Physics 2023 Paper II 50 marks Explain

Paper II — Q8

(a) What do you understand by the critical size of a reactor ? Explain the main features of nuclear reactors. 5+15=20 (b) What…

(a)

What do you understand by the critical size of a reactor ? Explain the main features of nuclear reactors. 5+15=20

(b)

What is superconductivity ? Explain Meissner effect. Why superconductors should be a diamagnetic material ? 15 marks

(c)
(i)

Determine the input and output impedances of the amplifier in given figure. The op-amp datasheet gives Z_in = 2 MΩ, Z_out = 75 Ω and A_OL = 200,000 (open loop voltage gain). 10 marks

(ii)

Find the closed-loop voltage gain. 5 marks

हिंदी में प्रश्न पढ़ें
(a)

रिएक्टर के क्रांतिक आकार से आप का क्या अभिप्राय है ? नाभिकीय रिएक्टरों की मुख्य विशेषताओं का वर्णन कीजिए । 5+15=20

(b)

अतिचालकता क्या है ? माइसनर प्रभाव की व्याख्या कीजिए । अतिचालक पदार्थ क्यों एक प्रतिचुंबकीय पदार्थ होते हैं ? 15 अंक

(c)
(i)

दर्शाए गए चित्र में प्रवर्धक का निवेशी और निर्गत प्रतिबाधाओं का मान निर्धारित कीजिए । संक्रियात्मक प्रवर्धक के डेटाशीट के अनुसार Z_in = 2 MΩ, Z_out = 75 Ω और A_OL (खुला पाश वोल्टता गेन) = 200,000 है । 10

(ii)

संवृत पाश वोल्टता गेन का मान प्राप्त कीजिए । 5

Q8 of the 2023 UPSC Mains Physics Paper II, as printed
The question as printed in the 2023 Physics paper

The figure this question refers to, in words

The question paper is a scan and the diagram did not survive as text. This is the figure as read from the original page — every component, value and label — so the question can be worked from the text below.

(c) Circuit diagram of an operational amplifier (op-amp) in a non-inverting configuration. The op-amp is represented by a triangle with a non-inverting input terminal labeled '+' and an inverting input terminal labeled '-'. The input voltage source Vin is connected to the non-inverting terminal. The output terminal is labeled Vout. A feedback network is connected to the inverting terminal, consisting of two resistors in series connected between the output terminal and ground. The upper resistor is labeled Rf with a value of 220 kΩ, and the lower resistor is labeled R1 with a value of 10 kΩ. The inverting input terminal is connected to the junction between Rf and R1.

Model answer

Drafted with AI by UPSC Answer Check against this question's marking rubric, to the expected length. UPSC does not publish answers for Mains — this is one way to score well, not an official key. How we build rubrics and answers.

(a) Critical size and main features of nuclear reactors

Critical size is the smallest dimension of the reactor core (for a given fuel, moderator and geometry) at which the chain reaction is just self-sustaining, that is, k_eff = 1. The multiplication factor is k_eff = k∞P_NL, where k∞ = ηfpε is the infinite-medium value and P_NL is the non-leakage probability. Leakage from the surface falls as the core grows (surface/volume ∝ 1/size), so below the critical size k_eff < 1 and the chain dies out; above it k_eff > 1 and power rises. The fuel mass in this volume is the critical mass, which is a different quantity from the size. Main features: Fuel: natural uranium (PHWR), enriched U-235 (PWR, BWR) or Pu-239 (fast reactors), whose fission releases heat and 2-3 fast neutrons. Moderator: heavy water, graphite or light water slows fission neutrons from about 2 MeV to thermal energies (0.025 eV), where the fission cross section is large; natural uranium needs heavy water or graphite because they absorb few neutrons. Control rods: cadmium, boron or hafnium absorb neutrons to hold k_eff at 1, or to shut the reactor down; the delayed neutrons (about 0.65% for U-235) make this control practical. Coolant: water, heavy water, CO₂ or liquid sodium carries heat to a steam generator. Reflector: returns leaking neutrons and so lowers the critical size. Shield and containment: concrete and steel confine gamma rays, neutrons and fission products. Reactor types differ by the combination chosen, for example PHWR (natural uranium, heavy water) and PWR (enriched uranium, light water).

Diagram: Nuclear reactor schematic

(b) Superconductivity, the Meissner effect and diamagnetism

Superconductivity: below a critical temperature T_c, the d.c. resistance of certain materials falls to zero, so a current persists without a voltage. The state is destroyed above a critical field H_c. Meissner effect (1933): when a superconductor is cooled below T_c in a magnetic field, the flux is expelled from its interior, B = 0, except in a surface layer of thickness λ_L ≈ 10-100 nm (from ∇²B = B/λ_L² and λ_L = √(m/μ₀n_se²)). This happens whether the field is applied before or after cooling. A merely perfect conductor would instead trap the flux present when it became perfect, so flux expulsion is a separate property of the superconducting state, not a result of zero resistance. Why diamagnetic: B = μ₀(H + M) = 0 inside requires M = −H, so the susceptibility is χ = −1, perfect diamagnetism. Surface screening currents, which flow within λ_L as the field is applied, produce the magnetisation that cancels the applied field. Expelling the flux costs energy μ₀H²/2 per unit volume, which is balanced by the condensation energy μ₀H_c²/2 of the superconducting state, so the state survives until H = H_c. Type-I superconductors expel flux completely up to H_c; type-II expel it up to H_c1 and are in a mixed state with quantised vortices up to H_c2.

Diagram: Meissner effect

(c)(i) Input and output impedances of the non-inverting amplifier

The circuit is a non-inverting amplifier (voltage-series negative feedback) with R_f = 220 kΩ and R_i = 10 kΩ. Feedback fraction: β = R_i/(R_i + R_f) = 10/230 = 0.0435. Loop gain: A_OL β = 200,000 × 0.04348 = 8696, so 1 + A_OLβ = 8697. Input impedance: Z_in(CL) = Z_in(1 + A_OLβ) = 2 MΩ × 8697 ≈ 1.7×10¹⁰ Ω (17 GΩ), because feedback reduces the differential voltage that drives the input current. Output impedance: Z_out(CL) = Z_out/(1 + A_OLβ) = 75/8697 ≈ 8.6×10⁻³ Ω, because feedback holds the output voltage fixed against load changes.

(c)(ii) Closed-loop voltage gain

A_CL = A_OL/(1 + A_OLβ) = 200,000/8697 = 23.0 (dimensionless), more exactly 22.997. Ideal check: 1 + R_f/R_i = 1 + 220/10 = 23 = 1/β, so the gain is set by the resistors and not by A_OL, as long as A_OLβ ≫ 1.

How this answer will be evaluated

What earns full marks: Complete derivations with correct formulas, units, and physical interpretation for all parts.

Evaluation rubric

Each sub-part is marked on its own, against the marks and word limit printed on the paper.

  1. (a) Define the critical size of a reactor and explain the main features of nuclear reactors. 20 marks

    explain— definition/context → points in order → small example → short close

    Must cover

    • Critical size: smallest core size with k_eff = 1
    • k_eff = k∞P_NL and the sub-critical and super-critical cases
    • Fuel, moderator, control rods, coolant, reflector, shielding with functions
    • Distinction between critical size and critical mass

    Loses marks

    • Confusing critical size with critical mass or listing components without functions.

    Earns more

    • Marks for the definition, the neutron balance and the function of each component.

    Extra mark

    • Examples of PHWR and PWR with moderator materials and delayed neutrons.
  2. (b) Define superconductivity, explain the Meissner effect and say why superconductors are diamagnetic. 15 marks

    explain— definition/context → points in order → small example → short close

    Must cover

    • Zero resistance below T_c
    • Flux expulsion B = 0 inside, with penetration depth λ_L
    • Difference from a perfect conductor
    • M = −H so χ = −1, perfect diamagnetism

    Loses marks

    • Treating zero resistance as the whole explanation.

    Earns more

    • Marks for the definition, the Meissner effect, the distinction from a perfect conductor and the diamagnetism argument.

    Extra mark

    • London equation, Type I and II and the energy argument μ₀H_c²/2.
  3. (c)(i) Find the input and output impedances of the non-inverting amplifier with R_f = 220 kΩ and R_i = 10 kΩ. 10 marks

    calculate— given → formula → substitution → result with units → interpretation

    Must cover

    • Non-inverting amplifier with β = R_i/(R_i+R_f) = 0.0435
    • Loop gain A_OLβ = 8696
    • Z_in(CL) = Z_in(1+A_OLβ) ≈ 1.7×10¹⁰ Ω
    • Z_out(CL) = Z_out/(1+A_OLβ) ≈ 8.6×10⁻³ Ω

    Loses marks

    • Multiplying and dividing the wrong way or dropping units.

    Earns more

    • Marks for β, the loop gain and both impedances with units.

    Extra mark

    • Effect of feedback on the impedances and comparison with the ideal op-amp.
  4. (c)(ii) Find the closed-loop voltage gain of the amplifier. 5 marks

    calculate— given → formula → substitution → result with units → interpretation

    Must cover

    • A_CL = A_OL/(1+A_OLβ)
    • Substitution gives 23.0
    • Ideal value 1+R_f/R_i = 23
    • Gain is dimensionless

    Loses marks

    • Using the inverting-amplifier gain.

    Earns more

    • Marks for the formula, the substitution and the value.

    Extra mark

    • Exact 22.997 against the ideal 23, showing A_OL independence.
What "Explain" is asking you to do

Make the working of something clear — what sets it off, what follows from what, and what it produces. Explain is the Commission's mechanism word: it dominates the technical papers and the “explain why” stems, where the marks sit in the causal chain and not in the label.

Structure that answers it

State what it is → the initiating condition → the chain of cause, step by step → an instance where it plays out → what the chain produces

Where marks are lost

Describing what something looks like instead of why it works that way. Naming the stages without linking them reads as description too.

All UPSC directive words, compared →

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