्ञात करें। (30 bar, 400°C पर: h = 3230·9 kJ/kg और s = 6·9212 kJ/kg K है। भाप/पानी के गुणों के लिए पुस्तिका के अंत में संलग्न भाप तालिका का भी प्रयोग करें)। (20 अंक)
एक नम हवा के नमूने का शुष्क बल्ब तापमान 30°C और विशिष्ट आर्द्रता 11·5 ग्राम जल वाष्प प्रति किलोग्राम शुष्क वायु है। यदि 30°C पर पानी का संतृप्त वाष्प दाब 4·24 kPa और कुल दाब 90 kPa है, तो वायु (हवा) के नमूने की सापेक्ष-आर्द्रता क्या है। (10 अंक)
Model answer
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(a) CI versus SI combustion, and combustion-induced swirl
(i) In an SI engine, a homogeneous air–fuel mixture is compressed and ignited by a spark. A premixed flame front spreads from the plug, and its speed depends on mixture strength, turbulence and temperature. In a CI engine only air is compressed; fuel is injected near the end of compression and autoignites after an ignition delay in the hot air. The charge is heterogeneous: part of the fuel burns quickly in the premixed phase, but most burns by diffusion, controlled by how fast air mixes with fuel. CI combustion is therefore mixing-controlled, with no flame propagating through a uniform charge, and the chamber must create strong air motion.
(ii) Combustion-induced swirl is turbulence generated by the combustion itself. Part of the fuel burns in a small auxiliary chamber, its pressure rises, and the burning gases are forced at high speed through a narrow passage into the main chamber, where they mix with the remaining air and fuel. This shortens the delay and completes combustion.
Two designs use this method:
- Pre-combustion chamber: a small chamber of about 20–30% of the clearance volume sits above the piston and connects to the main chamber by one or more narrow passages. Fuel is injected into it, partially burns, and the pressure rise blows the rich burning mixture into the main chamber, where it burns with the remaining air.
- Air-cell (energy-cell, Lanova type): a small cell lies opposite the injector, joined to the main chamber by a narrow throat. During compression, air enters the cell; after injection, burning in the cell raises its pressure and drives a violent jet of burning gas back into the main chamber.
Both give good mixing and a smooth, rapid burn, at the cost of heat loss through the passage, a higher compression ratio for starting, and poorer fuel economy than direct injection. The sketches below show both designs.
(b) Single-heater regenerative cycle
State 1: 30 bar, 400°C, h₁ = 3230.9 kJ/kg, s₁ = 6.9212 kJ/kg K. No turbine efficiency is given, so the expansion is isentropic.
Bleed at 0.3 MPa: s = s₁ gives x₂ = (6.9212 − 1.672)/(6.992 − 1.672) = 0.987 and h₂ = 561.4 + 0.987 × 2163.8 ≈ 2697 kJ/kg.
Exhaust at 0.1 bar: x₃ = (6.9212 − 0.649)/(8.150 − 0.649) = 0.836 and h₃ = 191.8 + 0.836 × 2392.8 ≈ 2192.5 kJ/kg.
In the direct-contact heater, y h₂ + (1 − y)h_f(0.1 bar) = h_f(0.3 MPa) = 561.4, so
y = (561.4 − 191.8)/(2697 − 191.8) = 0.1475 kg of steam bled per kg.
Neglecting pump work, the turbine work is w = (h₁ − h₂) + (1 − y)(h₂ − h₃) = 534 + 0.8525 × 504.5 = 964 kJ/kg. The heat supplied is q = h₁ − h_f(0.3 MPa) = 3230.9 − 561.4 = 2669.5 kJ/kg.
Cycle efficiency η = 964/2669.5 = 36.1%.
(c) Relative humidity
ω = 0.0115 kg/kg, and ω = 0.622p_v/(p − p_v) gives
p_v = ωp/(0.622 + ω) = 0.0115 × 90/0.6335 = 1.634 kPa.
φ = p_v/p_s = 1.634/4.24 = 0.385, that is, about 38.5%.
How this answer will be evaluated
What earns full marks: Complete derivations, labelled diagrams, and physical interpretation of results.
Evaluation rubric
Each sub-part is marked on its own, against the marks and word limit printed on the paper.
- (a) Distinguish CI from SI combustion and explain combustion-induced swirl with two chamber designs 20 marks
compare— paired headings or point-wise contrast → key differences → significance → conclusion
Must cover
- SI: premixed flame propagation, CI: autoignition with mixing-controlled diffusion burning
- Combustion-induced swirl produced by burning gases forced through a narrow passage
- Two chamber designs such as pre-combustion chamber and air cell, with sketches
Loses marks
- Confusing compression swirl with combustion-induced swirl
- Describing only one chamber
Earns more
- Ignition delay and premixed/diffusion phases mentioned
- How each design creates the swirl
- Merits and limits of the designs
Extra mark
- Compares with compression-induced swirl or direct injection
- (b) Find the efficiency of the single-heater regenerative cycle neglecting pump work 20 marks
calculate— given → formula → substitution → result with units → interpretation
Must cover
- Isentropic expansion to 0.3 MPa and to 0.1 bar with dryness fractions 0.987 and 0.836
- Bled fraction y ≈ 0.1475 from the heater balance
- Efficiency ≈ 36.1%
Loses marks
- Not reducing the mass after bleeding
- Heat supplied taken from the condensate enthalpy at 0.1 bar
Earns more
- h₂ ≈ 2697 and h₃ ≈ 2192.5 kJ/kg from steam tables
- Work (1 − y) term correct
Extra mark
- Compares with the Rankine efficiency without regeneration
- (c) Find the relative humidity of the moist air sample 10 marks
calculate— given → formula → substitution → result with units → interpretation
Must cover
- p_v = ωp/(0.622 + ω) = 1.634 kPa
- Relative humidity = p_v/p_s
- φ ≈ 38.5%
Loses marks
- Using 101.3 kPa as total pressure
- Leaving ω in g/kg in the formula
Earns more
- Specific humidity converted to kg/kg
- Total pressure 90 kPa used
Extra mark
- Distinguishes relative humidity from percentage saturation
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Structure that answers it
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Where marks are lost
Describing what something looks like instead of why it works that way. Naming the stages without linking them reads as description too.
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