Paper I — Q1
(a) A force F⃗ is given by F⃗ = x²y x̂ + zy² ŷ + xz² ẑ. Determine whether or not the force is conservative. 10 marks (b)…
A force F⃗ is given by F⃗ = x²y x̂ + zy² ŷ + xz² ẑ. Determine whether or not the force is conservative. 10 marks
Calculate the gravitational self-energy of the Earth. Given : Mass of Earth Mₑ = 6 × 10²⁴ kg and the Radius of Earth Rₑ = 6·4 × 10⁶ m 10 marks
What are the consequences of Lorentz transformations on length and time when observed from a frame moving at relativistic velocities ? 10 marks
Using Huygens' principle for a plane wave travelling from rarer medium 1 to a denser medium 2, show that
(sin i)/(sin r) = (v₁)/(v₂) = (μ₂)/(μ₁),
where i and r are the angles of incidence and refraction, respectively. v₁, μ₁ and v₂, μ₂ are the velocities and refractive indices in media 1 and 2, respectively. 10 marks
What are three and four level pumping schemes ? Explain the lasing action in these with schematic diagrams. 10 marks
हिंदी में प्रश्न पढ़ें
एक बल F⃗ = x²y x̂ + zy² ŷ + xz² ẑ से दिया गया है । ज्ञात कीजिए कि बल संरक्षी है या नहीं । 10
पृथ्वी की गुरुत्वीय नैज-ऊर्जा की गणना कीजिए । दिया गया है : पृथ्वी का द्रव्यमान Mₑ = 6 × 10²⁴ kg और पृथ्वी की त्रिज्या Rₑ = 6·4 × 10⁶ m 10
आपेक्षिक वेग पर गतिशील फ्रेम से प्रेक्षित होने की दशा में लोरेंट्ज़ रूपांतरण का लंबाई और समय पर क्या प्रभाव पड़ेगा ? 10 अंक
हाइगेंस के नियम का प्रयोग करते हुए, एक समतल प्रगामी तरंग के लिए, जो कि विरल माध्यम 1 से सघन माध्यम 2 में जा रही है, दर्शाइए कि
(sin i)/(sin r) = (v₁)/(v₂) = (μ₂)/(μ₁),
जहाँ कि i और r क्रमशः आपतन कोण और अपवर्तन कोण हैं । v₁, μ₁ और v₂, μ₂ माध्यम 1 और माध्यम 2 में क्रमशः वेग और अपवर्तनांक हैं । 10
तीन और चार स्तरीय पम्पिंग योजनाएँ क्या हैं ? इनमें लेज़िंग क्रिया को योजनाबद्ध रेखाचित्र सहित समझाइए । 10
Model answer
Drafted with AI by UPSC Answer Check against this question's marking rubric, to the expected length. UPSC does not publish answers for Mains — this is one way to score well, not an official key. How we build rubrics and answers.
(a) Is the force conservative?
A force defined on all space is conservative if and only if ∇×F = 0 everywhere; then the work is path-independent and F = −∇V. F = (x²y, zy², xz²), so Fx = x²y, Fy = zy², Fz = xz². (∇×F)x = ∂Fz/∂y − ∂Fy/∂z = 0 − y² = −y² (∇×F)y = ∂Fx/∂z − ∂Fz/∂x = 0 − z² = −z² (∇×F)z = ∂Fy/∂x − ∂Fx/∂y = 0 − x² = −x² Hence ∇×F = −(y² x̂ + z² ŷ + x² ẑ), which is non-zero except at the origin. The force is not conservative: the work done depends on the path, and no scalar potential exists.
(b) Gravitational self-energy of the Earth
Treat the Earth as a uniform sphere of mass M and radius R, built up shell by shell. When a sphere of radius r has been assembled, its mass is m = (4/3)πr³ρ, and a shell of thickness dr has mass dm = 4πr²ρ dr. Bringing it from infinity needs work dU = −G m dm / r = −(16/3)π²Gρ² r⁴ dr. Integrating from 0 to R: U = −(16/15)π²Gρ²R⁵. With ρ = 3M/(4πR³), this is U = −3GM²/(5R). Numbers: GM² = 6.67×10⁻¹¹ × (6×10²⁴)² = 6.67×10⁻¹¹ × 3.6×10⁴⁹ = 2.40×10³⁹ J·m U = −3 × 2.40×10³⁹ / (5 × 6.4×10⁶) = −2.25×10³² J. The Earth's gravitational self-energy is about −2.25×10³² J (the energy needed to disperse it to infinity); this is the uniform-density approximation, and the real, centrally dense Earth is more tightly bound (about −2.5×10³² J).
(c) Consequences of the Lorentz transformation for length and time
For frame S′ moving with speed v along x, x′ = γ(x − vt), t′ = γ(t − vx/c²), with γ = 1/√(1 − v²/c²) ≥ 1. Time dilation: a clock at rest in one frame shows proper time Δt₀; an observer in the other frame measures Δt = γΔt₀, so moving clocks run slow. Evidence: cosmic-ray muons (proper lifetime 2.2 μs) reach the ground because their lifetime in the Earth frame is γ times longer. Length contraction: a rod of proper length L₀ along the motion is measured as L = L₀/γ; dimensions perpendicular to the motion are unchanged. Relativity of simultaneity: events simultaneous in S (Δt = 0) separated by Δx have Δt′ = −γvΔx/c² in S′, so simultaneity is relative. The effects are reciprocal and become appreciable only when v is comparable to c; for v ≪ c, γ → 1 and the Galilean results are recovered. Because simultaneity is relative, length contraction and time dilation do not contradict each other.
(d) Snell's law from Huygens' principle
Huygens' principle: every point of a wavefront is a source of secondary wavelets, and the new wavefront is their common tangent (envelope). Let a plane wavefront AB in medium 1 (speed v₁) meet the plane interface at A, with the incident ray making angle i with the normal; B reaches the interface at C. In time t, B travels BC = v₁t. In the same time the wavelet from A spreads in medium 2 (speed v₂) to a sphere of radius AD = v₂t. The tangent from C to this sphere is CD, the refracted wavefront. The angle between the incident wavefront and the interface equals i, and that between the refracted wavefront and the interface equals r. In right triangles ABC and ADC, sharing the hypotenuse AC: sin i = BC/AC = v₁t/AC, sin r = AD/AC = v₂t/AC. Dividing: sin i / sin r = v₁/v₂. Since μ = c/v, v₁/v₂ = μ₂/μ₁. Hence sin i / sin r = v₁/v₂ = μ₂/μ₁. For a denser medium 2, v₂ < v₁, so r < i: the ray bends towards the normal.
(e) Three- and four-level pumping schemes
Lasing needs a population inversion between two levels, and a metastable upper level so that stimulated emission can compete with spontaneous decay. Three-level scheme (ruby laser): levels E₁ (ground), E₂ (metastable) and E₃ (pump band). Pumping takes atoms from E₁ to E₃; they decay rapidly and non-radiatively to E₂, which accumulates population. Laser transition: E₂ → E₁. Because the lower level is the ground state, more than half of all atoms must be pumped to E₂ before inversion, so the threshold is high and operation is often pulsed. Four-level scheme (Nd:YAG, He-Ne): levels E₁ (ground), E₂ (lower laser level), E₃ (metastable upper level) and E₄ (pump band). Atoms go from E₁ to E₄, decay quickly to E₃, and lase to E₂, which is nearly empty because it empties fast to E₁. Inversion between E₃ and E₂ is reached with only a small pumping, giving a low threshold and continuous operation. In both, a photon from spontaneous emission stimulates further identical photons (same frequency, phase, direction); mirrors of the optical cavity feed back, and when gain exceeds losses a coherent beam emerges. The four-level scheme is more efficient.
How this answer will be evaluated
What earns full marks: Complete derivations with clear diagrams, correct units, and physical interpretation
Evaluation rubric
Each sub-part is marked on its own, against the marks and word limit printed on the paper.
- (a) Determine whether the force F = x²y x̂ + zy² ŷ + xz² ẑ is conservative. 10 marks
calculate— given → formula → substitution → result with units → interpretation
Must cover
- Condition: curl F = 0
- Partial derivatives of each component
- Curl = -(y², z², x²)
- Conclusion: non-conservative
Loses marks
- Assuming conservative without a curl test.
Earns more
- Marks for the condition, the three components and the conclusion.
Extra mark
- Path dependence of work and no scalar potential.
- (b) Calculate the gravitational self-energy of the Earth. 10 marks
calculate— given → formula → substitution → result with units → interpretation
Must cover
- U = -3GM²/(5R) from shell assembly
- Substitution of M and R
- U ≈ -2.25×10³² J
- Units and interpretation
Loses marks
- Wrong formula or missing units.
Earns more
- Marks for the derivation, the correct power of ten and units.
Extra mark
- Uniform-density caveat.
- (c) Describe the consequences of Lorentz transformations on length and time at relativistic velocities. 10 marks
explain— definition/context → points in order → small example → short close
Must cover
- Lorentz factor γ
- Time dilation Δt = γΔt₀
- Length contraction L = L₀/γ
- Relativity of simultaneity
Loses marks
- Confusing proper length with observed length.
Earns more
- Marks for each effect and a physical interpretation.
Extra mark
- Muon evidence and reciprocity.
- (d) Using Huygens' principle derive sin i / sin r = v₁/v₂ = μ₂/μ₁. 10 marks
derive— given → assumptions → stepwise derivation → result → check
Must cover
- Huygens' principle and wavefront diagram
- BC = v₁t and AD = v₂t
- sin i = BC/AC, sin r = AD/AC
- μ = c/v for the final relation
Loses marks
- Missing diagram or skipped steps.
Earns more
- Marks for the construction, the geometry and the final relation.
Extra mark
- Bending towards the normal for a denser medium.
- (e) Explain three-level and four-level pumping schemes with lasing action. 10 marks
explain— definition/context → points in order → small example → short close
Must cover
- Population inversion and metastable level
- Three-level scheme (ruby), half the atoms must be pumped
- Four-level scheme (Nd:YAG, He-Ne), low threshold
- Stimulated emission and feedback
Loses marks
- Missing level labels or no comparison.
Earns more
- Marks for both schemes, labelled levels and a comparison.
Extra mark
- Pulsed versus continuous operation.
What "Derive" is asking you to do
Reach the stated expression from a starting relation, justifying every step. The destination is printed in the question, so only the route earns marks, and the assumptions you work under are part of that route.
Structure that answers it
Assumptions and notation defined → starting relation or governing equation → each step with its justification → the required expression → limiting case or boundary check
Where marks are lost
Writing the standard result first and fitting three lines to it, which an examiner reads at a glance. Marks also go on assumptions left unstated — lossless medium, small amplitude, errors independent with zero mean — and on symbols used before they are defined, even when the question says usual notations.
Practice this exact question
Write your answer and it is marked point by point against the model answer above — what you covered, what you missed, what you got wrong.
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