Zoology 2023 Paper II 50 marks Explain

Paper II — Q4

(a) Explain the following: (10×2=20 marks) (i) Haemophilia (ii) Red-green colour blindness (b) Describe various stages of…

(a)
(i)

Explain the following: (10×2=20 marks) Haemophilia

(ii)

Red-green colour blindness

(b)

Describe various stages of prophase of meiosis-I in an animal cell. 15 marks

(c)

Explain phenomenon of natural selection taking examples of peppered moth and sickle cell anaemia. 15 marks

हिंदी में प्रश्न पढ़ें
(a)
(i)

निम्नलिखित की व्याख्या कीजिए: (10×2=20 अंक) हीमोफीलिया

(ii)

लाल-हरी वर्णांधता

(b)

एक प्राणिकोशिका में अर्धसूत्री विभाजन-I के प्रोफेज के विभिन्न चरणों का वर्णन कीजिए। (15 अंक)

(c)

पेपर्ड शलभ (मोथ) एवं हँसिया कोशिका अरक्तता (सिकल सेल एनीमिया) का उदाहरण लेते हुए प्राकृतिक चयन की घटना की व्याख्या कीजिए। (15 अंक)

Q4 of the 2023 UPSC Mains Zoology Paper II, as printed
The question as printed in the 2023 Zoology paper

Model answer

Drafted with AI by UPSC Answer Check against this question's marking rubric, to the expected length. UPSC does not publish answers for Mains — this is one way to score well, not an official key. How we build rubrics and answers.

(a) Haemophilia and red-green colour blindness

(i) Haemophilia: Nature: an X-linked recessive bleeding disorder in which blood fails to clot properly because a clotting factor is missing. Haemophilia A (classical) lacks Factor VIII, and haemophilia B (Christmas disease) lacks Factor IX. The genes lie on the X chromosome. Inheritance: a male has one X, so one defective allele (XʰY) causes the disease. A heterozygous female (XᴴXʰ) is a normal carrier, and only a homozygous female (XʰXʰ) is affected, which is rare and often lethal. Cross: a carrier mother and a normal father give daughters half normal and half carriers, and sons half normal and half haemophilic. An affected father and a normal mother give carrier daughters and normal sons, so there is no male-to-male transmission. Features: prolonged bleeding after injury, bleeding into joints and bruising. The disease passed to many royal families from Queen Victoria, a carrier. Treatment is by replacing the factor. (ii) Red-green colour blindness: Nature: an X-linked recessive defect of colour vision in which red and green cannot be told apart. The genes for the red- and green-sensitive cone pigments lie close together on the X chromosome (Xq28). Types: protanopia (red-blind), deuteranopia (green-blind), and the milder protanomaly and deuteranomaly. Inheritance: the pattern is the same as haemophilia. It is much commoner in males (about 8 per cent of men and 0·5 per cent of women), because the female needs two defective alleles. A colour-blind father passes the allele to his daughters, who become carriers. Detection: Ishihara plates.

(b) Stages of prophase of meiosis I in an animal cell

Prophase I is the longest and most complex phase, in which homologous chromosomes pair and exchange segments. It has five stages. Leptotene: chromosomes condense and appear as long thin threads, each already having two chromatids. The ends attach to the nuclear envelope. Zygotene: homologous chromosomes come together, gene by gene, in synapsis. The synaptonemal complex forms between them, and each pair is a bivalent. Pachytene: chromosomes become short and thick, and each bivalent shows four chromatids, a tetrad. Crossing over takes place between non-sister chromatids at recombination nodules, giving new combinations of genes. Diplotene: the synaptonemal complex dissolves and the homologues begin to separate, but remain joined at X-shaped chiasmata where crossing over has occurred. In the oocytes of human females this stage can last for years. Diakinesis: chromosomes reach maximum condensation, the chiasmata move to the ends (terminalisation), the nucleolus disappears and the nuclear envelope breaks down, and the spindle forms.

(c) Natural selection, with peppered moth and sickle-cell anaemia

Natural selection is the differential survival and reproduction of individuals whose heritable variations suit them better to the environment, so that favourable alleles become more common. Peppered moth, Biston betularia: Before industrialisation in England, the light speckled form (typica) was well hidden on lichen-covered bark, and the dark form (carbonaria) was rare because birds picked it out. Pollution killed the lichens and blackened tree trunks, so dark moths were hidden and light ones were eaten. By about 1900 the dark form made up nearly all moths in industrial areas. Kettlewell's release-recapture experiments in the 1950s showed that birds were the agent. After the Clean Air Act (1956) the light form increased again. It is a case of directional selection. Sickle-cell anaemia: It is caused by a point mutation in the β-globin gene, in which glutamic acid is replaced by valine, forming the allele HbS. Homozygotes (HbSHbS) have severe anaemia and die early, so the allele should be lost. Heterozygotes (HbAHbS) are healthy, and resist falciparum malaria. In malarial regions, such as Africa and tribal areas of central and southern India, heterozygotes are fitter than both homozygotes, so the HbS allele is maintained at high frequency. This is balancing selection (heterozygote advantage).

How this answer will be evaluated

Framework: Zoology, Paper 2

What earns full marks: Precise definitions, clear mechanisms, accurate diagrams, and strong linkage of examples to theory.

Evaluation rubric

Each sub-part is marked on its own, against the marks and word limit printed on the paper.

  1. (a) Explain haemophilia and red-green colour blindness. 20 marks

    explain— definition/context → points in order → small example → short close

    Must cover

    • Haemophilia: X-linked recessive, factor VIII or IX deficiency
    • Carrier female and crosses; affected only females homozygous
    • Colour blindness: X-linked opsin genes at Xq28; protan and deutan types
    • Higher prevalence in males; Ishihara test

    Loses marks

    • Saying haemophilia is autosomal or dominant.

    Earns more

    • Both disorders with X-linked inheritance and crosses.

    Extra mark

    • Queen Victoria pedigree.
  2. (b) Describe the various stages of prophase of meiosis I in an animal cell. 15 marks

    describe— define → structure or process in order → labelled diagram → significance

    Must cover

    • Leptotene: condensation
    • Zygotene: synapsis and synaptonemal complex
    • Pachytene: tetrads and crossing over
    • Diplotene and diakinesis: chiasmata, terminalisation, envelope breakdown

    Loses marks

    • Mixing the order of stages.

    Earns more

    • All five stages in order with the key event.

    Extra mark

    • Dictyotene arrest in oocytes.
  3. (c) Explain the phenomenon of natural selection with peppered moth and sickle-cell anaemia. 15 marks

    explain— definition/context → points in order → small example → short close

    Must cover

    • Definition: differential reproduction of fitter variants
    • Peppered moth: lichen, soot, carbonaria rise, Kettlewell, decline after clean air
    • Sickle-cell: Glu to Val; HbS in homozygous harmful
    • Heterozygote advantage against malaria; balancing selection

    Loses marks

    • Saying selection creates new mutations.

    Earns more

    • Both examples with the type of selection.

    Extra mark

    • Clean Air Act 1956; Indian tribal belts.
What "Explain" is asking you to do

Make the working of something clear — what sets it off, what follows from what, and what it produces. Explain is the Commission's mechanism word: it dominates the technical papers and the “explain why” stems, where the marks sit in the causal chain and not in the label.

Structure that answers it

State what it is → the initiating condition → the chain of cause, step by step → an instance where it plays out → what the chain produces

Where marks are lost

Describing what something looks like instead of why it works that way. Naming the stages without linking them reads as description too.

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