Q8
(a) (i) The melting point of tin is 232°C, its latent heat of fusion is 14 cal/g and the specific heat of solid and molten tin are 0·055 and 0·064 cal/g °C respectively. Calculate the change in entropy when 1·0 gm of tin is heated from 100°C to 300°C. (ii) Calculate the efficiency of an engine having compression ratio 13·8 and expansion ratio 6 and working on diesel cycle. Given γ = 1·4. (10+5 marks) (b) (i) Write the expression for the Fermi-Dirac distribution. Plot the Fermi-Dirac distribution at T = 0 and for T₁ > T₂ > 0. Now from the plot propose two alternative definitions of the Fermi level. (ii) Calculate the probability of an electron occupying an energy level 0·02 eV above the Fermi level at T = 300 K. (15+5 marks) (c) Given an infinite line charge of charge density 2 nCm⁻¹ parallel to the y-axis and passing through the point (3, 0, 4) m and an infinite sheet of charge of charge density 4 nCm⁻² parallel to the x-y plane and passing through the point (0, 0, 6) m. Calculate the electric field intensity at the point (10, 10, 10) m. Assume free space. (15 marks)
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(a) (i) टिन का गलनांक 232°C है, इसके संगलन की गुप्त ऊष्मा 14 cal/g है और ठोस टिन और गलित टिन की विशिष्ट ऊष्मा क्रमशः 0·055 और 0·064 cal/g °C हैं । 1·0 gm टिन को 100°C से 300°C तक गर्म करने में एन्ट्रॉपी में हुए परिवर्तन की गणना कीजिए । (ii) एक इंजन की दक्षता की गणना कीजिए जिसका संपीडन अनुपात 13·8 है तथा प्रसार अनुपात 6 है । यह इंजन डीजल साइकिल पर काम करता है । दिया गया है γ = 1·4. (10+5 अंक) (b) (i) फर्मी-डिराक वितरण के लिए व्यंजक लिखिए । T = 0 और T₁ > T₂ > 0 के लिए फर्मी-डिराक वितरण को आरेखित कीजिए । इस आरेखण से फर्मी स्तर की दो विकल्पित परिभाषाएँ प्रस्तावित कीजिए । (ii) T = 300 K पर एक इलेक्ट्रॉन को फर्मी स्तर से 0·02 eV ऊपर ऊर्जा स्तर पर पाए जाने की प्रायिकता की गणना कीजिए । (15+5 अंक) (c) y-अक्ष के समांतर तथा बिंदु (3, 0, 4) m से जाने वाले एक अपरिमित रेखीय आवेश का आवेश घनत्व 2 nCm⁻¹ है तथा x-y तल के समांतर एवं बिंदु (0, 0, 6) m से जाने वाले एक अपरिमित आवेश तल (शीट) का आवेश घनत्व 4 nCm⁻² है । बिंदु (10, 10, 10) m पर वैद्युत क्षेत्र की तीव्रता की गणना कीजिए । मुक्त आकाश की स्थिति मान लीजिए । (15 अंक)
Directive word: Calculate
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How this answer will be evaluated
Approach
This is a multi-part numerical problem demanding precise calculation across thermodynamics, statistical mechanics and electrostatics. Allocate approximately 30% time to part (a) covering entropy change and diesel cycle efficiency, 40% to part (b) on Fermi-Dirac distribution with its conceptual plots and probability calculation, and 30% to part (c) on vector superposition of electric fields from line and sheet charges. Begin each part with stated assumptions and relevant formulas, show step-by-step calculations with proper units, and conclude with physical interpretation of results.
Key points expected
- For (a)(i): Calculate entropy change in three stages—heating solid tin from 100°C to 232°C, phase change at 232°C, and heating liquid tin from 232°C to 300°C using ΔS = ∫dQ/T and ΔS = mL/T
- For (a)(ii): Apply diesel cycle efficiency formula η = 1 - (1/γ)[(ρ^γ - 1)/(r^(γ-1)(ρ - 1))] where r = compression ratio, ρ = cutoff ratio = r/r_expansion = 13.8/6
- For (b)(i): State Fermi-Dirac distribution f(E) = 1/[exp((E-E_F)/k_BT) + 1], sketch three curves showing step function at T=0 and thermal broadening at T₁ > T₂ > 0, define Fermi level as E where f(E)=0.5 or as chemical potential
- For (b)(ii): Calculate f(E_F + 0.02 eV) using given values, showing substitution of k_BT at 300K ≈ 0.0259 eV
- For (c): Calculate electric field from infinite line charge E_line = λ/(2πε₀r) perpendicular to line, and from sheet E_sheet = σ/(2ε₀) perpendicular to sheet, then vectorially sum at point (10,10,10)m with proper distance calculations
Evaluation rubric
| Dimension | Weight | Max marks | Excellent | Average | Poor |
|---|---|---|---|---|---|
| Concept correctness | 20% | 10 | Correctly identifies all thermodynamic processes in (a), states Fermi-Dirac distribution with quantum mechanical basis in (b), and applies superposition principle with correct field directions in (c); no conceptual errors in any sub-part | Minor errors in identifying process stages or field directions; correct formulas but muddled physical reasoning in one sub-part | Fundamental misconceptions such as treating entropy as state function incorrectly, confusing Fermi-Dirac with Maxwell-Boltzmann, or adding fields as scalars in (c) |
| Derivation rigour | 20% | 10 | Shows complete step-by-step derivations for entropy integrals, diesel cycle efficiency formula manipulation, and vector field components with clear algebraic steps; justifies all approximations | Skips intermediate steps or assumes results without derivation in one sub-part; mostly correct but with gaps in logical flow | Missing derivations, jumps to final formulas without setup, or contains algebraic errors in key steps like cutoff ratio calculation |
| Diagram / FBD | 15% | 7.5 | Accurate Fermi-Dirac plots in (b)(i) showing T=0 step function, thermal smearing at finite T with T₁ > T₂ > 0 clearly distinguished, labeled axes (E/E_F vs f(E)), and E_F marked; diesel cycle P-V diagram optional but helpful | Rough sketches with correct qualitative features but poor scaling or missing labels; omits one temperature curve | Missing plots, incorrect curves (e.g., Maxwell-Boltzmann shape), or unlabeled axes making interpretation impossible |
| Numerical accuracy | 30% | 15 | Precise calculations: entropy change ≈ 0.042 cal/K (or 0.176 J/K), diesel efficiency ≈ 56-58%, probability ≈ 0.24, field magnitude ≈ 45-47 V/m with correct vector components; proper unit conversions throughout | Correct method but arithmetic errors or wrong unit conversions (e.g., °C vs K in entropy, nm vs m in distances); final answers within 10-20% of correct value | Order-of-magnitude errors, wrong formulas applied numerically, or missing units; demonstrates poor calculation discipline |
| Physical interpretation | 15% | 7.5 | Interprets entropy increase as irreversibility and disorder growth in phase change; explains why diesel efficiency exceeds Otto cycle; discusses how Fermi level shifts with temperature in real materials; validates field direction geometrically | Brief concluding statements without deep insight; mentions physical meaning but doesn't connect to broader principles | Purely mathematical treatment with no physical insight; fails to interpret what calculated values signify |
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