Mathematics

UPSC Mathematics 2025 — Paper I

All 8 questions from UPSC Civil Services Mains Mathematics 2025 Paper I (400 marks total). Every stem reproduced in full, with directive-word analysis, marks, word limits, and answer-approach pointers.

8Questions
400Total marks
2025Year
Paper IPaper

Topics covered

Linear algebra, calculus and 3D geometry (1)Linear transformation, mean value theorem and 3D geometry (1)Linear algebra, analytical geometry, multivariable calculus (1)Analytical geometry, partial derivatives, linear algebra (1)Differential equations, ellipses, orbital mechanics, catenary, vector calculus (1)Laplace transforms, convolution, integral equations, elastic string, directional derivative, Maxwell's equations (1)Mechanics, vector calculus and differential equations (1)Differential equations, vector calculus and particle dynamics (1)

A

Q1
50M Compulsory solve Linear algebra, calculus and 3D geometry

(a) Can the set {(0, 0, 0, 3), (1, 1, 0, 0), (0, 1, –1, 0)} be extended to form a basis of the vector space ℝ⁴? Justify your answer. 10 marks (b) Find the range, rank, kernel and nullity of the linear transformation T : ℝ⁴ → ℝ³ given by T(x, y, z, w) = (x – w, y + z, z – w). 10 marks (c) A rectangular sheet of metal of length 6 meters and width 2 meters is given. Four equal squares are removed from the four corners. The sides of this sheet are now folded up to form an open rectangular box. Find approximately the height of the box, such that the volume of the box is maximum. 10 marks (d) Given that f(x + y) = f(x) f(y) for all real x, y, f(x) ≠ 0 for any real x and f'(0) = 2. Show that for all real x, f'(x) = 2f(x). Hence find f(x). 10 marks (e) Find the equation of the cone whose vertex is the point (1, 1, 0) and whose guiding curve is y = 0, x² + z² = 4. 10 marks

हिंदी में पढ़ें

(a) क्या समुच्चय {(0, 0, 0, 3), (1, 1, 0, 0), (0, 1, –1, 0)} को सदिश समष्टि ℝ⁴ का एक आधार बनाने के लिए विस्तारित किया जा सकता है? अपने उत्तर की पुष्टि कीजिए। 10 अंक (b) रैखिक रूपांतरण T : ℝ⁴ → ℝ³, जो T(x, y, z, w) = (x – w, y + z, z – w) द्वारा दिया गया है, का परिसर (रेंज), कोटि (रैंक), अश्टि (कर्नेल) और शून्यता ज्ञात कीजिए। 10 अंक (c) लम्बाई 6 मीटर और चौड़ाई 2 मीटर की एक आयताकार धातु की चादर दी गई है। चारों कोनों से चार बराबर वर्गों को हटाया गया है। इस चादर के फलकों को मोड़कर एक खुला आयताकार संदूक बनाना है। संदूक की ऐसी सन्निकट ऊँचाई ज्ञात कीजिए कि संदूक का आयतन अधिकतम हो। 10 अंक (d) दिया गया है कि f(x + y) = f(x) f(y), सभी वास्तविक x, y के लिए, f(x) ≠ 0 किसी भी वास्तविक x के लिए और f'(0) = 2 है। सभी वास्तविक x के लिए दर्शाइए कि f'(x) = 2f(x) है। अतः f(x) ज्ञात कीजिए। 10 अंक (e) उस शंकु का समीकरण ज्ञात कीजिए जिसका शीर्ष बिंदु (1, 1, 0) है तथा जिसका निर्देशक वक्र y = 0, x² + z² = 4 है। 10 अंक

Answer approach & key points

Framework: UPSC Mathematics Paper 1. (a) justify: claim > 3-4 reasons > evidence > conclusion | (b) calculate: given > formula > substitution > result with units > interpretation | (c) calculate: given > formula > substitution > result with units > interpretation | (d) derive: given > assumptions > stepwise derivation > result > check | (e) derive: given > assumptions > stepwise derivation > result > check Full marks: Rigorous step-by-step derivation with all justifications and checks.

  • Check linear independence of the three given vectors
  • State the dimension of the vector space R⁴
  • Apply the basis extension theorem
  • Conclude with a clear yes/no answer
  • Determine the kernel by solving T(x,y,z,w) = 0
  • Calculate the nullity from the kernel dimension
  • Determine the range by analyzing the image vectors
  • Calculate the rank using the Rank-Nullity Theorem
Q2
50M solve Linear transformation, mean value theorem and 3D geometry

(a) Let T : ℝ³ → ℝ² be a linear transformation such that T(1, 1, -1) = (1, 0), T(4, 1, 1) = (0, 1) and T(1, -1, 2) = (1, 1). Find T. 15 marks (b) Using Mean Value Theorem, prove that π/6 + √3/15 < sin⁻¹(3/5) < π/6 + 1/8 15 marks (c) (i) Find the equation of the cylinder whose generators are parallel to the line x/1 = y/2 = z/3 and that passes through the curve x² + y² = 16, z = 0. 10 marks (ii) Find the shortest distance between the straight lines (x-3)/3 = (y-8)/(-1) = (z-3)/1 and (x+3)/(-3) = (y+7)/2 = (z-6)/4. 10 marks

हिंदी में पढ़ें

(a) माना T : ℝ³ → ℝ² एक ऐसा रैखिक रूपांतरण है कि T(1, 1, -1) = (1, 0), T(4, 1, 1) = (0, 1) तथा T(1, -1, 2) = (1, 1) है। T ज्ञात कीजिए। 15 अंक (b) माध्यमान प्रमेय का प्रयोग करते हुए सिद्ध कीजिए कि π/6 + √3/15 < sin⁻¹(3/5) < π/6 + 1/8 15 अंक (c) (i) उस बेलन का समीकरण ज्ञात कीजिए जिसके जनक, रेखा x/1 = y/2 = z/3 के समांतर हैं और जो वक्र x² + y² = 16, z = 0 से होकर गुजरता है। 10 अंक (ii) सरल रेखाओं (x-3)/3 = (y-8)/(-1) = (z-3)/1 और (x+3)/(-3) = (y+7)/2 = (z-6)/4 के बीच की न्यूनतम दूरी ज्ञात कीजिए। 10 अंक

Answer approach & key points

(a) calculate: given > formula > substitution > result with units > interpretation | (b) justify: claim > 3-4 reasons > evidence > conclusion | (c(i)) calculate: given > formula > substitution > result with units > interpretation | (c(ii)) calculate: given > formula > substitution > result with units > interpretation Full marks: Complete, rigorous derivations with all steps justified and verified.

  • Verify input vectors form a basis of R3
  • Express standard basis vectors as linear combinations
  • Apply linearity to find T(e1), T(e2), T(e3)
  • State final formula T(x,y,z) = (ax+by+cz, dx+ey+fz)
  • State Mean Value Theorem explicitly
  • Define f(x) = sin^-1(x) and interval [1/2, 3/5]
  • Calculate f'(c) = 1/sqrt(1-c^2) and bound it
  • Derive both lower and upper bounds from the inequality
Q3
50M solve Linear algebra, analytical geometry, multivariable calculus

(a) Reduce the following matrix to echelon form: A = 2 & -2 & 2 & 1 -3 & 6 & 0 & -1 1 & -7 & 10 & 2 (15 marks) (b) Find the equations of the spheres which pass through the circle x² + y² + z² - 2x + 2y + 4z - 3 = 0, 2x + y + z = 4and touch the plane3x + 4y = 14. (15 marks) (c) (i) Evaluate displaystyle∬limits_R y dx dy, where R is the region bounded by y = x and y = 4x - x². (10 marks) (ii) If u(x,y) = x f(y/x) + g(y/x), where f and g are arbitrary functions, then show that I. x (∂ u)/(∂ x) + y (∂ u)/(∂ y) = x f(y/x), II. x² (∂² u)/(∂ x²) + 2xy (∂² u)/(∂ x ∂ y) + y² (∂² u)/(∂ y²) = 0. (10 marks)

हिंदी में पढ़ें

(a) निम्नलिखित आव्यूह को सोपानक (एशेलोन) रूप में समानीत कीजिए : A = 2 & -2 & 2 & 1 -3 & 6 & 0 & -1 1 & -7 & 10 & 2 (15 अंक) (b) उन गोलों के समीकरण ज्ञात कीजिए जो वृत्त x² + y² + z² - 2x + 2y + 4z - 3 = 0, 2x + y + z = 4से होकर गुजरते हैं और समतल3x + 4y = 14 को स्पर्श करते हैं। (15 अंक) (c) (i) displaystyle∬limits_R y dx dy का मान ज्ञात कीजिए, जहाँ R, y = x तथा y = 4x - x² से परिवृत क्षेत्र है। (10 अंक) (ii) यदि u(x,y) = x f(y/x) + g(y/x) है, जहाँ f और g स्वेच्छ फलन हैं, तो दर्शाइए कि I. x (∂ u)/(∂ x) + y (∂ u)/(∂ y) = x f(y/x) है, II. x² (∂² u)/(∂ x²) + 2xy (∂² u)/(∂ x ∂ y) + y² (∂² u)/(∂ y²) = 0 है। (10 अंक)

Answer approach & key points

(a) calculate: given > formula > substitution > result with units > interpretation | (b) calculate: given > formula > substitution > result with units > interpretation | (c(i)) calculate: given > formula > substitution > result with units > interpretation | (c(ii)) derive: given > assumptions > stepwise derivation > result > check Full marks: Complete working with all steps shown, correct results, and verification

  • Apply elementary row operations (R_i -> R_i + kR_j) systematically
  • Show intermediate matrices after each operation
  • Achieve leading 1s in pivot positions
  • Ensure zeros below each pivot
  • Use family of spheres: S + λL = 0
  • Determine center and radius in terms of λ
  • Apply tangency condition: distance = radius
  • Solve for λ and write final equations
Q4
50M prove Analytical geometry, partial derivatives, linear algebra

(a) Show that there is no tangent plane to the sphere x² + y² + z² - 4x + 2y - 4z + 4 = 0 that can be passed through the straight line (x+6)/2 = y + 3 = z + 1. (15 marks) (b) If f(x, y) = { xy(x²-y²)/(x²+y²), when (x,y) ≠ (0,0) { 0, when (x,y) = (0,0), then find f_xy(0,0) and f_yx(0,0). (15 marks) (c) (i) Find the eigenvalues and the corresponding eigenvectors of the matrix A = [1 2 0] [2 1 -6] [2 -2 3] (12 marks) (ii) Let P_n denote the vector space of all polynomials of degree ≤ n over R. Verify that dim(P_4/P_2) = dim P_4 - dim P_2. (8 marks)

हिंदी में पढ़ें

(a) दर्शाइए कि गोले x² + y² + z² - 4x + 2y - 4z + 4 = 0 का कोई ऐसा स्पर्श समतल नहीं है, जो कि सरल रेखा (x+6)/2 = y + 3 = z + 1 से होकर गुजर सके। (15 अंक) (b) यदि f(x, y) = { xy(x²-y²)/(x²+y²), जब (x,y) ≠ (0,0) { 0, जब (x,y) = (0,0) है, तो f_xy(0,0) और f_yx(0,0) ज्ञात कीजिए। (15 अंक) (c) (i) आव्यूह A = [1 2 0] [2 1 -6] [2 -2 3] के अभिलक्षणिक मान और संगत अभिलक्षणिक सदिश ज्ञात कीजिए। (12 अंक) (ii) माना P_n, R पर घात ≤ n के सभी बहुपदों के सदिश समष्टि को दर्शाता है। सत्यापित कीजिए कि dim(P_4/P_2) = dim P_4 - dim P_2। (8 अंक)

Answer approach & key points

(a) justify: claim > 3-4 reasons > evidence > conclusion | (b) calculate: given > formula > substitution > result with units > interpretation | (c(i)) calculate: given > formula > substitution > result with units > interpretation | (c(ii)) justify: claim > 3-4 reasons > evidence > conclusion Full marks: Rigorous derivations with all steps shown and correct results

  • Identify sphere center and radius from equation
  • Parametrize the given straight line
  • Set up condition for plane passing through line
  • Show distance from center to plane is not equal to radius
  • Apply limit definition of partial derivative
  • Evaluate f_x(0,y) and f_y(x,0) limits
  • Compute f_xy(0,0) and f_yx(0,0) separately
  • Show that f_xy(0,0) ≠ f_yx(0,0)

B

Q5
50M Compulsory solve Differential equations, ellipses, orbital mechanics, catenary, vector calculus

(a) Solve (1-y²+(y⁴)/(x²))(dy/dx)²-2y/xdy/dx+(y²)/(x²)=0. 10 marks (b) Form the differential equation of all ellipses whose axes coincide with coordinate axes. 10 marks (c) Prove that the time taken by the Earth to travel over half of its orbit, which is separated by the minor axis and is remote from the Sun, when the Sun is at the focus of the elliptic orbit, is two days more than half of the year. The eccentricity of the orbit is taken as 1/60. 10 marks (d) Given that A and B are two points in the same horizontal line distant 2a apart. AO and BO are two equal heavy strings tied together at O and carrying their weight at O. If l is length of each string and d is depth of O below AB, then show that the parameter c of this catenary, in which the strings hang, is given by l²-d²=2c²[cosh(a/c)-1]. 10 marks (e) If u=x+y+z, v=x²+y²+z² and w=xy+yz+zx, then show that grad u, grad v and grad w are coplanar. 10 marks

हिंदी में पढ़ें

(a) (1-y²+(y⁴)/(x²))(dy/dx)²-2y/xdy/dx+(y²)/(x²)=0 को हल कीजिए । 10 अंक (b) सभी दीर्घवृत्तों, जिनके अक्ष निर्देशांक अक्षों के संपाती हैं, का अवकल समीकरण बनाइए । 10 अंक (c) सिद्ध कीजिए कि पृथ्वी को अपनी कक्षा के आधे भाग, जो कि लघु अक्ष द्वारा अलग किया गया है और सूर्य से सुदूर है, जब सूर्य दीर्घवृत्तीय कक्षा की नाभि (फोकस) पर है, की यात्रा करने में लगने वाला समय आधे वर्ष से दो दिन अधिक है। कक्षा की उत्केन्द्रता 1/60 ली गई है। 10 अंक (d) दिया गया है कि A और B एक ही क्षैतिज रेखा पर स्थित दो बिंदु हैं, जिनके बीच की दूरी 2a है। AO और BO दो समान भारी डोरी हैं जो O पर एक साथ बंधी हैं और जिनका भार O पर है। यदि प्रत्येक डोरी की लंबाई l है तथा d, AB से नीचे O की गहराई है, तो दर्शाइए कि इस कैटनरी, जिसमें डोरी लटकी है, का प्राचल c l²-d²=2c²[cosh(a/c)-1] द्वारा दिया गया है। 10 अंक (e) यदि u=x+y+z, v=x²+y²+z² और w=xy+yz+zx है, तो दर्शाइए कि grad u, grad v और grad w समतलीय हैं। 10 अंक

Answer approach & key points

(a) calculate: given > formula > substitution > result with units > interpretation | (b) derive: given > assumptions > stepwise derivation > result > check | (c) justify: claim > 3-4 reasons > evidence > conclusion | (d) justify: claim > 3-4 reasons > evidence > conclusion | (e) justify: claim > 3-4 reasons > evidence > conclusion Full marks: Complete, rigorous derivations with all steps justified and verified.

  • Identify equation as homogeneous in x, y
  • Apply substitution y = vx
  • Separate variables and integrate
  • State final general solution
  • State general equation of ellipse
  • Differentiate to eliminate constants
  • Form final differential equation
  • Use Kepler's Second Law (equal areas)
Q6
50M prove Laplace transforms, convolution, integral equations, elastic string, directional derivative, Maxwell's equations

(a) If F(s) and G(s) are Laplace transforms of f(t) and g(t) respectively, then prove that L∫₀^t f(x) g(t-x) dx = F(s) G(s). Using this result, solve the equation y(t) = t + ∫₀^t y(x) sin(t-x) dx. 15 marks (b) One end of an elastic string, having natural length a, is fixed at some point O and a heavy particle is attached to the other end of the string. The string is drawn vertically downward till it is four times its natural length at the point C and then released. If the modulus of elasticity of the string is equal to the weight of the particle, then show that the particle will return to the same point C in the time √(a/g)(2√3 + (4π)/3). 15 marks (c) (i) Find the absolute value of the directional derivative of φ(x, y, z) = x^2y^2z² at the point (1, 1, -1) in the direction of the tangent to the curve x = e^t, y = 2sin t + 1, z = t - cos t, at t = 0. 10 marks (ii) If ∇ · overrightarrowE=0, ∇ · overrightarrowH=0, ∇ × overrightarrowE=-(∂ overrightarrowH)/(∂ t) and ∇ × overrightarrowH=(∂ overrightarrowE)/(∂ t), then show that ∇² overrightarrowH=(∂² overrightarrowH)/(∂ t²) and ∇² overrightarrowE=(∂² overrightarrowE)/(∂ t²). 10 marks

हिंदी में पढ़ें

(a) यदि f(t) और g(t) के लाप्लास रूपान्तर क्रमशः F(s) और G(s) हैं, तो सिद्ध कीजिए कि L∫₀^t f(x) g(t-x) dx = F(s) G(s) है। इस परिणाम का प्रयोग करते हुए, समीकरण y(t) = t + ∫₀^t y(x) sin(t-x) dx को हल कीजिए। 15 अंक (b) एक प्रत्यास्थ डोरी, जिसकी प्राकृतिक लंबाई a है, का एक छोर किसि बिंदु O पर स्थिर है और डोरी के दूसरे छोर पर एक भारी कण जुड़ा हुआ है। डोरी को उर्ध्वाधर नीचे की ओर बिंदु C तक तब तक खींचा जाता है जब तक वह अपनी प्राकृतिक लंबाई से चार गुना न हो जाए तथा फिर छोड़ दिया जाता है। यदि डोरी का प्रत्यास्थता गुणांक कण के भार के बराबर है, तो दर्शाइए कि कण √(a/g)(2√3 + (4π)/3) समय में उसी बिंदु C पर वापस आ जाएगा। 15 अंक (c) (i) φ(x, y, z) = x^2y^2z² का बिंदु (1, 1, -1) पर, वक्र x = e^t, y = 2sin t + 1, z = t - cos t, के बिंदु t = 0 पर स्पर्श-रेखा की दिशा में दिक्-अवकलज का निरपेक्ष मान ज्ञात कीजिए। 10 अंक (ii) यदि ∇ · overrightarrowE=0, ∇ · overrightarrowH=0, ∇ × overrightarrowE=-(∂ overrightarrowH)/(∂ t) और ∇ × overrightarrowH=(∂ overrightarrowE)/(∂ t) है, तो दर्शाइए कि ∇² overrightarrowH=(∂² overrightarrowH)/(∂ t²) और ∇² overrightarrowE=(∂² overrightarrowE)/(∂ t²) है। 10 अंक

Answer approach & key points

(a) derive: given > assumptions > stepwise derivation > result > check | (b) derive: given > assumptions > stepwise derivation > result > check | (c(i)) calculate: given > formula > substitution > result with units > interpretation | (c(ii)) derive: given > assumptions > stepwise derivation > result > check Full marks: Rigorous step-by-step derivation with all theorems named and results verified.

  • Prove L{∫f(x)g(t-x)dx} = F(s)G(s) via double integration
  • Identify f(t)=t and g(t)=sin(t) in the given equation
  • Apply Laplace transform to both sides of the equation
  • Perform partial fraction decomposition of Y(s)
  • Formulate equation of motion for the elastic string
  • Determine the equilibrium position and angular frequency
  • Calculate the time for the first quarter period (C to equilibrium)
  • Calculate the time for the remaining three-quarter period
Q7
50M prove Mechanics, vector calculus and differential equations

(a) A solid sphere rests inside a fixed rough and hemispherical bowl of twice its radius. If a large amount of weight, whatsoever, is attached to the highest point of the sphere, then show that the equilibrium is stable. (15 marks) (b) Verify Green's theorem in the plane for ∮limits_C[(x y+y²) d x+x² d y], where C is the boundary of the region bounded by the curves y=x and y=x². (15 marks) (c) (i) Find the general solution and singular solution of the differential equation (1+(d y)/(d x))³=27/(8 a)(x+y)(1-(d y)/(d x))³. (10 marks) (ii) Find the complete solution of x³ (d³ y)/(d x³)+3 x² (d² y)/(d x²)+x (d y)/(d x)+y=x log x. (10 marks)

हिंदी में पढ़ें

(a) एक ठोस गोला अपनी त्रिज्या से दुगुनी त्रिज्या के स्थिर रूक्ष अर्धगोलीय कटोरे में रखा हुआ है। यदि एक बड़ा भार, कितना भी हो, गोले के सबसे ऊँचे बिंदु पर जुड़ा है, तो दर्शाइए कि संतुलन स्थिर है। (15 अंक) (b) ∮limits_C[(x y+y²) d x+x² d y], जहाँ C, वक्रों y=x और y=x² द्वारा परिबद्ध क्षेत्र की परिसीमा है, के लिए समतल में ग्रीन का प्रमेय सत्यापित कीजिए। (15 अंक) (c) (i) अवकल समीकरण (1+(d y)/(d x))³=27/(8 a)(x+y)(1-(d y)/(d x))³ के व्यापक हल और विचित्र हल ज्ञात कीजिए। (10 अंक) (ii) x³ (d³ y)/(d x³)+3 x² (d² y)/(d x²)+x (d y)/(d x)+y=x log x का पूर्ण हल ज्ञात कीजिए। (10 अंक)

Answer approach & key points

(a) justify: claim > 3-4 reasons > evidence > conclusion | (b) justify: claim > 3-4 reasons > evidence > conclusion | (c(i)) derive: given > assumptions > stepwise derivation > result > check | (c(ii)) derive: given > assumptions > stepwise derivation > result > check Full marks: Complete derivations with all steps, correct results, and verification.

  • Define geometry: bowl radius 2R, sphere radius R
  • Identify center of mass position with added weight
  • Derive potential energy as function of angle
  • Show second derivative of PE is positive
  • Compute line integral over boundary C
  • Compute double integral over region D
  • Show both integrals yield equal values
  • State Green's theorem explicitly
Q8
50M solve Differential equations, vector calculus and particle dynamics

(a) Solve the differential equation (x + 2)(d^2y)/(dx²) - (2x + 5)dy/dx + 2y = (1 + x) e^x by the method of variation of parameters. (15 marks) (b) Verify Gauss's divergence theorem for F⃗ = [(x² - yz)î + (y² - zx)ĵ + (z² - xy)k̂], taken over the rectangular parallelopiped 0 ≤ x ≤ a,0 ≤ y ≤ b,0 ≤ z ≤ c. (15 marks) (c) A particle is projected inside a fixed smooth cylinder with circular cross-section in a vertical plane from the lowest point with initial horizontal velocity u. Show that for (i) (u² ≤ 2ag); the particle oscillates about the mean position in the lower half, (ii) (u² ≥ 5ag); the particle executes complete circular motion, and (iii) (2ag < u² < 5ag); the particle will leave the curve in a tangential direction, making an angle α with the horizontal such that cos α = (u² - 2ag)/3ag. (20 marks)

हिंदी में पढ़ें

(a) अवकल समीकरण (x + 2)(d^2y)/(dx²) - (2x + 5)dy/dx + 2y = (1 + x) e^x को प्राचल विचरण विधि द्वारा हल कीजिए। (15 अंक) (b) समकोणिक समांतरपटलक 0 ≤ x ≤ a,0 ≤ y ≤ b,0 ≤ z ≤ cपरF⃗ = [(x² - yz)î + (y² - zx)ĵ + (z² - xy)k̂] के लिए गॉस अपसरण प्रमेय सत्यापित कीजिए। (15 अंक) (c) एक कण को उच्चाधर तल में वृत्ताकर अनुप्रस्थ-परिच्छेद वाले स्थिर चिकने बेलन के अंदर प्रारंभिक क्षैतिज वेग u के साथ सबसे निचले बिंदु से प्रक्षेपित किया जाता है। दर्शाइए कि (i) (u² ≤ 2ag) के लिए; कण निचले आधे भाग में माध्य स्थिति के आसपास (about) दोलन करता है, (ii) (u² ≥ 5ag) के लिए; कण पूर्णतः वृत्तीय गति करता है, और (iii) (2ag < u² < 5ag) के लिए; कण, वक्र को एक स्पर्श की दिशा में, जो क्षैतिज के साथ कोण α बनाती है, छोड़ देगा, जबकि cos α = (u² - 2ag)/3ag है। (20 अंक)

Answer approach & key points

(a) derive: given > assumptions > stepwise derivation > result > check | (b) derive: given > assumptions > stepwise derivation > result > check | (c) derive: given > assumptions > stepwise derivation > result > check Full marks: Rigorous derivations with all steps shown and verified.

  • Find complementary function y_c = c1e^x + c2e^(2x)
  • Set up Wronskian W = e^(3x)
  • Calculate u1' and u2' integrals correctly
  • Combine y_c and particular integral y_p
  • Calculate volume integral of div F = 2(x+y+z)
  • Evaluate surface integrals over all 6 faces
  • Show volume integral equals sum of surface integrals
  • Correct limits of integration for rectangular parallelepiped

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