Physics 2021 Paper II 50 marks Compulsory Solve

Paper II — Q5

(a) An X-ray beam of wavelength (λ₁) undergoes a first order Bragg reflection at a Bragg angle of 30°. X-ray of wavelength 97 nm…

(a)

An X-ray beam of wavelength (λ₁) undergoes a first order Bragg reflection at a Bragg angle of 30°. X-ray of wavelength 97 nm undergoes 3rd order reflection at a Bragg angle of 60°. Consider that the two beams are reflected from the same set of planes. Find the value of λ₁. 10 marks

(b)

Using the expression for internal energy U=3N(ℏω)/(e^ℏω/k_BT-1), show that Einstein specific heat capacity is given by; C=3R((ℏω)/(k_BT))²(e^ℏω/k_BT)/((e^ℏω/k_BT-1)²). Also show that Einstein specific heat capacity given above is proportional to e⁻ℏω/k_BT at very low temperature. 10 marks

(c)

ρ^° and K^° mesons both decay mostly to π⁺ and π⁻. Explain why the mean lifetime of ρ^° is shorter (∼10⁻²³s) compared to the mean lifetime of K^°(∼10⁻¹⁰s). 10 marks

(d)

What are the properties of the particles made up of the following quarks ? (a) ud̄ (b) ūd (c) dds (d) uss 10 marks

(e)

What are chain reactions ? What do you mean by critical size of the core in which chain reaction takes place ? 10 marks

हिंदी में प्रश्न पढ़ें
(a)

λ₁ तरंग-दैर्घ्य का एक एक्सरे किरणपुंज 30° के ब्रैग-कोण पर पहले क्रम के ब्रैग परावर्तन से गुजरता है । 97 nm तरंग-दैर्घ्य का एक्सरे 60° के ब्रैग कोण पर तृतीय क्रम के परावर्तन से गुजरता है । मान लीजिए कि दोनों किरणपुंज (बीम) एक ही तल से परावर्तित होते हैं तो λ₁ का मान ज्ञात कीजिए । (10 अंक)

(b)

आंतरिक ऊर्जा के व्यंजक U=3N(ℏω)/(e^ℏω/k_BT-1) का इस्तेमाल करते हुए दिखाइए कि आइंस्टीन की विशिष्ट ऊष्मा धारिता निम्नलिखित द्वारा निर्धारित है; C=3R((ℏω)/(k_BT))²(e^ℏω/k_BT)/((e^ℏω/k_BT-1)²)। यह भी दिखाइए कि ऊपर दी गई आइंस्टीन की विशिष्ट ऊष्मा धारिता कम तापमान पर e⁻ℏω/k_BT के समानुपाती होती है । (10 अंक)

(c)

ρ^° और K^° मेसॉन दोनों ही अधिकतर π⁺ और π⁻ में क्षय होते हैं । समझाइए कि ρ^° का औसत जीवन काल (∼10⁻²³s) K^° के औसत जीवन काल (∼10⁻¹⁰s) की तुलना में छोटा क्यों है । (10 अंक)

(d)

निम्नलिखित क्वार्कों से बने हुए कणों के गुण क्या हैं ? (a) ud̄ (b) ūd (c) dds (d) uss (10 अंक)

(e)

श्रृंखला अभिक्रियाएँ क्या होती हैं ? कोर के क्रांतिक परिमाण से, जिसके भीतर श्रृंखला अभिक्रिया होती है, आप क्या अर्थ निकालते हैं ? (10 अंक)

Q5 of the 2021 UPSC Mains Physics Paper II, as printed
The question as printed in the 2021 Physics paper

Model answer

Drafted with AI by UPSC Answer Check against this question's marking rubric, to the expected length. UPSC does not publish answers for Mains — this is one way to score well, not an official key. How we build rubrics and answers.

(a) Bragg’s law: nλ = 2d sin θ, with the same d for both beams.

First beam: λ₁ = 2d sin 30° = d. Second beam: 3 × 97 nm = 2d sin 60° = d√3, so d = 97√3 nm.

Hence λ₁ = d = 97√3 nm ≈ 168 nm.

(b) Let x = ħω/(k_BT). Then U = 3Nħω/(e^x − 1) and C = (∂U/∂T)_V.

Since dx/dT = −x/T = −ħω/(k_BT²), dU/dT = 3Nħω × e^x/(e^x − 1)² × ħω/(k_BT²) = 3Nk_B (ħω/(k_BT))² e^x/(e^x − 1)².

For one mole, Nk_B = R, so C = 3R (ħω/k_BT)² e^(ħω/k_BT)/(e^(ħω/k_BT) − 1)².

At very low temperature, x ≫ 1, so e^x − 1 ≈ e^x and C ≈ 3R x² e^(−x) = 3R (ħω/k_BT)² e^(−ħω/k_BT). Thus the exponential factor dominates and C ∝ e^(−ħω/k_BT); C falls to zero as T → 0, in agreement with the third law.

(c) ρ⁰ ≈ (uū − dd̄)/√2 has strangeness 0. The decay ρ⁰ → π⁺π⁻ conserves charge, baryon number, strangeness and isospin, so it proceeds by the strong interaction, whose characteristic time is about 10⁻²³ s.

K⁰ (d s̄) has strangeness S = +1, while π⁺π⁻ has S = 0. The decay K⁰ → π⁺π⁻ therefore changes strangeness by one unit (ΔS = 1). Strong and electromagnetic interactions conserve strangeness, so the decay must go through the weak interaction, which is far slower. Hence the lifetime is about 10⁻¹⁰ s (the short-lived K⁰ₛ component).

(d)

  • u d̄: Q = 2/3 + 1/3 = +1, B = 0, S = 0. This is the π⁺ meson, J^P = 0⁻, I = 1, I₃ = +1, mass ≈ 139.6 MeV/c², lifetime ≈ 2.6 × 10⁻⁸ s (weak decay).
  • ū d: Q = −1, B = 0, S = 0. This is the π⁻ meson, the antiparticle of π⁺, with the same J^P, mass and lifetime, and I₃ = −1.
  • d d s: Q = −1/3 − 1/3 − 1/3 = −1, B = 1, S = −1. This is the Σ⁻ baryon, J^P = 1/2⁺, I = 1, I₃ = −1, mass ≈ 1197 MeV/c², lifetime ≈ 1.5 × 10⁻¹⁰ s (weak decay).
  • u s s: Q = 2/3 − 1/3 − 1/3 = 0, B = 1, S = −2. This is the Ξ⁰ baryon, J^P = 1/2⁺, I = 1/2, I₃ = +1/2, mass ≈ 1315 MeV/c², lifetime ≈ 2.9 × 10⁻¹⁰ s (weak decay).

(e) A chain reaction is a self-sustaining series of fissions in which neutrons released by one fission induce further fissions. For example, a slow neutron absorbed by ²³⁵U gives fission fragments, 2–3 neutrons and about 200 MeV.

The multiplication factor k is the ratio of fission-causing neutrons in one generation to those in the previous generation. If k < 1 the reaction dies out (subcritical), if k = 1 it is steady (critical), and if k > 1 it grows (supercritical).

The critical size is the minimum size of the fissile core for which k = 1. In a smaller core, neutrons leak through the surface and are lost to parasitic absorption faster than they are produced, so the chain cannot be sustained. The critical mass is M_c = ρV_c. For a bare homogeneous sphere in one-speed diffusion theory, R_c = π√[D/(νΣ_f − Σ_a)]. The critical size is lowered by a spherical shape, higher enrichment or density, and a neutron reflector.

How this answer will be evaluated

What earns full marks: Complete derivations with correct limits; precise particle identification; clear physical reasoning for lifetimes.

Evaluation rubric

Each sub-part is marked on its own, against the marks and word limit printed on the paper.

  1. (a) Find λ1 using Bragg's law for two orders from the same planes. 10 marks

    calculate— given → formula → substitution → result with units → interpretation

    Must cover

    • nλ = 2d sin θ with the same d
    • d = 97√3 nm from the second beam
    • λ1 = 97√3 ≈ 168 nm

    Loses marks

    • Treating n = 1 for both beams
    • Arithmetic error in d

    Earns more

    • Correct use of sin 30° and sin 60°
  2. (b) Derive Einstein's specific heat and show C ∝ e^(−ħω/kT) at low T. 10 marks

    derive— given → assumptions → stepwise derivation → result → check

    Must cover

    • Differentiate U with respect to T using x = ħω/kT
    • Result C = 3R x² e^x/(e^x−1)²
    • Low T: e^x − 1 ≈ e^x gives C ∝ e^(−x)

    Loses marks

    • Sign or chain-rule error in dx/dT
    • Missing factor x²

    Earns more

    • Use Nk_B = R for one mole

    Extra mark

    • Note C → 0 as T → 0
  3. (c) Explain why ρ0 lives far shorter than K0 though both decay to π+π−. 10 marks

    explain— definition/context → points in order → small example → short close

    Must cover

    • ρ0 decay is strong, conserving strangeness; time about 1e-23 s
    • K0 has S = +1, pions S = 0, so ΔS = 1
    • Hence K0 decays weakly with lifetime about 1e-10 s

    Loses marks

    • Attributing the difference to mass alone

    Earns more

    • Quark content of ρ0 and K0

    Extra mark

    • Mention K0_S component
  4. (d) Identify the particles for the four quark combinations and give their properties. 10 marks

    describe— define → structure or process in order → labelled diagram → significance

    Must cover

    • ud̄ = π+ and ūd = π−, Q = ±1, B = 0, S = 0
    • dds = Σ−, Q = −1, B = 1, S = −1
    • uss = Ξ0, Q = 0, B = 1, S = −2

    Loses marks

    • Wrong charge or strangeness
    • Naming dds as Σ+

    Earns more

    • Spin-parity, isospin, mass or lifetime values

    Extra mark

    • Note weak decays for all four
  5. (e) Explain chain reaction and the critical size of the core. 10 marks

    define— precise definition → the distinguishing feature → one example

    Must cover

    • Self-sustaining fission by released neutrons, e.g. U-235
    • Multiplication factor k with k < 1, = 1, > 1 cases
    • Critical size = minimum core size for k = 1; leakage argument

    Loses marks

    • Confusing critical size with critical mass without explanation
    • Equating chain reaction with fusion

    Earns more

    • Critical mass and dependence on shape, enrichment, reflector
    • Diffusion-theory expression for R_c
What "Solve" is asking you to do

Choose the method, then carry it through to a final answer. Identifying what kind of problem this is and why that method applies is the first thing marked; a correct figure arrived at invisibly earns almost nothing.

Structure that answers it

Given data and what is required → method chosen, with the reason it applies → set-up (equation, circuit, free body, trial balance) → working, step by step → answer with units and any condition of validity

Where marks are lost

Doing the middle steps mentally and writing only the result. In mathematics papers, a further loss comes from giving a decimal where the exact value in surds or fractions was wanted, or from skipping the justification a part explicitly asks for.

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