Physics 2021 Paper I 50 marks Calculate

Q8

(a) (i) The melting point of tin is 232°C, its latent heat of fusion is 14 cal/g and the specific heat of solid and molten tin are 0·055 and 0·064 cal/g °C respectively. Calculate the change in entropy when 1·0 gm of tin is heated from 100°C to 300°C. (ii) Calculate the efficiency of an engine having compression ratio 13·8 and expansion ratio 6 and working on diesel cycle. Given γ = 1·4. (10+5 marks) (b) (i) Write the expression for the Fermi-Dirac distribution. Plot the Fermi-Dirac distribution at T = 0 and for T₁ > T₂ > 0. Now from the plot propose two alternative definitions of the Fermi level. (ii) Calculate the probability of an electron occupying an energy level 0·02 eV above the Fermi level at T = 300 K. (15+5 marks) (c) Given an infinite line charge of charge density 2 nCm⁻¹ parallel to the y-axis and passing through the point (3, 0, 4) m and an infinite sheet of charge of charge density 4 nCm⁻² parallel to the x-y plane and passing through the point (0, 0, 6) m. Calculate the electric field intensity at the point (10, 10, 10) m. Assume free space. (15 marks)

हिंदी में प्रश्न पढ़ें

(a) (i) टिन का गलनांक 232°C है, इसके संगलन की गुप्त ऊष्मा 14 cal/g है और ठोस टिन और गलित टिन की विशिष्ट ऊष्मा क्रमशः 0·055 और 0·064 cal/g °C हैं । 1·0 gm टिन को 100°C से 300°C तक गर्म करने में एन्ट्रॉपी में हुए परिवर्तन की गणना कीजिए । (ii) एक इंजन की दक्षता की गणना कीजिए जिसका संपीडन अनुपात 13·8 है तथा प्रसार अनुपात 6 है । यह इंजन डीजल साइकिल पर काम करता है । दिया गया है γ = 1·4. (10+5 अंक) (b) (i) फर्मी-डिराक वितरण के लिए व्यंजक लिखिए । T = 0 और T₁ > T₂ > 0 के लिए फर्मी-डिराक वितरण को आरेखित कीजिए । इस आरेखण से फर्मी स्तर की दो विकल्पित परिभाषाएँ प्रस्तावित कीजिए । (ii) T = 300 K पर एक इलेक्ट्रॉन को फर्मी स्तर से 0·02 eV ऊपर ऊर्जा स्तर पर पाए जाने की प्रायिकता की गणना कीजिए । (15+5 अंक) (c) y-अक्ष के समांतर तथा बिंदु (3, 0, 4) m से जाने वाले एक अपरिमित रेखीय आवेश का आवेश घनत्व 2 nCm⁻¹ है तथा x-y तल के समांतर एवं बिंदु (0, 0, 6) m से जाने वाले एक अपरिमित आवेश तल (शीट) का आवेश घनत्व 4 nCm⁻² है । बिंदु (10, 10, 10) m पर वैद्युत क्षेत्र की तीव्रता की गणना कीजिए । मुक्त आकाश की स्थिति मान लीजिए । (15 अंक)

Directive word: Calculate

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How this answer will be evaluated

Approach

This is a multi-part numerical problem demanding precise calculation across thermodynamics, statistical mechanics and electrostatics. Allocate approximately 30% time to part (a) covering entropy change and diesel cycle efficiency, 40% to part (b) on Fermi-Dirac distribution with its conceptual plots and probability calculation, and 30% to part (c) on vector superposition of electric fields from line and sheet charges. Begin each part with stated assumptions and relevant formulas, show step-by-step calculations with proper units, and conclude with physical interpretation of results.

Key points expected

  • For (a)(i): Calculate entropy change in three stages—heating solid tin from 100°C to 232°C, phase change at 232°C, and heating liquid tin from 232°C to 300°C using ΔS = ∫dQ/T and ΔS = mL/T
  • For (a)(ii): Apply diesel cycle efficiency formula η = 1 - (1/γ)[(ρ^γ - 1)/(r^(γ-1)(ρ - 1))] where r = compression ratio, ρ = cutoff ratio = r/r_expansion = 13.8/6
  • For (b)(i): State Fermi-Dirac distribution f(E) = 1/[exp((E-E_F)/k_BT) + 1], sketch three curves showing step function at T=0 and thermal broadening at T₁ > T₂ > 0, define Fermi level as E where f(E)=0.5 or as chemical potential
  • For (b)(ii): Calculate f(E_F + 0.02 eV) using given values, showing substitution of k_BT at 300K ≈ 0.0259 eV
  • For (c): Calculate electric field from infinite line charge E_line = λ/(2πε₀r) perpendicular to line, and from sheet E_sheet = σ/(2ε₀) perpendicular to sheet, then vectorially sum at point (10,10,10)m with proper distance calculations

Evaluation rubric

DimensionWeightMax marksExcellentAveragePoor
Concept correctness20%10Correctly identifies all thermodynamic processes in (a), states Fermi-Dirac distribution with quantum mechanical basis in (b), and applies superposition principle with correct field directions in (c); no conceptual errors in any sub-partMinor errors in identifying process stages or field directions; correct formulas but muddled physical reasoning in one sub-partFundamental misconceptions such as treating entropy as state function incorrectly, confusing Fermi-Dirac with Maxwell-Boltzmann, or adding fields as scalars in (c)
Derivation rigour20%10Shows complete step-by-step derivations for entropy integrals, diesel cycle efficiency formula manipulation, and vector field components with clear algebraic steps; justifies all approximationsSkips intermediate steps or assumes results without derivation in one sub-part; mostly correct but with gaps in logical flowMissing derivations, jumps to final formulas without setup, or contains algebraic errors in key steps like cutoff ratio calculation
Diagram / FBD15%7.5Accurate Fermi-Dirac plots in (b)(i) showing T=0 step function, thermal smearing at finite T with T₁ > T₂ > 0 clearly distinguished, labeled axes (E/E_F vs f(E)), and E_F marked; diesel cycle P-V diagram optional but helpfulRough sketches with correct qualitative features but poor scaling or missing labels; omits one temperature curveMissing plots, incorrect curves (e.g., Maxwell-Boltzmann shape), or unlabeled axes making interpretation impossible
Numerical accuracy30%15Precise calculations: entropy change ≈ 0.042 cal/K (or 0.176 J/K), diesel efficiency ≈ 56-58%, probability ≈ 0.24, field magnitude ≈ 45-47 V/m with correct vector components; proper unit conversions throughoutCorrect method but arithmetic errors or wrong unit conversions (e.g., °C vs K in entropy, nm vs m in distances); final answers within 10-20% of correct valueOrder-of-magnitude errors, wrong formulas applied numerically, or missing units; demonstrates poor calculation discipline
Physical interpretation15%7.5Interprets entropy increase as irreversibility and disorder growth in phase change; explains why diesel efficiency exceeds Otto cycle; discusses how Fermi level shifts with temperature in real materials; validates field direction geometricallyBrief concluding statements without deep insight; mentions physical meaning but doesn't connect to broader principlesPurely mathematical treatment with no physical insight; fails to interpret what calculated values signify

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