Q2
(a) (i) For the circuit shown in Figure 2(a)(i), initial current through the coil is zero. The switch is closed at time t = 0. Find the time domain expression of current flowing through the coil for t ≥ 0. How long will it take for the coil current to reach 95% of its final value and what is the final value of this current? (10 marks) (ii) Obtain the Thevenin's equivalent of the network shown in Figure 2(a)(ii), across the terminals XY. (10 marks) (b) (i) Determine the Inverse Laplace Transform of the following function: F(s) = (s³ + 7s² + 14s + 11)/(s³ + 6s² + 11s + 6) (6 marks) (ii) Find the initial and final value of the current whose Laplace Transform is given below: I(s) = 0.32/[s(s² + 2.42s + 0.672)] (4 marks) (iii) Solve the following differential equation: d²i/dt² + di/dt = t² + 2t. Given that i(0-) = 4 and (di/dt)₀₋ = -2. (10 marks) (c) A single phase AC bridge rectifier as shown in Figure 2(c) is operating at firing delay angle α = 45°. The thyristor T₃ gets damaged and behaves as an open circuit. Calculate the value of load resistance R if load current is 3·1556 A. (10 marks)
हिंदी में प्रश्न पढ़ें
(a) (i) चित्र 2(a)(i) में दर्शाए गए परिपथ में कुंडली की प्रारंभिक धारा शून्य है। परिपथ की कुंजी (स्विच) t = 0 पर बंद की जाती है। t ≥ 0 के लिए कुंडली में प्रवाहित होने वाली धारा का काल क्षेत्र व्यंजक ज्ञात कीजिए। कुंडली में प्रवाहित धारा को इसके अंतिम मान के 95% मान तक पहुँचने में कितना समय लगेगा, और इस धारा का अंतिम मान क्या होगा? (10 अंक) (ii) चित्र 2(a)(ii) में दर्शाए गए परिपथ (नेटवर्क) में अंतस्थ (टर्मिनल) XY के मध्य थेवेनिन समतुल्य प्राप्त कीजिए। (10 अंक) (b) (i) निम्नलिखित फलन का व्युत्क्रम (इनवर्स) लाप्लास रूपांतरण ज्ञात कीजिए: F(s) = (s³ + 7s² + 14s + 11)/(s³ + 6s² + 11s + 6) (6 अंक) (ii) धारा, जिसका लाप्लास रूपान्तरण नीचे दिया गया है, के प्रारम्भिक तथा अन्तिम मान ज्ञात कीजिए: I(s) = 0.32/[s(s² + 2.42s + 0.672)] (4 अंक) (iii) निम्नलिखित अवकल समीकरण को हल कीजिए: d²i/dt² + di/dt = t² + 2t। दिया गया है कि i(0-) = 4 और (di/dt)₀₋ = -2 है। (10 अंक) (c) चित्र 2(c) में दर्शाए गए एकल कला ए.सी. सेतु दिष्टकारी का प्रचालन α = 45° फायरिंग विलम्ब कोण पर होता है। थायरिस्टर T₃ में दोष के कारण वह विद्युत (खुला) परिपथ की तरह व्यवहार करता है। यदि भार विद्युत धारा 3.1556 A हो, तो भार प्रतिरोध R का मान परिकलित कीजिए। (10 अंक)
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How this answer will be evaluated
Approach
Solve this multi-part numerical problem by allocating time proportionally to marks: approximately 40% on part (a) [20 marks], 40% on part (b) [20 marks], and 20% on part (c) [10 marks]. Begin with clear circuit diagrams for (a)(i), (a)(ii) and (c), then proceed with systematic mathematical derivations. For transient analysis in (a)(i), establish the differential equation and apply initial conditions. For Thevenin's equivalent in (a)(ii), show open-circuit voltage and short-circuit current calculations. In part (b), demonstrate partial fraction expansion for (i), apply Initial and Final Value Theorems correctly for (ii), and use Laplace transforms to solve the differential equation in (iii). Conclude with practical interpretations of time constants, steady-state values, and fault implications in power electronics.
Key points expected
- For (a)(i): Derive i(t) = (V/R)(1 - e^(-t/τ)) for RL circuit, calculate time constant τ = L/R, determine 95% settling time as t = 3τ, and state final value I_final = V/R
- For (a)(ii): Calculate Thevenin voltage V_TH using mesh/nodal analysis and Thevenin resistance R_TH by deactivating independent sources, presenting equivalent circuit with values
- For (b)(i): Perform polynomial long division to make F(s) proper, factor denominator (s+1)(s+2)(s+3), apply partial fraction expansion, and obtain inverse Laplace transform
- For (b)(ii): Verify applicability of Initial Value Theorem (proper rational function) and Final Value Theorem (poles in LHP), then apply limits as s→∞ and s→0
- For (b)(iii): Take Laplace transform of differential equation, apply initial conditions i(0-) = 4 and i'(0-) = -2, solve for I(s), decompose by partial fractions, and invert to get i(t)
- For (c): Analyze single-phase bridge rectifier with T₃ open (fault condition), determine conduction pattern with only two thyristors firing, derive average output voltage V_o = (V_m/π)(1+cosα) for half-wave equivalent, and solve for R = V_o/I_o
Evaluation rubric
| Dimension | Weight | Max marks | Excellent | Average | Poor |
|---|---|---|---|---|---|
| Concept correctness | 20% | 10 | Correctly applies RL transient theory for (a)(i), Thevenin's theorem with proper source transformation for (a)(ii), partial fraction decomposition and ILT techniques for (b)(i)-(iii), and fault analysis of bridge rectifier with modified conduction angle for (c); no conceptual errors in network theorems or Laplace properties | Minor errors in applying theorems (e.g., incorrect sign convention in KVL, confusion between Thevenin and Norton, partial fraction arithmetic mistakes) or incomplete justification for IVT/FVT applicability; rectifier analysis shows understanding but incorrect voltage integration limits | Fundamental misconceptions such as treating RL circuit as RC, applying Thevenin's theorem incorrectly (e.g., keeping dependent sources active while finding R_TH), using Final Value Theorem when poles exist in RHP, or analyzing bridge rectifier as normal operation ignoring T₃ fault |
| Numerical accuracy | 20% | 10 | All calculations precise: correct time constant and 95% settling time in (a)(i), accurate V_TH and R_TH values in (a)(ii), exact partial fraction coefficients and final time-domain expressions in (b), correct initial value i(0+) = 0 and final value i(∞) = 0.476 A in (b)(ii), and R ≈ 50Ω in (c) with proper handling of α = 45° | Computational errors in 10-20% of calculations (e.g., arithmetic mistakes in partial fractions, incorrect pole identification, time constant calculation errors, or final resistance value off by 10-15%); method correct but execution flawed | Major numerical errors (>30% deviation), incorrect formula substitution (e.g., using ωt instead of α in rectifier), wrong unit conversions, or answers without any supporting calculations; demonstrates inability to handle complex algebra |
| Diagram quality | 15% | 7.5 | Clear, labeled circuit diagrams for (a)(i) showing switch, source, R and L with reference directions; (a)(ii) with terminals X-Y explicitly marked and Thevenin equivalent drawn; (c) showing bridge configuration with thyristors T₁-T₄, AC source, and load R with correct firing sequence indication; all component values marked | Diagrams present but incomplete labeling (missing current directions, polarity marks, or terminal labels), hand-drawn sketches acceptable but lacking neatness, or Thevenin equivalent shown without original circuit; rectifier diagram misses firing angle indication | Missing essential diagrams, unrecognizable sketches, or failure to show Thevenin equivalent circuit; no attempt to illustrate the fault condition in (c) or incorrect circuit topology (e.g., half-wave instead of bridge) |
| Step-by-step derivation | 30% | 15 | Systematic progression: KVL setup → characteristic equation → complete solution with transient and steady-state parts for (a)(i); sequential calculation of V_OC, I_SC, then R_TH = V_OC/I_SC for (a)(ii); explicit polynomial division, factorization, partial fraction setup with coefficient comparison, and term-by-term inversion for (b)(i); rigorous limit evaluation with theorem verification for (b)(ii); complete Laplace transformation, algebraic manipulation, and inverse transformation for (b)(iii); modified voltage waveform integration with proper limits for (c) | Derivations present but with skipped steps (e.g., jumping from differential equation to solution without showing characteristic roots, omitting partial fraction coefficient calculations, or presenting final answers without intermediate working); some logical gaps but recoverable | Disorganized or missing derivations, no shown work for partial fractions, direct statement of answers without methodology, or incorrect mathematical procedures (e.g., algebraic errors in solving simultaneous equations, wrong integration limits) |
| Practical interpretation | 15% | 7.5 | Interprets 95% settling time as 3τ for relay/inductor sizing applications; explains Thevenin equivalent utility for load matching and maximum power transfer; discusses physical significance of initial/final values in circuit transients; analyzes T₃ fault impact on output voltage ripple, reduced average voltage, and potential damage to remaining thyristors due to increased current stress—relevant to Indian railway traction and industrial drive protection systems | Brief mention of practical relevance without elaboration (e.g., stating 'used in filters' without context, or 'fault affects output' without quantifying impact); generic statements about Laplace transform utility without circuit-specific interpretation | No physical interpretation provided, purely mathematical treatment, or incorrect practical conclusions (e.g., claiming fault improves rectifier performance, misunderstanding time constant significance, or irrelevant applications cited) |
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