Q5 50M Compulsory solve Differential equations, linear algebra, numerical methods, classical mechanics, fluid dynamics
(a) It is given that the equation of any cone with vertex at (a, b, c) is f((x-a)/(z-c), (y-b)/(z-c)) = 0. Find the differential equation of the cone. (10 marks)
(b) Solve, by Gauss elimination method, the system of equations
2x + 2y + 4z = 18
x + 3y + 2z = 13
3x + y + 3z = 14 (10 marks)
(c) (i) Convert the number (1093·21875)₁₀ into octal and the number (1693·0628)₁₀ into hexadecimal systems.
(ii) Express the Boolean function F(x, y, z) = xy + x'z in a product of maxterms form. (10 marks)
(d) A particle at a distance r from the centre of force moves under the influence of the central force F = -k/r², where k is a constant. Obtain the Lagrangian and derive the equations of motion. (10 marks)
(e) The velocity components of an incompressible fluid in spherical polar coordinates (r, θ, ψ) are (2Mr⁻³cosθ, Mr⁻²sinθ, 0), where M is a constant. Show that the velocity is of the potential kind. Find the velocity potential and the equations of the streamlines. (10 marks)
हिंदी में पढ़ें
(a) दिया गया है कि शीर्ष (a, b, c) वाले किसी शंकु का समीकरण f((x-a)/(z-c), (y-b)/(z-c)) = 0 है। शंकु का अवकल समीकरण ज्ञात कीजिए। (10 अंक)
(b) गॉस विलोपन विधि द्वारा समीकरण निकाय
2x + 2y + 4z = 18
x + 3y + 2z = 13
3x + y + 3z = 14
को हल कीजिए। (10 अंक)
(c) (i) संख्या (1093·21875)₁₀ को अष्टाधारी तथा संख्या (1693·0628)₁₀ को षोडश-आधारी पद्धति में बदलिए।
(ii) बूलिय फलन F(x, y, z) = xy + x'z को योगद (मैक्सटर्म) के गुणन के रूप में अभिव्यक्त कीजिए। (10 अंक)
(d) एक कण, जो बल-केंद्र से r दूरी पर है, केंद्रीय बल F = -k/r², जहाँ k एक स्थिरांक है, के प्रभाव में गतिमान है। लैग्रांजियन निकालिये तथा गति के समीकरणों को व्युत्पन्न कीजिये। (10 अंक)
(e) किसी असंपीड्य तरल के गोलीय ध्रुवी निर्देशांकों (r, θ, ψ) में वेग-घटक (2Mr⁻³cosθ, Mr⁻²sinθ, 0) है, जहाँ M एक स्थिरांक है। दर्शाइये कि वेग, विभव प्रकार का है। वेग विभव तथा धारारेखाओं के समीकरण ज्ञात कीजिये। (10 अंक)
Answer approach & key points
Solve each sub-part systematically with clear section headings. For (a), set up the cone equation and eliminate the arbitrary function f to get the PDE; for (b), perform Gauss elimination with back substitution; for (c)(i), convert decimal to octal/hexadecimal using successive division/multiplication, and for (c)(ii), expand to canonical POS form using Boolean algebra or K-map; for (d), construct Lagrangian in polar coordinates and derive Euler-Lagrange equations; for (e), verify irrotational flow condition, integrate for velocity potential, and solve streamline equations. Allocate approximately 15% time each to (a), (b), (c)(i), (c)(ii), and 20% each to (d) and (e) due to their derivational complexity.
- For (a): Eliminate arbitrary function f by differentiating the cone equation with respect to x, y, z and eliminating f_u, f_v to obtain the PDE (z-c)p + (z-c)q = (x-a) + (y-b) where p=∂z/∂x, q=∂z/∂y
- For (b): Form augmented matrix, perform row operations to achieve upper triangular form, back-substitute to get x=1, y=2, z=3 with verification
- For (c)(i): Convert (1093.21875)₁₀ = (2105.16)₈ and (1693.0628)₁₀ = (69D.101)₁₆ showing integer and fractional part conversions separately
- For (c)(ii): Express F(x,y,z) = xy + x'z in product of maxterms as ΠM(0,2,4,6) or (x+y+z)(x+y'+z)(x'+y+z)(x'+y'+z) using truth table or algebraic expansion
- For (d): Construct Lagrangian L = ½m(ṙ² + r²θ̇²) + k/r in polar coordinates, derive equations: m(r̈ - rθ̇²) = -k/r² and d/dt(mr²θ̇) = 0 (conservation of angular momentum)
- For (e): Verify ∇×v = 0, obtain velocity potential φ = -Mr⁻²cosθ, and derive streamline equations as r²sin²θ = constant, ψ = constant
Q6 50M solve PDE heat equation, Boolean algebra, moment of inertia
(a) Solve the heat equation ∂u/∂t = ∂²u/∂x², 0 < x < l, t > 0 subject to the conditions u(0, t) = u(l, t) = 0, u(x, 0) = x(l-x), 0 ≤ x ≤ l. (20 marks)
(b) Find a combinatorial circuit corresponding to the Boolean function f(x, y, z) = [x · (ȳ + z)] + y and write the input/output table for the circuit. (15 marks)
(c) Find the moment of inertia of a right circular solid cone about one of its slant sides (generator) in terms of its mass M, height h and the radius of base as a. (15 marks)
हिंदी में पढ़ें
(a) उष्मा समीकरण ∂u/∂t = ∂²u/∂x², 0 < x < l, t > 0 का शर्तों u(0, t) = u(l, t) = 0, u(x, 0) = x(l-x), 0 ≤ x ≤ l से प्रतिबंधित हल ज्ञात कीजिये। (20 अंक)
(b) बूलिय फलन f(x, y, z) = [x · (ȳ + z)] + y का संगत संयोजीव्यास परिपथ (कॉम्बिनेटोरियल सर्किट) ज्ञात कीजिये तथा परिपथ के लिये निवेश/निर्गत (इनपुट/आउटपुट) सारणी लिखिये। (15 अंक)
(c) एक लम्ब वृत्तीय ठोस शंकु का उसकी संहति M, ऊँचाई h तथा आधार की त्रिज्या a के रूप में उसकी एक तिर्यक रेखा (जनक रेखा) के सापेक्ष जड़त्व-आघूर्ण ज्ञात कीजिये। (15 अंक)
Answer approach & key points
Solve requires systematic derivation of exact solutions with complete mathematical rigor. Allocate approximately 40% of effort to part (a) as it carries 20 marks—apply separation of variables, determine Fourier coefficients for the parabolic initial condition, and write the complete series solution. Spend roughly 30% each on (b) and (c): for (b), construct the logic circuit using AND/OR/NOT gates and enumerate all 8 input combinations; for (c), set up proper coordinate system with cone vertex at origin, use parallel axis theorem or direct integration about slant generator, and express result purely in terms of M, h, a. Present each part distinctly with clear labeling.
- Part (a): Correct application of separation of variables u(x,t) = X(x)T(t), eigenvalues λ_n = n²π²/l², and Fourier sine series coefficients a_n = (4l²/n³π³)[1-(-1)ⁿ] for the initial condition x(l-x)
- Part (a): Final solution expressed as u(x,t) = Σ_{n=1}^∞ (8l²/n³π³)sin(nπx/l)exp(-n²π²t/l²) for odd n, with explicit recognition that even terms vanish
- Part (b): Correct Boolean simplification to f = xz + xȳ + y, or equivalent form, followed by circuit diagram with proper gate symbols (AND, OR, NOT) showing input/output flow
- Part (b): Complete truth table with all 8 rows (000 through 111) showing intermediate values ȳ, (ȳ+z), x·(ȳ+z), and final output f
- Part (c): Proper coordinate setup with cone geometry, density ρ = 3M/πa²h, and integration limits; correct application of perpendicular axis theorem or direct moment calculation about slant generator
- Part (c): Final expression I = (3M/20)(a² + 4h²) or equivalent simplified form involving slant height l = √(a²+h²), with dimensional verification [ML²]
Q7 50M solve Partial differential equations and fluid dynamics
(a) Find the general solution of the partial differential equation $$(D^2 + DD' - 6D'^2)z = x^2 \sin(x+y)$$ where $D \equiv \frac{\partial}{\partial x}$ and $D' \equiv \frac{\partial}{\partial y}$. (15 marks)
(b) The velocity of a train which starts from rest is given by the following table, the time being reckoned in minutes from the start and the velocity in km/hour:
| $t$ (minutes) | 2 | 4 | 6 | 8 | 10 | 12 | 14 | 16 | 18 | 20 |
|---|---|---|---|---|---|---|---|---|---|---|
| $v$ (km/hour) | 16 | 28.8 | 40 | 46.4 | 51.2 | 32 | 17.6 | 8 | 3.2 | 0 |
Using Simpson's $\frac{1}{3}$rd rule, estimate approximately in km the total distance run in 20 minutes. (15 marks)
(c) Two point vortices each of strength $k$ are situated at $(\pm a, 0)$ and a point vortex of strength $-\frac{k}{2}$ is situated at the origin. Show that the fluid motion is stationary and also find the equations of streamlines. If the streamlines, which pass through the stagnation points, meet the $x$-axis at $(\pm b, 0)$, then show that $3\sqrt{3}(b^2-a^2)^2 = 16a^3b$. (20 marks)
हिंदी में पढ़ें
(a) आंशिक अवकल समीकरण $$(D^2 + DD' - 6D'^2)z = x^2 \sin(x+y)$$ जहाँ $D \equiv \frac{\partial}{\partial x}$ तथा $D' \equiv \frac{\partial}{\partial y}$, का व्यापक हल ज्ञात कीजिये। (15 अंक)
(b) एक रेलगाड़ी, जो कि विश्राम से चलना प्रारंभ करती है, का वेग निम्नलिखित सारणी द्वारा दिया गया है। प्रस्थान से समय की गणना मिनट में तथा वेग की कि० मी०/घंटा में की गयी है:
| $t$ (मिनट) | 2 | 4 | 6 | 8 | 10 | 12 | 14 | 16 | 18 | 20 |
|---|---|---|---|---|---|---|---|---|---|---|
| $v$ (कि० मी०/घंटा) | 16 | 28.8 | 40 | 46.4 | 51.2 | 32 | 17.6 | 8 | 3.2 | 0 |
सिम्पसन के $\frac{1}{3}$ नियम का उपयोग करके 20 मिनट में तय की गयी कुल दूरी (लगभग) का आकलन कि० मी० में कीजिये। (15 अंक)
(c) दो बिंदु भ्रमिल, जहाँ प्रत्येक का सामर्थ्य $k$ है, $(\pm a, 0)$ पर स्थित हैं तथा $-\frac{k}{2}$ सामर्थ्य का एक बिंदु भ्रमिल, मूलबिंदु पर स्थित है। दर्शाइये कि तरल गति अचल है तथा धारारेखाओं के समीकरण भी ज्ञात कीजिये। यदि धारारेखाएँ, जो कि प्रगतिरोध बिंदुओं (स्टैगनेशन पॉइंट) से गुजरती हैं, $x$-अक्ष पर $(\pm b, 0)$ पर मिलती हैं, तब दर्शाइये कि $3\sqrt{3}(b^2-a^2)^2 = 16a^3b$। (20 अंक)
Answer approach & key points
Solve this three-part numerical problem by allocating approximately 30% time to part (a) PDE solution, 30% to part (b) numerical integration, and 40% to part (c) vortex dynamics. Begin with the complementary function and particular integral for (a), apply Simpson's 1/3rd rule with proper unit conversion for (b), and establish complex potential, velocity field, and streamline equations for (c). Conclude each part with verified final answers and proper dimensional analysis.
- Part (a): Factorize the operator (D² + DD' - 6D'²) = (D + 3D')(D - 2D'), find complementary function φ₁(y - 3x) + φ₂(y + 2x), and use correct particular integral method for x²sin(x+y)
- Part (b): Convert time interval to hours (h = 2/60 = 1/30 hour), verify even number of intervals for Simpson's 1/3rd rule, and compute distance = ∫v dt with proper unit handling
- Part (c): Construct complex potential w = -ik/2π[ln(z-a) + ln(z+a) - ½ln(z)], show dw/dz = 0 at stagnation points, derive streamline equations ψ = constant
- Part (c): Locate stagnation points on x-axis by solving velocity equations, find streamline passing through them, and verify the given algebraic relation 3√3(b²-a²)² = 16a³b
- Correct handling of units throughout: km/hour to km for distance, consistent time conversions, and dimensionless verification in part (c)
Q8 50M solve PDE canonical forms and numerical methods
(a) Reduce the following partial differential equation to a canonical form and hence solve it: $$yu_{xx} + (x+y)u_{xy} + xu_{yy} = 0$$ (15 marks)
(b) Using Runge-Kutta method of fourth order, solve the differential equation $\frac{dy}{dx} = x + y^2$ with $y(0) = 1$, at $x = 0.2$. Use four decimal places for calculation and step length 0.1. (15 marks)
(c) Verify that $w = ik \log \{(z-ia)/(z+ia)\}$ is the complex potential of a steady flow of fluid about a circular cylinder, where the plane $y = 0$ is a rigid boundary. Find also the force exerted by the fluid on unit length of the cylinder. (20 marks)
हिंदी में पढ़ें
(a) निम्नलिखित आंशिक अवकल समीकरण $$yu_{xx} + (x+y)u_{xy} + xu_{yy} = 0$$ को विहित रूप में समानीत कीजिये और अतः इसको हल कीजिये। (15 अंक)
(b) चतुर्थ कोटि की रूने-कुट्टा विधि का उपयोग करके अवकल समीकरण $\frac{dy}{dx} = x + y^2$, जबकि $y(0) = 1$ है, को $x = 0.2$ पर हल कीजिये। परिकलन में दशमलव के चार स्थानों तक तथा पग लम्बाई (स्टेप लैंथ) 0.1 का उपयोग कीजिये। (15 अंक)
(c) सत्यापित कीजिये कि एक वृत्ताकार बेलन के इर्द-गिर्द एक तरल के अपरिवर्ती प्रवाह का सम्मिश्र विभव $w = ik \log \{(z-ia)/(z+ia)\}$ है, जहाँ समतल $y = 0$ एक दृढ़ सीमा है। बेलन की एकक लम्बाई (यूनिट लैंथ) पर तरल द्वारा लगाये गये बल को भी ज्ञात कीजिये। (20 अंक)
Answer approach & key points
Solve all three sub-parts systematically, allocating approximately 30% time to part (a) on PDE canonical reduction, 30% to part (b) on RK4 numerical computation, and 40% to part (c) on complex potential verification and force calculation. Begin with identifying the PDE type and characteristic equations for (a), execute precise iterative calculations for (b), and apply Blasius theorem or residue calculus for force in (c). Present each part with clear headings and final boxed answers.
- For (a): Correct classification of PDE type (hyperbolic/parabolic/elliptic) via discriminant B²-4AC = (x+y)²-4xy = (x-y)² ≥ 0, identifying hyperbolic nature with characteristic curves ξ = x-y and η = x+y or similar
- For (a): Proper reduction to canonical form u_ξη = 0 or equivalent, followed by general solution u = f(x-y) + g(x+y) or variant
- For (b): Correct RK4 formulas with k₁, k₂, k₃, k₄ calculations at each step, showing two complete steps (h=0.1) to reach x=0.2 with y(0.2) ≈ 1.2734
- For (c): Verification that w = ik log[(z-ia)/(z+ia)] represents flow past cylinder |z|=a with y=0 as streamline, using conformal mapping properties and image system
- For (c): Application of Blasius theorem or pressure integration to find force, showing zero drag (d'Alembert paradox) and lift calculation using circulation Γ = 2πk
- For (c): Final force expression as (0, 2πρk²) or equivalent per unit length, with proper physical interpretation